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Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

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πŸ”₯Guys plz Stop fearing for daily exams πŸ“ πŸ‘¨β€πŸ’» @srksvk is here to help you all at lowest cost possible.πŸ’ͺ πŸŒ€ ” Our Only Aim Is To Let Get Placed To You In A Reputed Company πŸ”₯Effort from our side = πŸ’― πŸ“±Main Channel: @coding_are πŸ“±Tel I'd : @srksvk

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πŸ“ˆ Analytical overview of Telegram channel Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Channel Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) in the English language segment is an active participant. Currently, the community unites 13 224 subscribers, ranking 15 290 in the Education category and 31 740 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 13 224 subscribers.

According to the latest data from 24 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -147 over the last 30 days and by 5 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 2.63%. Within the first 24 hours after publication, content typically collects 0.55% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 348 views. Within the first day, a publication typically gains 73 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 1.
  • Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œπŸ”₯Guys plz Stop fearing for daily exams πŸ“ πŸ‘¨β€πŸ’» @srksvk is here to help you all at lowest cost possible.πŸ’ͺ πŸŒ€ ” Our Only Aim Is To Let Get Placed To You In A Reputed Company πŸ”₯Effort from our side = πŸ’― πŸ“±Main Channel: @coding_are πŸ“±Tel I'd : @srks...”

Thanks to the high frequency of updates (latest data received on 25 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

13 224
Subscribers
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Posts Archive
import java.util.*;

class Main {

public static int solve(int n,int k,int[] v,int[] w){

long sumA=0,sumB=0;
ArrayList<Integer> list=new ArrayList<>();

for(int i=0;i<n;i++){
if(v[i]==1)sumA+=w[i];
else sumB+=w[i];
list.add(w[i]);
}

if(sumA>sumB)return 0;

Collections.sort(list,Collections.reverseOrder());

int ops=0;

for(int x:list){
if(ops==k)break;
sumA+=x;
sumB-=x;
ops++;
if(sumA>sumB)return ops;
}

return -1;
}

public static void main(String[] args){
Scanner sc=new Scanner(System.in);

int n=sc.nextInt();
int k=sc.nextInt();

int[] v=new int[n];
for(int i=0;i<n;i++)v[i]=sc.nextInt();

int[] w=new int[n];
for(int i=0;i<n;i++)w[i]=sc.nextInt();

System.out.println(solve(n,k,v,w));
}
}

long long solve(int n,int low,int high,vector<int>& arr){ long long res=0,cur=0,MOD=1000000007; for(int i=0;i<n;i++){ if(arr[i]>=low && arr[i]<=high){ cur++; }else{ res=(res + (cur*(cur+1))/2)%MOD; cur=0; } } res=(res + (cur*(cur+1))/2)%MOD; return res; }

import sys NEG_INF = -10**18 def solve(N: int, B: int, a: list) -> int: pos = NEG_INF neg = NEG_INF for x in a: if x > 0: pos = max(pos, x, neg + x + B) else: neg = max(neg, x, pos + x + B) return max(0, pos, neg) if name == "main": data = list(map(int, sys.stdin.read().split())) N = data[0] B = data[1] a = data[2:2+N] print(solve(N, B, a))

https://t.me/coding_are Share this group with your friends and college group.. I will upload next answer in 5min

