Learn Python Coding
Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills. Admin: @HusseinSheikho || @Hussein_Sheikho
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“Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills.
Admin: @HusseinSheikho || @Hussein_Sheikho”
Yuqori yangilanish chastotasi (oxirgi ma’lumot 31 Avgust, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
def filter_even_numbers(numbers):
return [num for num in numbers if num % 2 == 0]
my_numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
print(filter_even_numbers(my_numbers))[2, 4, 6, 8, 10]#97. Explain what
* does when unpacking a list or tuple.
A: The * operator can be used to unpack an iterable into individual elements. It's often used for function arguments or in assignments.
numbers = [1, 2, 3, 4, 5]
first, *middle, last = numbers
print(f"First: {first}")
print(f"Middle: {middle}")
print(f"Last: {last}")First: 1 Middle: [2, 3, 4] Last: 5#98. Write a function to merge two sorted lists into a single sorted list. A: You can simply concatenate them and sort, but a more efficient approach (O(n+m)) is to iterate through both lists simultaneously.
def merge_sorted_lists(list1, list2):
# The simple, Pythonic way
return sorted(list1 + list2)
l1 = [1, 3, 5]
l2 = [2, 4, 6]
print(merge_sorted_lists(l1, l2))[1, 2, 3, 4, 5, 6]#99. What will be the output of the following code? A: This question tests understanding of mutable default arguments.
def my_func(item, my_list=[]):
my_list.append(item)
return my_list
print(my_func(1))
print(my_func(2))
print(my_func(3))[1] [1, 2] [1, 2, 3]The default list is created only once when the function is defined. It is then shared across all subsequent calls, leading to this surprising behavior. The correct way is to use
my_list=None as the default.
#100. How would you count the occurrences of each word in a given text sentence?
A: The collections.Counter is the ideal tool for this task.
from collections import Counter
import re
sentence = "The quick brown fox jumps over the lazy dog dog"
# Pre-process: lowercase and split into words
words = re.findall(r'\w+', sentence.lower())
word_counts = Counter(words)
print(word_counts)Counter({'the': 2, 'dog': 2, 'quick': 1, 'brown': 1, 'fox': 1, 'jumps': 1, 'over': 1, 'lazy': 1})
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By: @DataScience4 ✨