现已上线！2025 年 Telegram 研究 — 年度关键洞察 
Tcs exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer
前往频道在 Telegram
🔥Guys plz Stop fearing for daily exams 📝 👨💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk
显示更多📈 Telegram 频道 Tcs exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer 的分析概览
频道 Tcs exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 13 276 名订阅者，在 教育 类别中位列第 15 335，并在 印度 地区排名第 32 351 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 13 276 名订阅者。
根据 12 六月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 111，过去 24 小时变化为 -9，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 2.86%。内容发布后 24 小时内通常能获得 1.13% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 380 次浏览，首日通常累积 150 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 1。
- 主题关注点： 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“🔥Guys plz Stop fearing for daily exams 📝
👨💻 @srksvk is here to help you all at lowest cost possible.💪
🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company
🔥Effort from our side = 💯
📱Main Channel: @coding_are
📱Tel I'd : @srks...”
凭借高频更新（最新数据采集于 13 六月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
13 276
订阅者
-924 小时
-397 天
+11130 天
帖子存档
Lowercase
import sys
sys.setrecursionlimit(2000)
input = sys.stdin.read
def solve(N: int, S: str, w: list) -> int:
if N == 0:
return 0
dp = [[0] * N for _ in range(N)]
for i in range(N):
dp[i][i] = w[i]
for length in range(2, N + 1):
for i in range(N - length + 1):
j = i + length - 1
if S[i] == S[j]:
if length == 2:
dp[i][j] = w[i] + w[j]
else:
dp[i][j] = dp[i+1][j-1] + w[i] + w[j]
else:
dp[i][j] = max(dp[i+1][j], dp[i][j-1])
return dp[0][N-1]
if name == "main":
data = input().split()
if data:
N = int(data[0])
S = data[1]
w = list(map(int, data[2:]))
result = solve(N, S, w)
print(result)
13.3k after i will post ✅
All tests passed code will Upload again
https://t.me/coding_are
Share this group with your friends and college group..
I will upload next answer in 5min
import sys
input = sys.stdin.readline
def solve(n: int, l: int, a: list) -> int:
if len(a) < n:
a += list(map(int, sys.stdin.read().split()))
cur = 1
ans = 1
for i in range(1, n):
if abs(a[i] - a[i - 1]) <= l:
cur += 1
else:
cur = 1
ans = max(ans, cur)
return ans
Write with function
Next answer in 5min
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https://t.me/coding_are
Share this group with your friends and college group..
I will upload next answer in 5min
import sys
input = sys.stdin.readline
def solve(S: str) -> int:
def cost(ch):
pos = [i for i, c in enumerate(S) if c == ch]
k = len(pos)
if k <= 1:
return 0
q = [pos[i] - i for i in range(k)]
m = q[k // 2]
return sum(abs(x - m) for x in q)
return min(cost('0'), cost('1'))
Full passed ✅
https://t.me/coding_are
Share this group with your friends and college group..
I will upload next answer in 5min
#include <bits/stdc++.h>
using namespace std;
int solve(int N, int K, vector<int>& A) {
sort(A.begin(), A.end());
int i = 0;
int c = 0;
while (i < N - 1) {
if (abs(A[i] - A[i + 1]) <= K) {
c++;
i += 2;
} else {
i += 1;
}
}
return c;
}
int main() {
int N, K;
cin >> N >> K;
vector<int> A(N);
for (int i = 0; i < N; i++) {
cin >> A[i];
}
cout << solve(N, K, A) << endl;
return 0;
}
Full passed ✅
Check function name the. Write 👍
Ready for next code
♥️
import sys
input = sys.stdin.readline
def solve(n: int, a: list, b: list) -> int:
a.sort()
b.sort()
i = j = 0
wins = 0
while i < n and j < n:
if a[i] > b[j]:
wins += 1
i += 1
j += 1
else:
i += 1
return wins
n = int(input())
a = [int(input()) for _ in range(n)]
b = [int(input()) for _ in range(n)]
print(solve(n, a, b))
https://t.me/coding_are
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Contact @srksvk
200% suree clearance gaurntee ✅
Remote access also available
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2/2 code done with all tests cases passed ✅
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