AddMath Spmnetic!™⚡️
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网络:📈 Telegram 频道 AddMath Spmnetic!™⚡️ 的分析概览
频道 AddMath Spmnetic!™⚡️ (@addmathspmnotes) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 37 911 名订阅者，在 教育 类别中位列第 4 984，并在 印度 地区排名第 10 290 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 37 911 名订阅者。
根据 20 十月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 1 079，过去 24 小时变化为 21，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 11.89%。内容发布后 24 小时内通常能获得 6.51% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 4 506 次浏览，首日通常累积 2 468 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 7。
- 主题关注点： 内容集中在 addmath, untuk, 629/4, math, eqn 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻
For any enquiries, please directly ask in our discussion group ✨”
凭借高频更新（最新数据采集于 21 十月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
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Repost from Thespmnetic™ 🕵🏻🕵🏻♀
Countdown SPM:
69 days left (9 minggu 6 hari)
Either study hard for a better future or do nothing and ruin your future.
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Since f(x) = ax² + bx + c = 0 for all real numbers x, by letting x = 0, we get f(0) = a(0²) + b(0) + c = 0, which further implies that c = 0.
This directly simplifies f(x) to:
f(x) = ax² + bx = 0.
By letting x = 1, f(1) = a(1²) + b(1) = 0 implies that a + b = 0.
By letting x = -1, f(-1) = a(-1)² + b(-1) = 0 implies that a - b = 0.
Adding the two equations gives 2a = 0, which implies that a = 0.
Substitute a = 0 into either equation yields b = 0.
So it's proven that if f(x) = ax² + bx + c = 0 for all real number x, then a = b = c = 0.
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how to really know ur potential and improve?
1. time yourself 2 hours *PAPER 1) or 2 hours 30 minutes (PAPER 2), stop writting when timer ends.
2. mark using answer scheme, K0 , N0 most of the times, dont simply put N1 just bcz ur answer correct.
3. Know why K0
4. know why and where P1 is given
5. differentiate between the steps that can be skipped and cannot be skipped
6. Know how to recheck ur answer and ur working.
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Suppose we are given f(x) = ax^2 + bx + c. It is easy to see that if a = b = c = 0, then f(x) = 0 for all (real) numbers x.
The challenge is to prove the other direction. Can you prove that if f(x) = 0 for all (real) numbers x, then a = b = c = 0?
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1st step in this chapter is to know how to convert the equation , this exercise would be helpful.
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Repost from SPMADDMATHS(MathsItEasy)
SPM Additional Mathematics Trial / Pass Year question errata 🔍
When doing the following questions , is better to skip 🚫 the questions since it may consisit one or more of the following error ⚠️ This list will be update from time to time ⏰
The error maybe
1-Question can't be solved 🥲
2-Question lack some important info that affect the answer 😶
3-Question consist some minor grammar mistake 😒
4-Question is ambiguous 😵💫
5-Question is not logic 😅
6-Official scheme answer ( either from LPM or JPN or publisher ) is wrong 😵
7-Official scheme answer ( either from LPM or JPN or publisher ) is missing other answer / step 🧐
8-Is out of SPM syllabus 🤭
SPM 2021
P1 Q8(a)
P2 Q14,15(c)(ii)
SPM 2022
