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AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

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📈 Telegram kanali AddMath Spmnetic!™⚡️ analitikasi

AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 38 035 obunachidan iborat bo'lib, Taʼlim toifasida 4 963-o'rinni va Hindiston mintaqasida 10 224-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 38 035 obunachiga ega bo‘ldi.

25 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 1 035 ga, so‘nggi 24 soatda esa 21 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 12.44% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 6.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 4 727 marta ko‘riladi; birinchi sutkada odatda 2 375 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 10 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 26 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

38 035
Obunachilar
+2124 soatlar
+1497 kun
+1 03530 kun
Postlar arxiv
Since someone asked for hints. 😁👍
Since someone asked for hints. 😁👍

Apakah nilai √(-5)² ?
Anonymous voting

Apakah nilai √(-5)²
Anonymous voting

photo content

Try this. Find the area of the shaded region. No rewards though. 🤣🤣
Try this. Find the area of the shaded region. No rewards though. 🤣🤣

Try this. Find the area of the shaded region. No rewards though. 🤣🤣
Try this. Find the area of the shaded region. No rewards though. 🤣🤣

As long as above y-axis, no matter what shape, the object is still accelerating.

This is because all of them are above the y-axis.

Hello there homie. Let's say all of these are acceleration-time graph. The object in the following graphs are all still accel
+2
Hello there homie. Let's say all of these are acceleration-time graph. The object in the following graphs are all still accelerating.

the 48km one, u dont have to worry if u dont understand, its not important for now. but if u insist to understand it, feel free to ask.

is there any questions u dont understand above? if yes lemme know in comments, 12 am I will explain.

Since velocity is a vector quantity, it consists of both magnitude (speed) and direction. Therefore, a change in either the magnitude or the direction of motion is defined as acceleration.

A stock's value drops by 50% on Monday. What percentage must it rise on Tuesday to return to its original value?
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A car travels from Point A to Point B at 40km/h and returns from B to A at 60km/h. What is the average speed for the round trip?
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An object is traveling at a constant speed of 10ms^-1. Is it possible for the object to be accelerating?
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If an object is moving in a perfect circle at a constant speed, is it "accelerating"?
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If an object is moving in a perfect circle at a constant speed, is it not accelerating?
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For those who maybe confuse...we have to look at what the object is actually doing. For acceleration (a > 0)..the velocity of the object is increasing..while deceleration (a < 0)..the velocity of the object is decreasing. In the quiz, the acceleration changes from 3 m s-² to 2 m s-²..both numbers are positive.Because the acceleration is still positive,the object is still gaining speed every second. It is simply gaining speed more slowly than it was before. Imagine you are pressing the gas pedal in a car. At first, you floor it which is high acceleration.Then, you lift your foot slightly but keep pressing down which is lower acceleration.The car is still speeding up, just not as quickly as before.You haven't hit the brakes yet.. So...when would it be deceleration? For the motion to be considered deceleration,the acceleration value would need to become negative which is relative to the direction of motion..

Can an object have zero velocity but non-zero acceleration?
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if an object's acceleration has changed from 3ms^-2 to 2ms^-2, the motion is
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