KPIT EXAM SOLUTIONS

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

Ko'proq ko'rsatish

Hindiston28 046 Taʼlim14 030...

📈 Telegram kanali KPIT EXAM SOLUTIONS analitikasi

KPIT EXAM SOLUTIONS (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 14 156 obunachidan iborat bo'lib, Taʼlim toifasida 14 030-o'rinni va Hindiston mintaqasida 28 046-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 14 156 obunachiga ega bo‘ldi.

16 Sentabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -119 ga, so‘nggi 24 soatda esa 2 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 4.52% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.56% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 641 marta ko‘riladi; birinchi sutkada odatda 221 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 18 Sentabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

14 161

Obunachilar

+224 soatlar

-47 kun

-11930 kun

641

Post ko'rishlar

~ 22124 soatlar

~ 31248 soatlar

4.52%

Muloqot nisbati

~ 3

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14 156

10am Infosys exam successfully completed by remote access 👍👍👍👍👍 3/3 code done with all tests cases passed ✅ ✅ ✅ Contact for placement exam @srksvk

14 156

10am Infosys exam successfully completed by remote access 👍👍👍👍👍 3/3 code done with all tests cases passed ✅ Contact for placement exam

14 156

https://t.me/coding_are

14 156

10am Infosys exam successfully completed by remote access 👍👍 3/3 code done with all tests cases passed ✅✅✅ Contact for placement exam @srksvk Slot 4

14 156

10am Infosys exam successfully completed by remote access 👍👍 3/3 code done with all tests cases passed ✅✅✅ Contact for placement exam @srksvk Slot 3

14 156

10am Infosys exam successfully completed by remote access 👍👍 3/3 code done with all tests cases passed ✅✅✅ Contact for placement exam @srksvk Slot 2

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10am Infosys exam successfully completed by remote access 👍👍 3/3 code done with all tests cases passed ✅✅✅ Contact for placement exam @srksvk

14 156

def solve(N: int, X: int, Y: int, Z: int) -> int: if N == 1: return 0 dp0 = [0] * (N + 1) dp1 = [0] * (N + 1) for n in range(2, N + 1): sub_cost = X + dp0[n - 1] dp1[n] = sub_cost dp0[n] = sub_cost if n % 2 == 0: cand = Y + dp1[n // 2] if cand < dp0[n]: dp0[n] = cand if n % 3 == 0: cand = Z + dp1[n // 3] if cand < dp0[n]: dp0[n] = cand return dp0[N]

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https://whatsapp.com/channel/0029VaicY2a65yD2YNehWP2j Another answer shared chekc fast

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Answer share here join and and check Full passed ✅ https://whatsapp.com/channel/0029VaicY2a65yD2YNehWP2j .

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Next answer loaded 👇👇👇 https://t.me/coding_are https://t.me/coding_are

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Custom Fence Panels import sys from math import gcd input = sys.stdin.readline def inverse(x, mod): a, b = x, mod p, q = 1, 0 while b: div = a // b a, b = b, a % b p, q = q, p - div * q return p % mod def solve(N: int, a: int, b: int, p: int, q: int, F: int) -> int: g = gcd(a, b) if N % g != 0: return F a //= g b //= g N //= g if b == 1: x = 0 else: x = (N * inverse(a, b)) % b y = (N - a * x) // b if y < 0: return F if b * p < a * q: k = y // a x += k * b y -= k * a cost = x * p + y * q return min(cost, F) https://t.me/coding_are

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import sys input = sys.stdin.readline def solve(N: int) -> int: MOD = 10**9 + 7 a, b, c = 1, 1, 1 # N=1: "A", "B", "C" for _ in range(2, N + 1): na = (b + c) % MOD nb = (a + b) % MOD nc = (a + b + c) % MOD a, b, c = na, nb, nc return (a + b + c) % MOD if name == "main": try: N = int(input()) result = solve(N) print(result) except (EOFError, ValueError): pass

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