P1 Q13(c),15(c)
P2 Q4,7,14(c),15(b)
SPM 2023
P1 Q10(a),12(b),14(c)(ii)
P2 Q7,15(c)(iii)
SPM 2024
P1 9(b),11(b)(ii)
P2 3(b),7,8(b)(ii),10(c)
2021⚠️
Melaka 2021
P1 Q9
MRSM 2021
P2 Q14(b)
SBP 2021
P1 Q6
Selangor 2021 Set1
P1 Q8(b)
P2 Q4(b),11(b)(ii),14
Selangor 2021 Set2
P2 Q4(b),14
2022⚠️
Batu Pahat
P1 Q4,5(c),7(b)(ii),13(b)(c)
P2 Q1(b),7,9(c),12(c),13(a),14(c)
Kedah
P1 Q5(b),9(b),12(c)(ii),13(c),14(a)(b)(ii)(c)
P2 Q1,4(b)(ii),9(a),12(a)(ii),14(d)
Kelantan MPSM
P1 Q6(b)(i)(ii),11(b)
P2 Q5(b)(i)(ii),7(b),9(c)(ii),14
Kelantan YIK
P1 Q2(b),5(b),6,8(a),9(a)
P2 Q11
Melaka
P1 Q7(b)
P2 Q14(c)
MRSM
P2 Q9(b)
Muar
P1 Q2(b),13(b)(ii),15
P2 Q6(b),12(c)(ii)
Pahang
P1 Q6(b),11(b),13(a),15(a)
P2 Q14(c)(ii)
Perak Set 1
P1 Q1,8,13(b)
P2 Q2(b)(ii),13(a)(i)(iii)
Perak Set 2
P1 Q1,9,15(b)
P2 Q3(b),12(c),14(b)(c)
Perlis
P1 Q6(a)(b),11(b),12(b)
P2 Q10(c),15(c)(i)
Putrajaya
P1 Q3(b)
P2 Q9(c)
Selangor Set 1
P1 Q13(b)
Selangor Set 2
P1 Q13(b)
P2 Q10
SMKA SABK
P1 Q5(b),8(a),11(a)(i),13(b)(i)(ii)
P2 Q9(b),14(c)
SBP
P2 Q5,6(a),7(c)
Tangkak
P2 Q3(b),5(b)
Terengganu
P2 Q3(c)
2023⚠️
Batu Pahat
Set 1
P1 Q5,7,12(a)(ii)
P2 Q5(b)
Set 2
P1 Q5,10(a)(i)(ii)
J.Bharu
P1 Q7,10(b)(i)
P2 Q2(c)(i)(ii),4(b),9(a)(i)
Kedah
P1 Q3(b),4(b)(c),10(a)(b)
P2 Q3(a),15
Kelantan
P1 Q2(b),8,12(a)
P2 Q3(b),4(b)
Kluang Set 1
P1 Q1,6(a),8(a)(i),10(a)(ii),11(a)(ii),15(b)
P2 Q15(c)
Kluang Set 2
P1 Q10(b)(i)(ii),11(b)(ii),12(c)
P2 Q2(c),10(a)(b)(c)
Melaka
P1 Q3(a),10(b)
Mersing Set 1
P1 Q1(d),10(a)(ii),15(b)
P2 Q9(a)(ii),15(c)
Mersing Set 2
P1 Q1(d),2(a),5,6(b),10(a)(ii),14
P2 Q1,5(a),8(c),12(b)(i)(ii),15(c)
MRSM
P1 Q4,8(a)(i)(ii)
P2 Q7(b),8(c)
Muar
P1 Q2(a),5,6(a),7,9,11(c),15(b)
P2 Q3(a)(ii),4(a),6(b),15(c)
Negeri Sembilan
P1 Q3(b)
P2 Q15(c)
Pahang
P2 Q14(c)(i)
Pasir Gudang Set 1
P1 Q15(a)
P2 Q2(a),9(b)(i)
Pasir Gudang Set 2
P1 Q3(b),6(b),7,8,9(a),13(a)(d)(i),14(a)(b)
P2 Q4(c),7(b),9(a)(ii),10(b)
Perak Set 1
P1 Q3(a)(ii),11
P2 Q10(b)(ii)
Perlis
P1 Q8(b),11(b)
P2 Q1,2(b),4(b),13(b)(ii),15(c)(i)(ii)
Pontian Set 2
P1 Q6(b),9(b)
P2 Q2(c),4(a),6,7,13,15(b)(c)
Putrajaya
P1 Q2(b),7(a)(b),10(b),11(b),15(a)
P2 Q4(c),5(b),10(a)(ii)
Sabah
P1 Q8(a),14(b)(ii)
P2 Q14(c)
SBP
P1 Q5(a)(i)(ii)(b)(i),8(b),14(b)
P2 Q1,6(b),10,12(c)
Selangor Set 1
P1 Q2(b),5(c),12,13(b)
P2 Q5
Selangor Set 2
P1 Q6,8
SMKA SABK Set 1
P1 Q1
P2 Q4,5(b)
SMKA SABK Set 2
P1 Q3(a)(b),5(b),6(b),11(b)(ii)
P2 Q6(b)
SMKJD
The scheme are blur 😭
Tangkak Set 1
P1 Q2(a),10(a)(i)
Tangkak Set 2
P1 Q11(a)(i)
P2 Q12(a)(ii)
Terengganu
(Version P1 Q10(b) computer screen)
P1 Q10(a)(ii)
Terengganu
(Version P1 Q10(b) table)
P1 Q10(a)(ii)(b)(ii)
To be continued ...
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jadual for the 3rd week, today we will do Addmaths f4c6, linear law, and bio f4c9 Nutrition and human digestive system.
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‼️‼️Attention to SPM 2026 ADDMATHS candidates‼️‼️
I will have a discussion tonight on actual spm 2025 addmath paper(final part). Today, we will focus on *Section B and Section C Paper 2*. There will be 5 questions to discuss in total before we complete everything. Hope you can make it for the discussion tonight. I will share some tips on how to score well in your section C paper 2 as well. Here are the details:
Time: *8pm-10pm*
Question discussed: *Q10, Q12-Q15*
meet.google.com/qzr-gqvt-cpj
Or dial: (US) +1 347-467-1667
PIN: 623 249 540#
See you tonight ❤️
