AddMath Spmnetic!™⚡️
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Red:📈 Análisis del canal de Telegram AddMath Spmnetic!™⚡️
El canal AddMath Spmnetic!™⚡️ (@addmathspmnotes) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 37 922 suscriptores, ocupando la posición 4 977 en la categoría Educación y el puesto 10 275 en la región India.
📊 Métricas de audiencia y dinámica
Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 37 922 suscriptores.
Según los últimos datos del 21 octubre, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de 1 076, y en las últimas 24 horas de 25, conservando un alto alcance.
- Estado de verificación: No verificado
- Tasa de interacción (ER): El promedio de interacción de la audiencia es 11.94%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 6.30% de reacciones respecto al total de suscriptores.
- Alcance de las publicaciones: Cada publicación recibe en promedio 4 527 visualizaciones. En el primer día suele acumular 2 390 visualizaciones.
- Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 7.
- Intereses temáticos: El contenido se centra en temas clave como addmath, untuk, 629/4, math, eqn.
📝 Descripción y política de contenido
El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻
For any enquiries, please directly ask in our discussion group ✨”
Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 22 octubre, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Educación.
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Archivo de publicaciones
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KERTAS PERCUBAAN MATEMATIK TAMABHAN 2026
DILENGKAPI DENGAN LANGKAH PENYELESAIAN & PENJELASAN
JOHOR BAHRU
K1: https://addmaths-atlas.pages.dev/trials/johor-bahru/paper-1.html?lang=bm
K2: https://addmaths-atlas.pages.dev/trials/johor-bahru/paper-2.html?lang=bm
JOHOR BATU PAHAT
K1: https://addmaths-atlas.pages.dev/trials/johor-batu-pahat/paper-1.html?lang=bm
K2: https://addmaths-atlas.pages.dev/trials/johor-batu-pahat/paper-2.html?lang=bm
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Repost from Thespmnetic™ 🕵🏻🕵🏻♀
Countdown SPM:
69 days left (9 minggu 6 hari)
Either study hard for a better future or do nothing and ruin your future.
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Since f(x) = ax² + bx + c = 0 for all real numbers x, by letting x = 0, we get f(0) = a(0²) + b(0) + c = 0, which further implies that c = 0.
This directly simplifies f(x) to:
f(x) = ax² + bx = 0.
By letting x = 1, f(1) = a(1²) + b(1) = 0 implies that a + b = 0.
By letting x = -1, f(-1) = a(-1)² + b(-1) = 0 implies that a - b = 0.
Adding the two equations gives 2a = 0, which implies that a = 0.
Substitute a = 0 into either equation yields b = 0.
So it's proven that if f(x) = ax² + bx + c = 0 for all real number x, then a = b = c = 0.
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how to really know ur potential and improve?
1. time yourself 2 hours *PAPER 1) or 2 hours 30 minutes (PAPER 2), stop writting when timer ends.
2. mark using answer scheme, K0 , N0 most of the times, dont simply put N1 just bcz ur answer correct.
3. Know why K0
4. know why and where P1 is given
5. differentiate between the steps that can be skipped and cannot be skipped
6. Know how to recheck ur answer and ur working.
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Suppose we are given f(x) = ax^2 + bx + c. It is easy to see that if a = b = c = 0, then f(x) = 0 for all (real) numbers x.
The challenge is to prove the other direction. Can you prove that if f(x) = 0 for all (real) numbers x, then a = b = c = 0?
