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KPIT EXAM SOLUTIONS

KPIT EXAM SOLUTIONS

前往频道在 Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 Telegram 频道 KPIT EXAM SOLUTIONS 的分析概览

频道 KPIT EXAM SOLUTIONS (@coding_are) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 14 156 名订阅者,在 教育 类别中位列第 14 030,并在 印度 地区排名第 28 046

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 14 156 名订阅者。

根据 17 九月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -126,过去 24 小时变化为 -13,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 4.44%。内容发布后 24 小时内通常能获得 1.62% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 629 次浏览,首日通常累积 229 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 1
  • 主题关注点: 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

凭借高频更新(最新数据采集于 18 九月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

14 156
订阅者
-1324 小时
-117 天
-12630 天
帖子存档
10am Infosys exam successfully completed by remote access 👍👍👍👍👍 3/3 code done with all tests cases passed ✅ ✅ ✅ Contact
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10am Infosys exam successfully completed by remote access 👍👍👍👍👍 3/3 code done with all tests cases passed ✅ ✅ ✅ Contact for placement exam @srksvk

10am Infosys exam successfully completed by remote access 👍👍👍👍👍 3/3 code done with all tests cases passed ✅ Contact for
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10am Infosys exam successfully completed by remote access 👍👍👍👍👍 3/3 code done with all tests cases passed ✅ Contact for placement exam

10am Infosys exam successfully completed by remote access 👍👍 3/3 code done with all tests cases passed ✅✅✅ Contact for plac
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10am Infosys exam successfully completed by remote access 👍👍 3/3 code done with all tests cases passed ✅✅✅ Contact for placement exam @srksvk Slot 4

10am Infosys exam successfully completed by remote access 👍👍 3/3 code done with all tests cases passed ✅✅✅ Contact for plac
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10am Infosys exam successfully completed by remote access 👍👍 3/3 code done with all tests cases passed ✅✅✅ Contact for placement exam @srksvk Slot 3

10am Infosys exam successfully completed by remote access 👍👍 3/3 code done with all tests cases passed ✅✅✅ Contact for plac
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10am Infosys exam successfully completed by remote access 👍👍 3/3 code done with all tests cases passed ✅✅✅ Contact for placement exam @srksvk Slot 2

10am Infosys exam successfully completed by remote access 👍👍 3/3 code done with all tests cases passed ✅✅✅ Contact for plac
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10am Infosys exam successfully completed by remote access 👍👍 3/3 code done with all tests cases passed ✅✅✅ Contact for placement exam @srksvk

def solve(N: int, X: int, Y: int, Z: int) -> int: if N == 1: return 0 dp0 = [0] * (N + 1) dp1 = [0] * (N + 1) for n in ran
def solve(N: int, X: int, Y: int, Z: int) -> int: if N == 1: return 0 dp0 = [0] * (N + 1) dp1 = [0] * (N + 1) for n in range(2, N + 1): sub_cost = X + dp0[n - 1] dp1[n] = sub_cost dp0[n] = sub_cost if n % 2 == 0: cand = Y + dp1[n // 2] if cand < dp0[n]: dp0[n] = cand if n % 3 == 0: cand = Z + dp1[n // 3] if cand < dp0[n]: dp0[n] = cand return dp0[N]

For that question ready 👇👇👇
For that question ready 👇👇👇

Ready for that ✅ Share fast ⏩⏩
Ready for that ✅ Share fast ⏩⏩

Answer share here join and and check Full passed ✅ https://whatsapp.com/channel/0029VaicY2a65yD2YNehWP2j .
Answer share here join and and check Full passed ✅ https://whatsapp.com/channel/0029VaicY2a65yD2YNehWP2j .

I will send all answers here . Just share my group https://t.me/coding_are

Next answer loaded 👇👇👇 https://t.me/coding_are https://t.me/coding_are

Custom Fence Panels import sys from math import gcd input = sys.stdin.readline def inverse(x, mod): a, b = x, mod p, q = 1, 0 while b: div = a // b a, b = b, a % b p, q = q, p - div * q return p % mod def solve(N: int, a: int, b: int, p: int, q: int, F: int) -> int: g = gcd(a, b) if N % g != 0: return F a //= g b //= g N //= g if b == 1: x = 0 else: x = (N * inverse(a, b)) % b y = (N - a * x) // b if y < 0: return F if b * p < a * q: k = y // a x += k * b y -= k * a cost = x * p + y * q return min(cost, F) https://t.me/coding_are

Share my channel guys https://t.me/coding_are Fast

import sys input = sys.stdin.readline def solve(N: int) -> int: MOD = 10**9 + 7 a, b, c = 1, 1, 1 # N=1: "A", "B", "C" for _
import sys input = sys.stdin.readline def solve(N: int) -> int: MOD = 10**9 + 7 a, b, c = 1, 1, 1 # N=1: "A", "B", "C" for _ in range(2, N + 1): na = (b + c) % MOD nb = (a + b) % MOD nc = (a + b + c) % MOD a, b, c = na, nb, nc return (a + b + c) % MOD if name == "main": try: N = int(input()) result = solve(N) print(result) except (EOFError, ValueError): pass

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