All passed βœ… import sys from collections import Counter def solve(N: int, C: int, A: list, W: list) -> int: mp = {} comp = [] for x in A: if x not in mp: mp[x] = len(mp) comp.append(mp[x]) A = comp freq = Counter(A) ans = max(W) B = 700 max_light = 1 for f in freq.values(): if f <= B and f > max_light: max_light = f max_len = min(N, 2 * max_light - 1) cnt = [0] * (len(mp) + 1) for l in range(N): total = 0 mx = 0 touched = [] end = min(N, l + max_len) for r in range(l, end): x = A[r] total += W[r] if cnt[x] == 0: touched.append(x) cnt[x] += 1 if cnt[x] > mx: mx = cnt[x] if mx * 2 > r - l + 1 and total > ans: ans = total for x in touched: cnt[x] = 0 heavy = [x for x, f in freq.items() if f > B] size = 2 * N + 5 off = N + 2 INF = 10**30 for cat in heavy: bit = [INF] * (size + 2) def update(i, val): while i <= size: if val < bit[i]: bit[i] = val i += i & -i def query(i): res = INF while i > 0: if bit[i] < res: res = bit[i] i -= i & -i return res bal = 0 pref = 0 update(off, 0) for i in range(N): pref += W[i] if A[i] == cat: bal += 1 else: bal -= 1 best = query(bal + off - 1) if best != INF: val = pref - best if val > ans: ans = val update(bal + off, pref) return ans if name == "main": data = list(map(int, sys.stdin.read().split())) idx = 0 N = data[idx]; idx += 1 C = data[idx]; idx += 1 A = data[idx:idx + N]; idx += N W = data[idx:idx + N] print(solve(N, C, A, W)) All passed βœ…

import sys from collections import deque input = sys.stdin.readline def solve(N: int, F: int, MAX: int, s: list) -> int: limit = min(N, F + 1) dp = [-10**30] * limit dp[0] = s[0] dq = deque([0]) ans = dp[0] for i in range(1, limit): while dq and dq[0] < i - MAX: dq.popleft() dp[i] = s[i] + dp[dq[0]] ans = max(ans, dp[i]) while dq and dp[dq[-1]] <= dp[i]: dq.pop() dq.append(i) return ans if name == "main": data = list(map(int, sys.stdin.read().split())) idx = 0 N = data[idx]; idx += 1 F = data[idx]; idx += 1 MAX = data[idx]; idx += 1 s = data[idx:idx + N] print(solve(N, F, MAX, s))

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https://t.me/coding_are Share this group with your friends and college group.. I will upload next answer in 5min

import sys sys.setrecursionlimit(2000) input = sys.stdin.read def solve(N: int, S: str, w: list) -> int: if N == 0: return 0 dp = [[0] * N for _ in range(N)] for i in range(N): dp[i][i] = w[i] for length in range(2, N + 1): for i in range(N - length + 1): j = i + length - 1 if S[i] == S[j]: if length == 2: dp[i][j] = w[i] + w[j] else: dp[i][j] = dp[i+1][j-1] + w[i] + w[j] else: dp[i][j] = max(dp[i+1][j], dp[i][j-1]) return dp[0][N-1] if name == "main": data = input().split() if data: N = int(data[0]) S = data[1] w = list(map(int, data[2:])) result = solve(N, S, w) print(result)

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Lowercase import sys sys.setrecursionlimit(2000) input = sys.stdin.read def solve(N: int, S: str, w: list) -> int: if N == 0: return 0 dp = [[0] * N for _ in range(N)] for i in range(N): dp[i][i] = w[i] for length in range(2, N + 1): for i in range(N - length + 1): j = i + length - 1 if S[i] == S[j]: if length == 2: dp[i][j] = w[i] + w[j] else: dp[i][j] = dp[i+1][j-1] + w[i] + w[j] else: dp[i][j] = max(dp[i+1][j], dp[i][j-1]) return dp[0][N-1] if name == "main": data = input().split() if data: N = int(data[0]) S = data[1] w = list(map(int, data[2:])) result = solve(N, S, w) print(result)

13.3k after i will post βœ… All tests passed code will Upload again

https://t.me/coding_are Share this group with your friends and college group.. I will upload next answer in 5min

import sys input = sys.stdin.readline def solve(n: int, l: int, a: list) -> int: if len(a) < n: a += list(map(int, sys.stdin.read().split())) cur = 1 ans = 1 for i in range(1, n): if abs(a[i] - a[i - 1]) <= l: cur += 1 else: cur = 1 ans = max(ans, cur) return ans Write with function

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