AddMath Spmnetic!™⚡️

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Tarmoq:Sejarah spmnetic!™Hindiston12 393 Taʼlim5 658...

📈 Telegram kanali AddMath Spmnetic!™⚡️ analitikasi

AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 33 761 obunachidan iborat bo'lib, Taʼlim toifasida 5 658-o'rinni va Hindiston mintaqasida 12 393-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 33 761 obunachiga ega bo‘ldi.

18 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 555 ga, so‘nggi 24 soatda esa 8 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 13.21% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 4.55% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 4 460 marta ko‘riladi; birinchi sutkada odatda 1 536 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 9 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 19 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

33 761

Obunachilar

+824 soatlar

+607 kunlar

+55530 kunlar

4 460

Post ko'rishlar

~ 1 53624 soatlar

~ 2 01348 soatlar

13.21%

Muloqot nisbati

~ 2

Kuniga postlar

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Postlar arxiv

33 761

Siapa mau lagi 1 soalan kbat yg mmg Susah gila Kalau U tak tahu Cara penyelesaian

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Yg ni 1 mark question 😂😂😂

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It can move 7ups and then 7rights , or 7rights 1st then 7ups, it doesn't matter how many rights/ups

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Imagine there is one rook piece placed in A1(red box) , it should finally reach h8(orange box) the rook can only move up or right, so what's the total different ways to reach h8??

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Guys another tricky question(super easy actually) for Permutations and combinations

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This proves that sometimes, we need to think before you write anything.,

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my approach was a bit different , I use Pythagoras to make quadratic which returned imaginary roots so triangle cannot exist

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Which means, there won't be any area.

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Since it's a right angle triangle, we can draw a circle circumscribing the triangle. This circle will have a radius of 5. But as you can see, the altitude ( or height in simple terms ) is 6, which is larger than the radius. Hence, the triangle is impossible to be constructed.

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The triangle does not exist.

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If you're still confused, check out this video: https://www.youtube.com/watch?v=CmskSlStE6Y&t=8s

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Just guna Thales theorem

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Haha seorang je betul, yg ni Kalau U guna Pythagoras, u akan dapat imaginary roots sbb triangle ni tak boleh exist

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Guys it's not 30

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Find the area

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Repost from Thespmnetic™ 🕵🏻🕵🏻‍♀

Link all subjects under spmnetic! https://spmnetic.carrd.co

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Finally, we multiply both numbers to gather to get the total paths. 15×35 = 525

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Now we focus on this part. You'll love to the right 4 times and 3 times upward. Which gives 7 moves in total. Out of these 7 moves, you'll have to choose 3 moves to be upward and the rest to the right. Hence, the number of path is just 7C3 = 35

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There will be 4 moves to the right and 2 moves upwards. 6 moves total. Out of these six moves, you'll have to choose 2 moves to be moving upwards and the rest will be moving to the right. Hence, the total number of ways is just 6C2 = 15.