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1st step in this chapter is to know how to convert the equation , this exercise would be helpful.
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Repost from SPMADDMATHS(MathsItEasy)
SPM Additional Mathematics Trial / Pass Year question errata 🔍
When doing the following questions , is better to skip 🚫 the questions since it may consisit one or more of the following error ⚠️ This list will be update from time to time ⏰
The error maybe
1-Question can't be solved 🥲
2-Question lack some important info that affect the answer 😶
3-Question consist some minor grammar mistake 😒
4-Question is ambiguous 😵💫
5-Question is not logic 😅
6-Official scheme answer ( either from LPM or JPN or publisher ) is wrong 😵
7-Official scheme answer ( either from LPM or JPN or publisher ) is missing other answer / step 🧐
8-Is out of SPM syllabus 🤭
SPM 2021
P1 Q8(a)
P2 Q14,15(c)(ii)
SPM 2022
P1 Q13(c),15(c)
P2 Q4,7,14(c),15(b)
SPM 2023
P1 Q10(a),12(b),14(c)(ii)
P2 Q7,15(c)(iii)
SPM 2024
P1 9(b),11(b)(ii)
P2 3(b),7,8(b)(ii),10(c)
2021⚠️
Melaka 2021
P1 Q9
MRSM 2021
P2 Q14(b)
SBP 2021
P1 Q6
Selangor 2021 Set1
P1 Q8(b)
P2 Q4(b),11(b)(ii),14
Selangor 2021 Set2
P2 Q4(b),14
2022⚠️
Batu Pahat
P1 Q4,5(c),7(b)(ii),13(b)(c)
P2 Q1(b),7,9(c),12(c),13(a),14(c)
Kedah
P1 Q5(b),9(b),12(c)(ii),13(c),14(a)(b)(ii)(c)
P2 Q1,4(b)(ii),9(a),12(a)(ii),14(d)
Kelantan MPSM
P1 Q6(b)(i)(ii),11(b)
P2 Q5(b)(i)(ii),7(b),9(c)(ii),14
Kelantan YIK
P1 Q2(b),5(b),6,8(a),9(a)
P2 Q11
Melaka
P1 Q7(b)
P2 Q14(c)
MRSM
P2 Q9(b)
Muar
P1 Q2(b),13(b)(ii),15
P2 Q6(b),12(c)(ii)
Pahang
P1 Q6(b),11(b),13(a),15(a)
P2 Q14(c)(ii)
Perak Set 1
P1 Q1,8,13(b)
P2 Q2(b)(ii),13(a)(i)(iii)
Perak Set 2
P1 Q1,9,15(b)
P2 Q3(b),12(c),14(b)(c)
Perlis
P1 Q6(a)(b),11(b),12(b)
P2 Q10(c),15(c)(i)
Putrajaya
P1 Q3(b)
P2 Q9(c)
Selangor Set 1
P1 Q13(b)
Selangor Set 2
P1 Q13(b)
P2 Q10
SMKA SABK
P1 Q5(b),8(a),11(a)(i),13(b)(i)(ii)
P2 Q9(b),14(c)
SBP
P2 Q5,6(a),7(c)
Tangkak
P2 Q3(b),5(b)
Terengganu
P2 Q3(c)
2023⚠️
Batu Pahat
Set 1
P1 Q5,7,12(a)(ii)
P2 Q5(b)
Set 2
P1 Q5,10(a)(i)(ii)
J.Bharu
P1 Q7,10(b)(i)
P2 Q2(c)(i)(ii),4(b),9(a)(i)
Kedah
P1 Q3(b),4(b)(c),10(a)(b)
P2 Q3(a),15
Kelantan
P1 Q2(b),8,12(a)
P2 Q3(b),4(b)
Kluang Set 1
P1 Q1,6(a),8(a)(i),10(a)(ii),11(a)(ii),15(b)
P2 Q15(c)
Kluang Set 2
P1 Q10(b)(i)(ii),11(b)(ii),12(c)
P2 Q2(c),10(a)(b)(c)
Melaka
P1 Q3(a),10(b)
Mersing Set 1
P1 Q1(d),10(a)(ii),15(b)
P2 Q9(a)(ii),15(c)
Mersing Set 2
P1 Q1(d),2(a),5,6(b),10(a)(ii),14
P2 Q1,5(a),8(c),12(b)(i)(ii),15(c)
MRSM
P1 Q4,8(a)(i)(ii)
P2 Q7(b),8(c)
Muar
P1 Q2(a),5,6(a),7,9,11(c),15(b)
P2 Q3(a)(ii),4(a),6(b),15(c)
Negeri Sembilan
P1 Q3(b)
P2 Q15(c)
Pahang
P2 Q14(c)(i)
Pasir Gudang Set 1
P1 Q15(a)
P2 Q2(a),9(b)(i)
Pasir Gudang Set 2
P1 Q3(b),6(b),7,8,9(a),13(a)(d)(i),14(a)(b)
P2 Q4(c),7(b),9(a)(ii),10(b)
Perak Set 1
P1 Q3(a)(ii),11
P2 Q10(b)(ii)
Perlis
P1 Q8(b),11(b)
P2 Q1,2(b),4(b),13(b)(ii),15(c)(i)(ii)
Pontian Set 2
P1 Q6(b),9(b)
P2 Q2(c),4(a),6,7,13,15(b)(c)
Putrajaya
P1 Q2(b),7(a)(b),10(b),11(b),15(a)
P2 Q4(c),5(b),10(a)(ii)
Sabah
P1 Q8(a),14(b)(ii)
P2 Q14(c)
SBP
P1 Q5(a)(i)(ii)(b)(i),8(b),14(b)
P2 Q1,6(b),10,12(c)
Selangor Set 1
P1 Q2(b),5(c),12,13(b)
P2 Q5
Selangor Set 2
P1 Q6,8
SMKA SABK Set 1
P1 Q1
P2 Q4,5(b)
SMKA SABK Set 2
P1 Q3(a)(b),5(b),6(b),11(b)(ii)
P2 Q6(b)
SMKJD
The scheme are blur 😭
Tangkak Set 1
P1 Q2(a),10(a)(i)
Tangkak Set 2
P1 Q11(a)(i)
P2 Q12(a)(ii)
Terengganu
(Version P1 Q10(b) computer screen)
P1 Q10(a)(ii)
Terengganu
(Version P1 Q10(b) table)
P1 Q10(a)(ii)(b)(ii)
To be continued ...
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jadual for the 3rd week, today we will do Addmaths f4c6, linear law, and bio f4c9 Nutrition and human digestive system.
