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Firibgarlarga uchmang! Telemetrio bunday kanallarni topadi va belgilaydi 👉 Belgini ko‘rmoqchi bo‘lsangiz, obuna bo‘ling

AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

Kanalga Telegram’da o‘tish

This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

Ko'proq ko'rsatish

📈 Telegram kanali AddMath Spmnetic!™⚡️ analitikasi

AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 38 035 obunachidan iborat bo'lib, Taʼlim toifasida 4 963-o'rinni va Hindiston mintaqasida 10 224-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 38 035 obunachiga ega bo‘ldi.

25 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 1 035 ga, so‘nggi 24 soatda esa 21 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 12.44% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 6.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 4 727 marta ko‘riladi; birinchi sutkada odatda 2 375 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 10 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 26 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

38 035
Obunachilar
+2124 soatlar
+1497 kun
+1 03530 kun
Postlar arxiv
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For question 2.
For question 2.

Pikat dibawa ke tengah rimba, Taji tajam berkilat cahaya; Syawal mulia kini telah tiba, Maaf dipinta di hari raya. Kokok galak memecah sunyi, Tunggu 'samurai' turun ke laman; Silap dan salah harap dimaafi, Tulus ikhlas buatkan teman. Tangkas melompat si ayam hutan, Masuk racik tersimpul mati; Tanda persaudaraan kita kekalkan, Maaf zahir batin setulus hati. Assalamualaikum teman ii , saya barq (admin) ingin mengucapkan Selamat Hari Raya Maaf Zahir dan Batin , saya ingin memohon maaf jika saya ada terkasar bahasa atau pun saya ada membuat sesuatu yang membuatkan teman teman rasa kecik hati. selamat hari raya buat anda sekeluarga <3

For someone who don't realized, those curve lines around the parallelogram is actually a semicircle and a quarter circle.
For someone who don't realized, those curve lines around the parallelogram is actually a semicircle and a quarter circle.

After someone answers correctly, I will share number 2 answer also

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+1

One of the solutions

The rest I'll send later on. I'm outside holidaying. 🤣🤣

For the first question.
For the first question.

Answer 1-1.23 Answer 2-10.00 Answer 3-1.84

James sinweixuan is the winner for this competition, since he got 2/3 correct, tho didn't follow 2 decimal places instruction. Congratulations broo...keep it up...others, good try learn your mistakes, don't trust ai so much.

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No one got even 1 question correct..

Ok the contest has finished properly, time to announce the winner.

Ok la no submission after 5pm

Should I extend the timing to 5pm?
Anonymous voting

Luas berlorek = ?

Luas segi empat selari = 28 cm² Luas berlorek = ?