AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

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📈 Analytical overview of Telegram channel AddMath Spmnetic!™⚡️

Channel AddMath Spmnetic!™⚡️ (@addmathspmnotes) in the English language segment is an active participant. Currently, the community unites 33 761 subscribers, ranking 5 658 in the Education category and 12 393 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 33 761 subscribers.

According to the latest data from 18 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 555 over the last 30 days and by 8 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 13.21%. Within the first 24 hours after publication, content typically collects 4.55% reactions from the total number of subscribers.
Post reach: On average, each post receives 4 460 views. Within the first day, a publication typically gains 1 536 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 9.
Thematic interests: Content is focused on key topics such as addmath, untuk, 629/4, math, eqn.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Thanks to the high frequency of updates (latest data received on 19 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

33 761

Subscribers

+824 hours

+607 days

+55530 days

4 460

Post views

~ 1 53624 hours

~ 2 01348 hours

13.21%

Engagement rate

~ 2

Posts per day

Ads index

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Posts Archive

33 761

Siapa mau lagi 1 soalan kbat yg mmg Susah gila Kalau U tak tahu Cara penyelesaian

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Yg ni 1 mark question 😂😂😂

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It can move 7ups and then 7rights , or 7rights 1st then 7ups, it doesn't matter how many rights/ups

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Imagine there is one rook piece placed in A1(red box) , it should finally reach h8(orange box) the rook can only move up or right, so what's the total different ways to reach h8??

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Guys another tricky question(super easy actually) for Permutations and combinations

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This proves that sometimes, we need to think before you write anything.,

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my approach was a bit different , I use Pythagoras to make quadratic which returned imaginary roots so triangle cannot exist

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Which means, there won't be any area.

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Since it's a right angle triangle, we can draw a circle circumscribing the triangle. This circle will have a radius of 5. But as you can see, the altitude ( or height in simple terms ) is 6, which is larger than the radius. Hence, the triangle is impossible to be constructed.

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The triangle does not exist.

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If you're still confused, check out this video: https://www.youtube.com/watch?v=CmskSlStE6Y&t=8s

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Just guna Thales theorem

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Haha seorang je betul, yg ni Kalau U guna Pythagoras, u akan dapat imaginary roots sbb triangle ni tak boleh exist

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Guys it's not 30

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Find the area

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Repost from Thespmnetic™ 🕵🏻🕵🏻‍♀

Link all subjects under spmnetic! https://spmnetic.carrd.co

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Finally, we multiply both numbers to gather to get the total paths. 15×35 = 525

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Now we focus on this part. You'll love to the right 4 times and 3 times upward. Which gives 7 moves in total. Out of these 7 moves, you'll have to choose 3 moves to be upward and the rest to the right. Hence, the number of path is just 7C3 = 35

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There will be 4 moves to the right and 2 moves upwards. 6 moves total. Out of these six moves, you'll have to choose 2 moves to be moving upwards and the rest will be moving to the right. Hence, the total number of ways is just 6C2 = 15.