Learn Python Coding
Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills. Admin: @HusseinSheikho || @Hussein_Sheikho
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网络:📈 Telegram 频道 Learn Python Coding 的分析概览
频道 Learn Python Coding (@pythonre) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 40 115 名订阅者，在 技术与应用 类别中位列第 3 236，并在 印度 地区排名第 9 568 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 40 115 名订阅者。
根据 30 八月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 151，过去 24 小时变化为 53，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 2.36%。内容发布后 24 小时内通常能获得 1.08% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 946 次浏览，首日通常累积 435 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 2。
- 主题关注点： 内容集中在 math, harvard, oxford, supervision, waybienad 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills.
Admin: @HusseinSheikho || @Hussein_Sheikho”
凭借高频更新（最新数据采集于 31 八月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 技术与应用 类别中的关键影响点。
def filter_even_numbers(numbers):
return [num for num in numbers if num % 2 == 0]
my_numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
print(filter_even_numbers(my_numbers))[2, 4, 6, 8, 10]#97. Explain what
* does when unpacking a list or tuple.
A: The * operator can be used to unpack an iterable into individual elements. It's often used for function arguments or in assignments.
numbers = [1, 2, 3, 4, 5]
first, *middle, last = numbers
print(f"First: {first}")
print(f"Middle: {middle}")
print(f"Last: {last}")First: 1 Middle: [2, 3, 4] Last: 5#98. Write a function to merge two sorted lists into a single sorted list. A: You can simply concatenate them and sort, but a more efficient approach (O(n+m)) is to iterate through both lists simultaneously.
def merge_sorted_lists(list1, list2):
# The simple, Pythonic way
return sorted(list1 + list2)
l1 = [1, 3, 5]
l2 = [2, 4, 6]
print(merge_sorted_lists(l1, l2))[1, 2, 3, 4, 5, 6]#99. What will be the output of the following code? A: This question tests understanding of mutable default arguments.
def my_func(item, my_list=[]):
my_list.append(item)
return my_list
print(my_func(1))
print(my_func(2))
print(my_func(3))[1] [1, 2] [1, 2, 3]The default list is created only once when the function is defined. It is then shared across all subsequent calls, leading to this surprising behavior. The correct way is to use
my_list=None as the default.
#100. How would you count the occurrences of each word in a given text sentence?
A: The collections.Counter is the ideal tool for this task.
from collections import Counter
import re
sentence = "The quick brown fox jumps over the lazy dog dog"
# Pre-process: lowercase and split into words
words = re.findall(r'\w+', sentence.lower())
word_counts = Counter(words)
print(word_counts)Counter({'the': 2, 'dog': 2, 'quick': 1, 'brown': 1, 'fox': 1, 'jumps': 1, 'over': 1, 'lazy': 1})
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By: @DataScience4 ✨