Learn Python Coding
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Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills. Admin: @HusseinSheikho || @Hussein_Sheikho
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Tarmoq:📈 Telegram kanali Learn Python Coding analitikasi
Learn Python Coding (@pythonre) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 40 348 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 3 227-o'rinni va Hindiston mintaqasida 9 434-o'rinni egallagan.
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невідомо sanasidan buyon loyiha tez o‘sib, 40 348 obunachiga ega bo‘ldi.
14 Sentabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 244 ga, so‘nggi 24 soatda esa 19 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
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“Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills.
Admin: @HusseinSheikho || @Hussein_Sheikho”
Yuqori yangilanish chastotasi (oxirgi ma’lumot 15 Sentabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
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Kanal postlari
Repost from Machine Learning with Python
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| 5 | Creating Nested Dictionary Values using `setdefault()` 🔥
When grouping data, it's often necessary to check if a key exists, create a container for it, and then add a value.
For example, distributing users by role. Without special methods, this usually involves a separate key check.
users = [
("admin", "alex"),
("user", "max"),
("admin", "kate"),
]
groups = {}
for role, name in users:
if role not in groups:
groups[role] = []
groups[role].append(name)
The setdefault() method allows you to perform this operation directly when accessing the dictionary. If the key exists, it returns its current value. If the key is missing, the provided value is written to the dictionary and then returned:
groups = {}
for role, name in users:
groups.setdefault(
role,
[],
).append(name)
The result is the same structure without a separate key existence check:
print(groups)
# {
# 'admin': ['alex', 'kate'],
# 'user': ['max']
# }
It's important to note that the expression of the second argument is evaluated every time setdefault() is called, even if the key already exists. Therefore, you should avoid creating expensive objects or performing functions with side effects there:
value = cache.setdefault(
key,
build_value(),
)
In this code, build_value() will be called before the method itself is executed. If the value creation should only happen when the key is missing, it's better to use an explicit check or a suitable data structure, such as defaultdict.
🔥 setdefault() is well-suited for compactly initializing simple mutable containers when grouping and aggregating data. However, it's important to remember that the provided value is evaluated regardless of whether the key exists.
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| 18 | Why identical arguments can create different entries in `lru_cache`? 🤔
The lru_cache creates a key not only from the values of the arguments, but also from the way they are passed.
load(True)
load(debug=True)
Although both calls pass the same value, for the cache, these are different keys, so the function will be executed twice.
print(load.cache_info())
# CacheInfo(hits=0, misses=2, ...)
The order of named arguments can also affect how an entry is created in the cache.
func(a=1, b=2)
func(b=2, a=1)
Therefore, it is best to call cached functions in a consistent style: either by position or by name, in the same order.
load(debug=True)
load(debug=True)
🔥 A consistent call format prevents unnecessary cache misses and redundant execution of expensive operations.
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