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AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

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📈 Analytical overview of Telegram channel AddMath Spmnetic!™⚡️

Channel AddMath Spmnetic!™⚡️ (@addmathspmnotes) in the English language segment is an active participant. Currently, the community unites 38 215 subscribers, ranking 4 922 in the Education category and 9 910 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 38 215 subscribers.

According to the latest data from 01 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 939 over the last 30 days and by 28 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 12.94%. Within the first 24 hours after publication, content typically collects 6.07% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 4 942 views. Within the first day, a publication typically gains 2 318 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 14.
  • Thematic interests: Content is focused on key topics such as addmath, untuk, 629/4, math, eqn.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Thanks to the high frequency of updates (latest data received on 02 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

38 215
Subscribers
+2824 hours
+1907 days
+93930 days
Posts Archive
Answer now U have 1000 bottles kan So U number all the bottles 1 to 1000 and make it to binary digits So Ur 1st bottle is numbered as 0000000001 2nd bottle is 000000010 The 000000011 Then 000000100 Like that Ok now there are 10 rats kan So if let's say rat1 U need to feed wine with all the bottles that have 1 at the 10th digit, 2 Nd rat should drink from all the wine bottles that have 1 in 9th place mcm tu, So at the end since 2 to the power of 10 is 1024 and it's lesser than 1000, U can find which bottle is poisoned based on which rats died..

Guys actually I am just form 4 now, but my father asks me many different types of questions, these weird questions are my father's questions, if U know how to do these, it proves you can do hots questions..

Question is how U will find the poisoned bottle?

Google translate

Bayangkan U adalah raja sebuah negara, dan dalam masa 24 jam, U mengadakan acara dengan 1000 tetamu, dan U menyediakan 1000 botol wain untuk tetamu, tetapi orang jahat meracuni 1 botol wain, jadi sekarang U mempunyai 10 ekor tikus untuk mengetahui yang manakah wain beracun, Anda boleh menyuapkan setitik wain kepada tikus-tikus itu, sebotol wain dan tin yang tepat dapat dibuang... ia, anda tidak boleh membuang semua botol wain, dan bahagian yang terbaik ialah tikus akan mati dalam masa 24 jam setelah minum racun..

Imagine U are a king of a country, and in 24 hours,U have an event with 1000 guests, and U prepared 1000 bottle of wine for the guests, but a bad guy poisoned 1 of the wine bottles, so now U have 10 rats to find out which is the poisoned wine, U can feed a drop of wine to the rats, rats can drink from multiple bottle of wines... U should find the exact bottle of wine and throw it, U can't throw all the bottles of wines, and the next part is the rat will die in 24 hours once drank the poison..

Pukul 1.15 saya akan hantar

So 3432

its just 14C7 😂

Siapa mau lagi 1 soalan kbat yg mmg Susah gila Kalau U tak tahu Cara penyelesaian

Yg ni 1 mark question 😂😂😂

It can move 7ups and then 7rights , or 7rights 1st then 7ups, it doesn't matter how many rights/ups

Imagine there is one rook piece placed in A1(red box) , it should finally reach h8(orange box) the rook can only move up or right, so what's the total different ways to reach h8??

photo content

Guys another tricky question(super easy actually) for Permutations and combinations

This proves that sometimes, we need to think before you write anything.,

my approach was a bit different , I use Pythagoras to make quadratic which returned imaginary roots so triangle cannot exist

Which means, there won't be any area.

Since it's a right angle triangle, we can draw a circle circumscribing the triangle. This circle will have a radius of 5. But as you can see, the altitude ( or height in simple terms ) is 6, which is larger than the radius. Hence, the triangle is impossible to be constructed.

The triangle does not exist.