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AddMath Spmnetic!™⚡️

Open in Telegram

This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

Network: Sejarah spmnetic!™India9 921Education4 919...

📈 Analytical overview of Telegram channel AddMath Spmnetic!™⚡️

Channel AddMath Spmnetic!™⚡️ (@addmathspmnotes) in the English language segment is an active participant. Currently, the community unites 38 217 subscribers, ranking 4 919 in the Education category and 9 921 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 38 217 subscribers.

According to the latest data from 02 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 909 over the last 30 days and by 21 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 13.94%. Within the first 24 hours after publication, content typically collects 6.13% reactions from the total number of subscribers.
Post reach: On average, each post receives 5 328 views. Within the first day, a publication typically gains 2 342 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 17.
Thematic interests: Content is focused on key topics such as addmath, untuk, 629/4, math, eqn.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Thanks to the high frequency of updates (latest data received on 03 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

38 217

Subscribers

+2124 hours

+1807 days

+90930 days

5 328

Post views

~ 2 34224 hours

~ 2 98848 hours

13.94%

Engagement rate

~ 5

Posts per day

Ads index

Posts Archive

38 217

saya akan hantar lagi 50 soalan yg bukan susah sangat guyss ( cuba buat semua soalan ni kalau u guys aim credit shj)

38 217

ok guys 10 soalan ady, pls react a bit to make me continue posting

38 217

guys since tmr u guys have malay exam, lemme send 10 problems as i said, but u guys can try it after exam

38 217

Let x=length of the rectangle h = height of the rectangle Black line = h/tan(60°) = (h√3)/3 Using Pythagoras' Theorem, [(h√3)/3 + x]² + h² = 36 h²/3 + (2xh√3)/3 + x² + h² - 36 = 0 h²(4/3) + [(2x√3)/3]h + (x²-36) = 0 h = [-(2x√3)/3 + √[(4x²/3)-(16/3)(x²-36)]]/(8/3) h = [-x√3 + 3√(48-x²)]/4 Area of the rectangle, A = xh = x([-x√3 + 3√(48-x²)]/4) dA/dx = (72-3x²-x√(144-3x²))/(2√(48-x²)) At Maximum, dA/dx = 0 (72-3x²-x√(144-3x²))/(2√(48-x²)) = 0 72-3x²-x√(144-3x²) = 0 => x=-6 or x=2√3 Max A = 6√3

38 217

Thanks to TonyCWX

38 217

Circular measure+ differentiation

38 217

Repost from 9a+ 🤝

addmath f4 ch 5 progressions