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INFOSYS EXAM SOLUTIONS

INFOSYS EXAM SOLUTIONS

الذهاب إلى القناة على Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

إظهار المزيد

📈 نظرة تحليلية على قناة تيليجرام INFOSYS EXAM SOLUTIONS

تُعد قناة INFOSYS EXAM SOLUTIONS (@coding_are) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 13 544 مشتركاً، محتلاً المرتبة 14 897 في فئة التعليم والمرتبة 30 554 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 13 544 مشتركاً.

بحسب آخر البيانات بتاريخ 29 يوليو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار 301، وفي آخر 24 ساعة بمقدار 36، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 6.07‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 2.28‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 820 مشاهدة. وخلال اليوم الأول يجمع عادةً 308 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 3.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل placement, gaurntee, suree, capgemini, infosy.

📝 الوصف وسياسة المحتوى

يصف المؤلف القناة بأنها مساحة للتعبير عن الآراء الذاتية:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 30 يوليو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التعليم.

13 544
المشتركون
+3624 ساعات
+1957 أيام
+30130 أيام
أرشيف المشاركات
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const int MOD=1e9+7; int solve(int n, int k, int t) { vector<vector<int>> ways(k + 1, vector<int>(t + 1, 0)), temp; for (int face = 1; face <= k; face++) { if (face <= t) { ways[face][face] = 1; } } for (int step = 2; step <= n; step++) { temp.assign(k + 1, vector<int>(t + 1, 0)); for (int prev = 1; prev <= k; prev++) { for (int total = 1; total <= t; total++) { if (ways[prev][total] == 0) { continue; } if (prev - 1 >= 1 && total + prev - 1 <= t) { temp[prev - 1][total + prev - 1] = (temp[prev - 1][total + prev - 1] + ways[prev][total]) % MOD; } if (prev + 1 <= k && total + prev + 1 <= t) { temp[prev + 1][total + prev + 1] = (temp[prev + 1][total + prev + 1] + ways[prev][total]) % MOD; } } } ways = temp; } long long result = 0; for (int value = 1; value <= k; value++) { result = (result + ways[value][t]) % MOD; } return result; }. https://whatsapp.com/channel/0029VaicY2a65yD2YNehWP2j (Dice and roll Target)