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AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

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AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 37 917 obunachidan iborat bo'lib, Taʼlim toifasida 4 977-o'rinni va Hindiston mintaqasida 10 275-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 37 917 obunachiga ega bo‘ldi.

21 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 1 076 ga, so‘nggi 24 soatda esa 25 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 11.94% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 6.30% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 4 527 marta ko‘riladi; birinchi sutkada odatda 2 390 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 7 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 22 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

37 917
Obunachilar
+2524 soatlar
+1927 kun
+1 07630 kun
Postlar arxiv
Guys do anyone have mrsm addmx paper with skema?

Countdown SPM: 69 days left (9 minggu 6 hari) Either study hard for a better future or do nothing and ruin your future.

solution by tonyXWX08

Since f(x) = ax² + bx + c = 0 for all real numbers x, by letting x = 0, we get f(0) = a(0²) + b(0) + c = 0, which further implies that c = 0. This directly simplifies f(x) to: f(x) = ax² + bx = 0. By letting x = 1, f(1) = a(1²) + b(1) = 0 implies that a + b = 0. By letting x = -1, f(-1) = a(-1)² + b(-1) = 0 implies that a - b = 0. Adding the two equations gives 2a = 0, which implies that a = 0. Substitute a = 0 into either equation yields b = 0. So it's proven that if f(x) = ax² + bx + c = 0 for all real number x, then a = b = c = 0.

idk when , but maybe one day I will share how to recheck answer

how to really know ur potential and improve? 1. time yourself 2 hours *PAPER 1) or 2 hours 30 minutes (PAPER 2), stop writting when timer ends. 2. mark using answer scheme, K0 , N0 most of the times, dont simply put N1 just bcz ur answer correct. 3. Know why K0 4. know why and where P1 is given 5. differentiate between the steps that can be skipped and cannot be skipped 6. Know how to recheck ur answer and ur working.

Suppose we are given f(x) = ax^2 + bx + c. It is easy to see that if a = b = c = 0, then f(x) = 0 for all (real) numbers x. The challenge is to prove the other direction. Can you prove that if f(x) = 0 for all (real) numbers x, then a = b = c = 0?

2026 kedah paper 1
2026 kedah paper 1

2026 Johor Batu Pahat Paper 2
2026 Johor Batu Pahat Paper 2

2026 melaka paper 2
2026 melaka paper 2

2026 melaka paper 1
2026 melaka paper 1

1st step in this chapter is to know how to convert the equation , this exercise would be helpful.

