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INFOSYS EXAM SOLUTIONS

INFOSYS EXAM SOLUTIONS

رفتن به کانال در Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 تحلیل کانال تلگرام INFOSYS EXAM SOLUTIONS

کانال INFOSYS EXAM SOLUTIONS (@coding_are) در بخش زبانی انگلیسی بازیگری فعال است. در حال حاضر جامعه شامل 13 544 مشترک است و جایگاه 14 897 را در دسته آموزش و رتبه 30 554 را در منطقه الهند دارد.

📊 شاخص‌های مخاطب و پویایی

از زمان ایجاد در невідомо، پروژه رشد سریعی داشته و 13 544 مشترک جذب کرده است.

بر اساس آخرین داده‌ها در تاریخ 29 ژوئیه, 2026، کانال فعالیت پایداری دارد. در ۳۰ روز گذشته تغییر اعضا برابر 301 و در ۲۴ ساعت گذشته برابر 36 بوده و همچنان دسترسی گسترده‌ای حفظ شده است.

  • وضعیت تأیید: تأیید نشده
  • نرخ تعامل (ER): میانگین تعامل مخاطب 6.07% است و در ۲۴ ساعت نخست پس از انتشار، محتوا معمولاً 2.28% واکنش نسبت به کل مشترکان کسب می‌کند.
  • دسترسی پست‌ها: هر پست به طور میانگین 820 بازدید دریافت می‌کند. در اولین روز معمولاً 308 بازدید جمع‌آوری می‌شود.
  • واکنش‌ها و تعامل: مخاطبان به‌طور فعال حمایت می‌کنند؛ میانگین واکنش به هر پست 3 است.
  • علایق موضوعی: محتوا بر موضوعات کلیدی مانند placement, gaurntee, suree, capgemini, infosy تمرکز دارد.

📝 توضیح و سیاست محتوایی

نویسنده این فضا را محل بیان دیدگاه‌های شخصی توصیف می‌کند:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

به لطف به‌روزرسانی‌های پرتکرار (آخرین داده در تاریخ 30 ژوئیه, 2026)، کانال همواره به‌روز و دارای دسترسی بالاست. تحلیل‌ها نشان می‌دهد مخاطبان به‌طور فعال با محتوا تعامل دارند و آن را به نقطه اثرگذاری مهم در دسته آموزش تبدیل کرده‌اند.

13 544
مشترکین
+3624 ساعت
+1957 روز
+30130 روز
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const int MOD=1e9+7; int solve(int n, int k, int t) { vector<vector<int>> ways(k + 1, vector<int>(t + 1, 0)), temp; for (int face = 1; face <= k; face++) { if (face <= t) { ways[face][face] = 1; } } for (int step = 2; step <= n; step++) { temp.assign(k + 1, vector<int>(t + 1, 0)); for (int prev = 1; prev <= k; prev++) { for (int total = 1; total <= t; total++) { if (ways[prev][total] == 0) { continue; } if (prev - 1 >= 1 && total + prev - 1 <= t) { temp[prev - 1][total + prev - 1] = (temp[prev - 1][total + prev - 1] + ways[prev][total]) % MOD; } if (prev + 1 <= k && total + prev + 1 <= t) { temp[prev + 1][total + prev + 1] = (temp[prev + 1][total + prev + 1] + ways[prev][total]) % MOD; } } } ways = temp; } long long result = 0; for (int value = 1; value <= k; value++) { result = (result + ways[value][t]) % MOD; } return result; }. https://whatsapp.com/channel/0029VaicY2a65yD2YNehWP2j (Dice and roll Target)