ACCENTURE EXAM SOLUTIONS

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

Ko'proq ko'rsatish

Hindiston28 010 Taʼlim14 044...

📈 Telegram kanali ACCENTURE EXAM SOLUTIONS analitikasi

ACCENTURE EXAM SOLUTIONS (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 14 141 obunachidan iborat bo'lib, Taʼlim toifasida 14 044-o'rinni va Hindiston mintaqasida 28 010-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 14 141 obunachiga ega bo‘ldi.

21 Sentabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -136 ga, so‘nggi 24 soatda esa 1 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 4.15% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.53% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 586 marta ko‘riladi; birinchi sutkada odatda 216 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 22 Sentabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

14 141

Obunachilar

+124 soatlar

-367 kun

-13630 kun

586

Post ko'rishlar

~ 21624 soatlar

~ 29048 soatlar

4.15%

Muloqot nisbati

~ 3

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Hello everyone I will share all code there... I will share code then change' some variable because of plagiarism Each and every question I will send here answer Now your turn share my channel with your friends and college group https://t.me/coding_are

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#include <iostream> #include <string> using namespace std; pair<int, long long> solve(long long N, long long S) { if (S == 0) { if (N >= 0) return {1, 0}; else return {0, -1}; } long long q = S / 9; long long r = S % 9; string num; if (r == 0) num = "9"; else num = char('0' + r); num += string(q, '0'); long long x = stoll(num); if (x <= N) return {1, x}; return {0, -1}; } int main() { long long N, S; cin >> N >> S; pair<int, long long> result = solve(N, S); cout << result.first << endl; cout << result.second << endl; return 0; }

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import sys input = sys.stdin.readline def digit_sum(n: int) -> int: return sum(int(c) for c in str(n)) def solve(N: int, S: int) -> list: if S == 0: m = 0 else: num_digits = (S + 8) // 9 # ceil(S/9) first = S - 9 * (num_digits - 1) m = int(str(first) + '9' * (num_digits - 1)) if m <= N: return [1, m] else: return [0, -1] if name == "main": try: N = int(input()) S = int(input()) result = solve(N, S) print(" ".join(map(str, result))) except (EOFError, ValueError): pass

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