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فریب کلاهبرداران را نخورید! تل‌متریو این کانال‌ها را شناسایی و برچسب‌گذاری می‌کند 👉 برای مشاهده برچسب، اشتراک تهیه کنید

AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

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📈 تحلیل کانال تلگرام AddMath Spmnetic!™⚡️

کانال AddMath Spmnetic!™⚡️ (@addmathspmnotes) در بخش زبانی انگلیسی بازیگری فعال است. در حال حاضر جامعه شامل 38 004 مشترک است و جایگاه 4 963 را در دسته آموزش و رتبه 10 224 را در منطقه الهند دارد.

📊 شاخص‌های مخاطب و پویایی

از زمان ایجاد در невідомо، پروژه رشد سریعی داشته و 38 004 مشترک جذب کرده است.

بر اساس آخرین داده‌ها در تاریخ 25 اکتبر, 2026، کانال فعالیت پایداری دارد. در ۳۰ روز گذشته تغییر اعضا برابر 1 035 و در ۲۴ ساعت گذشته برابر 21 بوده و همچنان دسترسی گسترده‌ای حفظ شده است.

  • وضعیت تأیید: تأیید نشده
  • نرخ تعامل (ER): میانگین تعامل مخاطب 12.44% است و در ۲۴ ساعت نخست پس از انتشار، محتوا معمولاً 6.25% واکنش نسبت به کل مشترکان کسب می‌کند.
  • دسترسی پست‌ها: هر پست به طور میانگین 4 727 بازدید دریافت می‌کند. در اولین روز معمولاً 2 375 بازدید جمع‌آوری می‌شود.
  • واکنش‌ها و تعامل: مخاطبان به‌طور فعال حمایت می‌کنند؛ میانگین واکنش به هر پست 10 است.
  • علایق موضوعی: محتوا بر موضوعات کلیدی مانند addmath, untuk, 629/4, math, eqn تمرکز دارد.

📝 توضیح و سیاست محتوایی

نویسنده این فضا را محل بیان دیدگاه‌های شخصی توصیف می‌کند:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

به لطف به‌روزرسانی‌های پرتکرار (آخرین داده در تاریخ 26 اکتبر, 2026)، کانال همواره به‌روز و دارای دسترسی بالاست. تحلیل‌ها نشان می‌دهد مخاطبان به‌طور فعال با محتوا تعامل دارند و آن را به نقطه اثرگذاری مهم در دسته آموزش تبدیل کرده‌اند.

38 004
مشترکین
+2124 ساعت
+1497 روز
+1 03530 روز
آرشیو پست ها
Since someone asked for hints. 😁👍
Since someone asked for hints. 😁👍

Apakah nilai √(-5)² ?
Anonymous voting

Apakah nilai √(-5)²
Anonymous voting

photo content

Try this. Find the area of the shaded region. No rewards though. 🤣🤣
Try this. Find the area of the shaded region. No rewards though. 🤣🤣

Try this. Find the area of the shaded region. No rewards though. 🤣🤣
Try this. Find the area of the shaded region. No rewards though. 🤣🤣

As long as above y-axis, no matter what shape, the object is still accelerating.

This is because all of them are above the y-axis.

Hello there homie. Let's say all of these are acceleration-time graph. The object in the following graphs are all still accel
+2
Hello there homie. Let's say all of these are acceleration-time graph. The object in the following graphs are all still accelerating.

the 48km one, u dont have to worry if u dont understand, its not important for now. but if u insist to understand it, feel free to ask.

is there any questions u dont understand above? if yes lemme know in comments, 12 am I will explain.

Since velocity is a vector quantity, it consists of both magnitude (speed) and direction. Therefore, a change in either the magnitude or the direction of motion is defined as acceleration.

A stock's value drops by 50% on Monday. What percentage must it rise on Tuesday to return to its original value?
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A car travels from Point A to Point B at 40km/h and returns from B to A at 60km/h. What is the average speed for the round trip?
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An object is traveling at a constant speed of 10ms^-1. Is it possible for the object to be accelerating?
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If an object is moving in a perfect circle at a constant speed, is it "accelerating"?
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If an object is moving in a perfect circle at a constant speed, is it not accelerating?
Anonymous voting

For those who maybe confuse...we have to look at what the object is actually doing. For acceleration (a > 0)..the velocity of the object is increasing..while deceleration (a < 0)..the velocity of the object is decreasing. In the quiz, the acceleration changes from 3 m s-² to 2 m s-²..both numbers are positive.Because the acceleration is still positive,the object is still gaining speed every second. It is simply gaining speed more slowly than it was before. Imagine you are pressing the gas pedal in a car. At first, you floor it which is high acceleration.Then, you lift your foot slightly but keep pressing down which is lower acceleration.The car is still speeding up, just not as quickly as before.You haven't hit the brakes yet.. So...when would it be deceleration? For the motion to be considered deceleration,the acceleration value would need to become negative which is relative to the direction of motion..

Can an object have zero velocity but non-zero acceleration?
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if an object's acceleration has changed from 3ms^-2 to 2ms^-2, the motion is
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