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AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 37 979 obunachidan iborat bo'lib, Taʼlim toifasida 4 959-o'rinni va Hindiston mintaqasida 10 221-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 37 979 obunachiga ega bo‘ldi.

23 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 1 060 ga, so‘nggi 24 soatda esa 30 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 11.95% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 6.26% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 4 536 marta ko‘riladi; birinchi sutkada odatda 2 378 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 6 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

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Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 24 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

37 979

Obunachilar

+3024 soatlar

+2027 kun

+1 06030 kun

4 536

Post ko'rishlar

~ 2 37824 soatlar

~ 2 92248 soatlar

11.95%

Muloqot nisbati

~ 8

Kuniga postlar

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Postlar arxiv

37 983

Repost from N/a

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these 2 are the most easiest chapters in addmaths, masterize these 2 if you want to pass.

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💗💗May month support for maths and addmaths🔥🔥 😢😢Worried about SPM exams approaching too quickly? My recorded video lessons for maths and addmaths has got you covered!💪💪 🍀🍀Online whatsapp support group available and personal guidance from me to all your questions🙌🙌 🤩🤩What are you waiting for? Contact 0179660510 to join me and hundreds of other students on the road to success❤️❤️

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A challenge for anyone who have studied f5c6, Find the problem in this video.

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https://www.youtube.com/watch?v=HxUU-ra1JBo&list=PL1i-vcfkkTHM_iqfaggz_cnjsp9p04GJ5&index=42

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Kategori pertama, anda ingin mendapat skor sekitar 10-15 jadi, untuk SPM anda dapat LULUS untuk matematik tambahan, fokus pada bab-bab ini f4(1,2,3,6,10) jika boleh belajar f5(1,7) (boleh mendapat skor di atas 20) Kategori kedua, anda ingin mendapat skor sekitar 20-35 untuk SPM jadi anda dapat KREDIT untuk matematik tambahan, fokus pada bab-bab ini f4(1,2,3,6,10) f5(1,7) jika boleh cuba belajar f5c2,f5c6 (boleh mendapat skor di atas 40) Kategori ketiga, anda ingin mendapat skor sekitar 45-65 untuk SPM jadi anda dapat B atau A untuk matematik tambahan fokus pada bab-bab ini f4(1,2,3,4,6,7,9,10) f5(1,2,6,7,8) jika boleh cuba belajar f4c5,f4c8, f5c3,f5c5, (boleh mendapat skor di atas 75) Kategori keempat, anda ingin mendapat skor sekitar 75-100 untuk SPM jadi anda dapat A+ untuk matematik tambahan belajar semua terpulang kepada anda untuk tidak belajar 1 atau 2 bab maksimum.

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1st category, u want to score around 10-15 so, for SPM u get LULUS for addmaths, focus on these chapters f4(1,2,3,6,10) if possible study f5(1,7) (can score above 20) 2nd category, u want to score around 20-35 for spm so u get KREDIT for addmaths, focus on these chapters f4(1,2,3,6,10) f5(1,7) if possible try to study f5c2,f5c6 (can score above 40) 3rd category, u want to score around 45-65 for spm so u get B or A for addmaths focus on these chapters f4(1,2,3,4,6,7,9,10) f5(1,2,6,7,8) if possible try to study f4c5,f4c8, f5c3,f5c5, (can score above 75) 4th category u want to score around 75-100 for SPM so u get A+ for addmaths study all its up to u to not study 1 or 2 chapters maximum.

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those who said yes, dont forget to check again for the meaning of congruent.

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Level 2: replace 81 with a. Express x in terms of a.

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I guess because the length of triangle A & B are not the same even though it have the same interior angles , C is another case .

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does the question maker understands the meaning of CONGRUENT?

Anonymous voting

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if u dont consider the function J above and just focus to 3b, u should use definite integral, and u should integrate from 1 to 2, or u can also integrate from 0 to 2 and minus 0 to 1. and the correct answer would be 3950 liters.

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this question is wrong, and answer provided is also wrong, u wont get dj/dt if u differentiate j function, and this questions wants to use integral as the reverse of differentiation concept, and not adding +c, and they want u to substitute 2, which is totally wrong.

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Okay guys.... I have trouble with 5a... can anyone help me with this question?

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Repost from Bayu Cendekia *ೃ༄

Bahan untuk malam ni ya Cendekians!✨💫

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Repost from Bayu Cendekia *ೃ༄

MASIH PENING DENGAN FUNGSI? MALAM NI KITA SETELKAN! 🧠💥 Cendekians, malam ni ada slot last untuk minggu ni tahu! Kita ada Cendekiawan Muda Aisya yang akan share rahsia macam mana nak skor bab Functions (Tingkatan 4 Bab 1). 📚✨ Bab ni nampak macam senang, tapi kalau silap konsep f(x) dengan f^{-1}(x), memang boleh melayang markah! 📉😱 ⏰ 9.00 PM – 10.30 PM 🗓 26 Mei 2026 (Selasa / Malam Ini) Sambil-sambil rehat malam ni, jom masuk kelas bawa buku nota. Kita bagi tajuk Fungsi ni 'singgah' terus masuk dalam kepala. 🧠💡 🔗 LINK UNTUK KELAS MALAM NI: http://meet.google.com/fts-xixu-fcb "From students, For students" #BayuCendekia #addmath@bayucendekia #spm2026

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the answers for this will be somewhat close to the poll.