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AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

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📈 Análisis del canal de Telegram AddMath Spmnetic!™⚡️

El canal AddMath Spmnetic!™⚡️ (@addmathspmnotes) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 38 035 suscriptores, ocupando la posición 4 963 en la categoría Educación y el puesto 10 224 en la región India.

📊 Métricas de audiencia y dinámica

Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 38 035 suscriptores.

Según los últimos datos del 25 octubre, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de 1 035, y en las últimas 24 horas de 21, conservando un alto alcance.

  • Estado de verificación: No verificado
  • Tasa de interacción (ER): El promedio de interacción de la audiencia es 12.44%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 6.25% de reacciones respecto al total de suscriptores.
  • Alcance de las publicaciones: Cada publicación recibe en promedio 4 727 visualizaciones. En el primer día suele acumular 2 375 visualizaciones.
  • Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 10.
  • Intereses temáticos: El contenido se centra en temas clave como addmath, untuk, 629/4, math, eqn.

📝 Descripción y política de contenido

El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 26 octubre, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Educación.

38 035
Suscriptores
+2124 horas
+1497 días
+1 03530 días
Archivo de publicaciones
Since someone asked for hints. 😁👍
Since someone asked for hints. 😁👍

Apakah nilai √(-5)² ?
Anonymous voting

Apakah nilai √(-5)²
Anonymous voting

photo content

Try this. Find the area of the shaded region. No rewards though. 🤣🤣
Try this. Find the area of the shaded region. No rewards though. 🤣🤣

Try this. Find the area of the shaded region. No rewards though. 🤣🤣
Try this. Find the area of the shaded region. No rewards though. 🤣🤣

As long as above y-axis, no matter what shape, the object is still accelerating.

This is because all of them are above the y-axis.

Hello there homie. Let's say all of these are acceleration-time graph. The object in the following graphs are all still accel
+2
Hello there homie. Let's say all of these are acceleration-time graph. The object in the following graphs are all still accelerating.

the 48km one, u dont have to worry if u dont understand, its not important for now. but if u insist to understand it, feel free to ask.

is there any questions u dont understand above? if yes lemme know in comments, 12 am I will explain.

Since velocity is a vector quantity, it consists of both magnitude (speed) and direction. Therefore, a change in either the magnitude or the direction of motion is defined as acceleration.

A stock's value drops by 50% on Monday. What percentage must it rise on Tuesday to return to its original value?
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A car travels from Point A to Point B at 40km/h and returns from B to A at 60km/h. What is the average speed for the round trip?
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An object is traveling at a constant speed of 10ms^-1. Is it possible for the object to be accelerating?
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If an object is moving in a perfect circle at a constant speed, is it "accelerating"?
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If an object is moving in a perfect circle at a constant speed, is it not accelerating?
Anonymous voting

For those who maybe confuse...we have to look at what the object is actually doing. For acceleration (a > 0)..the velocity of the object is increasing..while deceleration (a < 0)..the velocity of the object is decreasing. In the quiz, the acceleration changes from 3 m s-² to 2 m s-²..both numbers are positive.Because the acceleration is still positive,the object is still gaining speed every second. It is simply gaining speed more slowly than it was before. Imagine you are pressing the gas pedal in a car. At first, you floor it which is high acceleration.Then, you lift your foot slightly but keep pressing down which is lower acceleration.The car is still speeding up, just not as quickly as before.You haven't hit the brakes yet.. So...when would it be deceleration? For the motion to be considered deceleration,the acceleration value would need to become negative which is relative to the direction of motion..

Can an object have zero velocity but non-zero acceleration?
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if an object's acceleration has changed from 3ms^-2 to 2ms^-2, the motion is
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