现已上线！2025 年 Telegram 研究 — 年度关键洞察 
AddMath Spmnetic!™⚡️
前往频道在 Telegram
This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨
显示更多📈 Telegram 频道 AddMath Spmnetic!™⚡️ 的分析概览
频道 AddMath Spmnetic!™⚡️ (@addmathspmnotes) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 33 761 名订阅者，在 教育 类别中位列第 5 658，并在 印度 地区排名第 12 393 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 33 761 名订阅者。
根据 18 六月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 555，过去 24 小时变化为 8，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 13.21%。内容发布后 24 小时内通常能获得 4.55% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 4 460 次浏览，首日通常累积 1 536 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 9。
- 主题关注点： 内容集中在 addmath, untuk, 629/4, math, eqn 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻
For any enquiries, please directly ask in our discussion group ✨”
凭借高频更新（最新数据采集于 19 六月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
33 761
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+607 天
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帖子存档
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Siapa mau lagi 1 soalan kbat yg mmg Susah gila Kalau U tak tahu Cara penyelesaian
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It can move 7ups and then 7rights , or 7rights 1st then 7ups, it doesn't matter how many rights/ups
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Imagine there is one rook piece placed in A1(red box) , it should finally reach h8(orange box) the rook can only move up or right, so what's the total different ways to reach h8??
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Guys another tricky question(super easy actually) for Permutations and combinations
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my approach was a bit different , I use Pythagoras to make quadratic which returned imaginary roots so triangle cannot exist
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Since it's a right angle triangle, we can draw a circle circumscribing the triangle.
This circle will have a radius of 5.
But as you can see, the altitude ( or height in simple terms ) is 6, which is larger than the radius.
Hence, the triangle is impossible to be constructed.
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If you're still confused, check out this video:
https://www.youtube.com/watch?v=CmskSlStE6Y&t=8s
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Haha seorang je betul, yg ni Kalau U guna Pythagoras, u akan dapat imaginary roots sbb triangle ni tak boleh exist
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Finally, we multiply both numbers to gather to get the total paths.
15×35 = 525
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Now we focus on this part.
You'll love to the right 4 times and 3 times upward.
Which gives 7 moves in total.
Out of these 7 moves, you'll have to choose 3 moves to be upward and the rest to the right.
Hence, the number of path is just 7C3 = 35
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There will be 4 moves to the right and 2 moves upwards.
6 moves total.
Out of these six moves, you'll have to choose 2 moves to be moving upwards and the rest will be moving to the right.
Hence, the total number of ways is just 6C2 = 15.