form 4 chapter 6 question
+1
form 4 chapter 6 question

Let's join the class now everyone 🔥🔥 http://meet.google.com/qzr-gqvt-cpj

SPM Additional Mathematics Trial / Pass Year question errata 🔍 When doing the following questions , is better to skip 🚫 the questions since it may consisit one or more of the following error ⚠️ This list will be update from time to time ⏰ The error maybe 1-Question can't be solved 🥲 2-Question lack some important info that affect the answer 😶 3-Question consist some minor grammar mistake 😒 4-Question is ambiguous 😵‍💫 5-Question is not logic 😅 6-Official scheme answer ( either from LPM or JPN or publisher ) is wrong 😵 7-Official scheme answer ( either from LPM or JPN or publisher ) is missing other answer / step 🧐 8-Is out of SPM syllabus 🤭 SPM 2021 P1 Q8(a) P2 Q14,15(c)(ii) SPM 2022 P1 Q13(c),15(c) P2 Q4,7,14(c),15(b) SPM 2023 P1 Q10(a),12(b),14(c)(ii) P2 Q7,15(c)(iii) SPM 2024 P1 9(b),11(b)(ii) P2 3(b),7,8(b)(ii),10(c) 2021⚠️ Melaka 2021 P1 Q9 MRSM 2021 P2 Q14(b) SBP 2021 P1 Q6 Selangor 2021 Set1 P1 Q8(b) P2 Q4(b),11(b)(ii),14 Selangor 2021 Set2 P2 Q4(b),14 2022⚠️ Batu Pahat P1 Q4,5(c),7(b)(ii),13(b)(c) P2 Q1(b),7,9(c),12(c),13(a),14(c) Kedah P1 Q5(b),9(b),12(c)(ii),13(c),14(a)(b)(ii)(c) P2 Q1,4(b)(ii),9(a),12(a)(ii),14(d) Kelantan MPSM P1 Q6(b)(i)(ii),11(b) P2 Q5(b)(i)(ii),7(b),9(c)(ii),14 Kelantan YIK P1 Q2(b),5(b),6,8(a),9(a) P2 Q11 Melaka P1 Q7(b) P2 Q14(c) MRSM P2 Q9(b) Muar P1 Q2(b),13(b)(ii),15 P2 Q6(b),12(c)(ii) Pahang P1 Q6(b),11(b),13(a),15(a) P2 Q14(c)(ii) Perak Set 1 P1 Q1,8,13(b) P2 Q2(b)(ii),13(a)(i)(iii) Perak Set 2 P1 Q1,9,15(b) P2 Q3(b),12(c),14(b)(c) Perlis P1 Q6(a)(b),11(b),12(b) P2 Q10(c),15(c)(i) Putrajaya P1 Q3(b) P2 Q9(c) Selangor Set 1 P1 Q13(b) Selangor Set 2 P1 Q13(b) P2 Q10 SMKA SABK P1 Q5(b),8(a),11(a)(i),13(b)(i)(ii) P2 Q9(b),14(c) SBP P2 Q5,6(a),7(c) Tangkak P2 Q3(b),5(b) Terengganu P2 Q3(c) 2023⚠️ Batu Pahat Set 1 P1 Q5,7,12(a)(ii) P2 Q5(b) Set 2 P1 Q5,10(a)(i)(ii) J.Bharu P1 Q7,10(b)(i) P2 Q2(c)(i)(ii),4(b),9(a)(i) Kedah P1 Q3(b),4(b)(c),10(a)(b) P2 Q3(a),15 Kelantan P1 Q2(b),8,12(a) P2 Q3(b),4(b) Kluang Set 1 P1 Q1,6(a),8(a)(i),10(a)(ii),11(a)(ii),15(b) P2 Q15(c) Kluang Set 2 P1 Q10(b)(i)(ii),11(b)(ii),12(c) P2 Q2(c),10(a)(b)(c) Melaka P1 Q3(a),10(b) Mersing Set 1 P1 Q1(d),10(a)(ii),15(b) P2 Q9(a)(ii),15(c) Mersing Set 2 P1 Q1(d),2(a),5,6(b),10(a)(ii),14 P2 Q1,5(a),8(c),12(b)(i)(ii),15(c) MRSM P1 Q4,8(a)(i)(ii) P2 Q7(b),8(c) Muar P1 Q2(a),5,6(a),7,9,11(c),15(b) P2 Q3(a)(ii),4(a),6(b),15(c) Negeri Sembilan P1 Q3(b) P2 Q15(c) Pahang P2 Q14(c)(i) Pasir Gudang Set 1 P1 Q15(a) P2 Q2(a),9(b)(i) Pasir Gudang Set 2 P1 Q3(b),6(b),7,8,9(a),13(a)(d)(i),14(a)(b) P2 Q4(c),7(b),9(a)(ii),10(b) Perak Set 1 P1 Q3(a)(ii),11 P2 Q10(b)(ii) Perlis P1 Q8(b),11(b) P2 Q1,2(b),4(b),13(b)(ii),15(c)(i)(ii) Pontian Set 2 P1 Q6(b),9(b) P2 Q2(c),4(a),6,7,13,15(b)(c) Putrajaya P1 Q2(b),7(a)(b),10(b),11(b),15(a) P2 Q4(c),5(b),10(a)(ii) Sabah P1 Q8(a),14(b)(ii) P2 Q14(c) SBP P1 Q5(a)(i)(ii)(b)(i),8(b),14(b) P2 Q1,6(b),10,12(c) Selangor Set 1 P1 Q2(b),5(c),12,13(b) P2 Q5 Selangor Set 2 P1 Q6,8 SMKA SABK Set 1 P1 Q1 P2 Q4,5(b) SMKA SABK Set 2 P1 Q3(a)(b),5(b),6(b),11(b)(ii) P2 Q6(b) SMKJD The scheme are blur 😭 Tangkak Set 1 P1 Q2(a),10(a)(i) Tangkak Set 2 P1 Q11(a)(i) P2 Q12(a)(ii) Terengganu (Version P1 Q10(b) computer screen) P1 Q10(a)(ii) Terengganu (Version P1 Q10(b) table) P1 Q10(a)(ii)(b)(ii) To be continued ...

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jadual for the 3rd week, today we will do Addmaths f4c6, linear law, and bio f4c9 Nutrition and human digestive system.

‼️‼️Attention to SPM 2026 ADDMATHS candidates‼️‼️ I will have a discussion tonight on actual spm 2025 addmath paper(final par
‼️‼️Attention to SPM 2026 ADDMATHS candidates‼️‼️ I will have a discussion tonight on actual spm 2025 addmath paper(final part). Today, we will focus on *Section B and Section C Paper 2*. There will be 5 questions to discuss in total before we complete everything. Hope you can make it for the discussion tonight. I will share some tips on how to score well in your section C paper 2 as well. Here are the details: Time: *8pm-10pm* Question discussed: *Q10, Q12-Q15* meet.google.com/qzr-gqvt-cpj Or dial: (US) +1 347-467-1667 PIN: 623 249 540# See you tonight ❤️