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AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

Kanalga Telegram’da o‘tish

This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

Ko'proq ko'rsatish

📈 Telegram kanali AddMath Spmnetic!™⚡️ analitikasi

AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 33 800 obunachidan iborat bo'lib, Taʼlim toifasida 5 626-o'rinni va Hindiston mintaqasida 12 164-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 33 800 obunachiga ega bo‘ldi.

22 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 528 ga, so‘nggi 24 soatda esa 18 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 14.27% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 6.03% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 4 822 marta ko‘riladi; birinchi sutkada odatda 2 038 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 7 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

Yuqori yangilanish chastotasi (oxirgi ma’lumot 23 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

33 800
Obunachilar
+1824 soatlar
+747 kunlar
+52830 kunlar
Postlar arxiv
JANJANG/PROGRESSIONS •gp C5F4
+2
JANJANG/PROGRESSIONS •gp C5F4

JANJANG/PROGRESSIONS •gp(geometric progression) C5F4
+1
JANJANG/PROGRESSIONS •gp(geometric progression) C5F4

JANJANG/PROGRESSIONS •gp (geometric progression) C5F4
+1
JANJANG/PROGRESSIONS •gp (geometric progression) C5F4

btw JEE advanced is one of the most toughest exams for undergraduate students..

congrats to Aireez
congrats to Aireez

haha, a very nice question...
haha, a very nice question...

Answer
Answer

congrats to Nisha also...👍🏽👍🏽👍🏽
congrats to Nisha also...👍🏽👍🏽👍🏽

remember not all linear functions are arithemic sequences, but all arithemic sequences are linear functions..

congrats to amni madiha...

y=ax+b tu linear function Yang nj ikut pola je f(1) = 4 f(2) = 7 So 7-4=3 So .. f(3) = 7+3

guys, may I know your working for this question?

f(x) = 2x + 3, g(x) = x^2. Solve f(x) = g(x) for x.
Anonymous voting

f(x+2) = f(x) + 6, f(0) = 1. Find f(4).
Anonymous voting

f(x+1) = f(x) + 5, f(0) = 2. What is f(3)?
Anonymous voting

If f(x) = 2x - 1, what is f inverse of 3?
Anonymous voting

If f(x) = ax+ b, if f(1) = 4 and f(2) = 7. Find f(3)
Anonymous voting

lets make it a bit more harder 🙂

Given f(x) = 2x + 1 and f(a) = 13, find the value of a.
Anonymous voting