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Hindiston31 969 Taʼlim15 351...

📈 Telegram kanali MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer analitikasi

MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 13 231 obunachidan iborat bo'lib, Taʼlim toifasida 15 351-o'rinni va Hindiston mintaqasida 31 969-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 13 231 obunachiga ega bo‘ldi.

20 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -141 ga, so‘nggi 24 soatda esa -9 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 2.80% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.96% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 370 marta ko‘riladi; birinchi sutkada odatda 127 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 21 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

13 231

Obunachilar

-924 soatlar

-437 kunlar

-14130 kunlar

370

Post ko'rishlar

~ 12724 soatlar

~ 16448 soatlar

2.80%

Muloqot nisbati

~ 3

Kuniga postlar

Ads index

beta

Postlar arxiv

13 231

import sys from collections import deque input = sys.stdin.readline def solve(N: int, F: int, MAX: int, s: list) -> int: limit = min(N, F + 1) dp = [-10**30] * limit dp[0] = s[0] dq = deque([0]) ans = dp[0] for i in range(1, limit): while dq and dq[0] < i - MAX: dq.popleft() dp[i] = s[i] + dp[dq[0]] ans = max(ans, dp[i]) while dq and dp[dq[-1]] <= dp[i]: dq.pop() dq.append(i) return ans if name == "main": data = list(map(int, sys.stdin.read().split())) idx = 0 N = data[idx]; idx += 1 F = data[idx]; idx += 1 MAX = data[idx]; idx += 1 s = data[idx:idx + N] print(solve(N, F, MAX, s))

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https://t.me/coding_are Share this group with your friends and college group.. I will upload next answer in 5min

13 231

Check function name then write

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import sys sys.setrecursionlimit(2000) input = sys.stdin.read def solve(N: int, S: str, w: list) -> int: if N == 0: return 0 dp = [[0] * N for _ in range(N)] for i in range(N): dp[i][i] = w[i] for length in range(2, N + 1): for i in range(N - length + 1): j = i + length - 1 if S[i] == S[j]: if length == 2: dp[i][j] = w[i] + w[j] else: dp[i][j] = dp[i+1][j-1] + w[i] + w[j] else: dp[i][j] = max(dp[i+1][j], dp[i][j-1]) return dp[0][N-1] if name == "main": data = input().split() if data: N = int(data[0]) S = data[1] w = list(map(int, data[2:])) result = solve(N, S, w) print(result)

13 231

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13 231

Lowercase import sys sys.setrecursionlimit(2000) input = sys.stdin.read def solve(N: int, S: str, w: list) -> int: if N == 0: return 0 dp = [[0] * N for _ in range(N)] for i in range(N): dp[i][i] = w[i] for length in range(2, N + 1): for i in range(N - length + 1): j = i + length - 1 if S[i] == S[j]: if length == 2: dp[i][j] = w[i] + w[j] else: dp[i][j] = dp[i+1][j-1] + w[i] + w[j] else: dp[i][j] = max(dp[i+1][j], dp[i][j-1]) return dp[0][N-1] if name == "main": data = input().split() if data: N = int(data[0]) S = data[1] w = list(map(int, data[2:])) result = solve(N, S, w) print(result)

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13.3k after i will post ✅ All tests passed code will Upload again

13 231

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13 231

import sys input = sys.stdin.readline def solve(n: int, l: int, a: list) -> int: if len(a) < n: a += list(map(int, sys.stdin.read().split())) cur = 1 ans = 1 for i in range(1, n): if abs(a[i] - a[i - 1]) <= l: cur += 1 else: cur = 1 ans = max(ans, cur) return ans Write with function

13 231

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import sys input = sys.stdin.readline def solve(S: str) -> int: def cost(ch): pos = [i for i, c in enumerate(S) if c == ch] k = len(pos) if k <= 1: return 0 q = [pos[i] - i for i in range(k)] m = q[k // 2] return sum(abs(x - m) for x in q) return min(cost('0'), cost('1')) Full passed ✅

13 231

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13 231

#include <bits/stdc++.h> using namespace std; int solve(int N, int K, vector<int>& A) { sort(A.begin(), A.end()); int i = 0; int c = 0; while (i < N - 1) { if (abs(A[i] - A[i + 1]) <= K) { c++; i += 2; } else { i += 1; } } return c; } int main() { int N, K; cin >> N >> K; vector<int> A(N); for (int i = 0; i < N; i++) { cin >> A[i]; } cout << solve(N, K, A) << endl; return 0; } Full passed ✅ Check function name the. Write 👍

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import sys input = sys.stdin.readline def solve(n: int, a: list, b: list) -> int: a.sort() b.sort() i = j = 0 wins = 0 while i < n and j < n: if a[i] > b[j]: wins += 1 i += 1 j += 1 else: i += 1 return wins n = int(input()) a = [int(input()) for _ in range(n)] b = [int(input()) for _ in range(n)] print(solve(n, a, b)) https://t.me/coding_are Share with you frd

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