AddMath Spmnetic!™⚡️

U can try revising all lower form chapters using book, if U think it's time consuming, feel free to search tchr daisy videos

Soon maths / addmaths ppt? Forgot about lower form maths?

Shout out to @seankoko3 for this wonderful solution. 🔥🔥

Not so SPM friendly. But I'll just post it anyways. 🤣🤣

😭It's late. You've done enough for today. Sleep now, grind tomorrow. 📈

haha, now is it clear?

B-BOY G-GIRL BB BG GB GG we must eliminate BB from our list since we know one is a girl, and in BG, GB, GG the only possibility is GG, so 1/3 is the answer

the correct answer for this is D

bab 2 persamaan kuadratik f4

hey hey!! I'm raffa and I will be one of ur new add math admins! saya batch 10 and I'm still studying adm but I THINK I got the hang of it so far. without wasting anymore time, I hope u guys don't mind if I post a few questions here already!! it's very simple

MOTIVATION keep this as you phone wallpaper...

try to read this completely

Edit jap

I am sorry for teaching wrongly, the correct answer to this question is , you cannot determine if the object is accelerating or decelerating , because the initial velocity of object is not given, if lets say the initial velocity was -3ms-1, or in words 3 meters per second to the left(assuming right as positive and left as negative) then it would be deceleration because acceleration works like a push force. lets say u are moving to the right with speed of 2ms-2 and if your acceleration is 2 ms-2, then its acceleration because the push direction and the direction of your initial motion is same, but if lets say the u are moving left with the speed of 2ms-1 and if your acceleration is 2 ms-2, then its deceleration because the push direction and the direction of your initial motion is not same, so to determine if an object is accelerating or decelerating, we have a formula av>0 means acceleration or av<0 means deceleration, where a is acceleration and v is velocity. Saya minta maaf kerana sebelum ini tersilap mengajar. Jawapan yang betul untuk soalan ini ialah: kita tidak boleh tentukan sama ada objek itu sedang memecut atau mengalami nyahpecutan kerana halaju awal objek tidak diberikan. Sebabnya, pecutan bertindak seperti daya tolakan (push force). Katakanlah halaju awal ialah -3 ms-1 (iaitu bergerak 3 meter sesaat ke kiri, jika kita anggap kanan sebagai positif dan kiri sebagai negatif): Jika kita bergerak ke kanan dengan halaju 2 ms-1 dan pecutan kita juga 2 ms-2 (ke kanan sebab anggap kanan sebagai positif dan kiri sebagai negatifi), maka itu adalah Pecutan. Ini kerana arah tolakan dan arah gerakan asal adalah sama. Jika kita bergerak ke kiri dengan halaju 2 ms-1 tetapi pecutan kita adalah 2 ms-2 (ke kanan), maka itu adalah Nyahpecutan. Ini kerana arah tolakan bertentangan dengan arah gerakan asal, menyebabkan objek menjadi perlahan. Jadi, untuk menentukan sama ada sesuatu objek itu memecut atau mengalami nyahpecutan, kita gunakan formula ini: av > 0 bermaksud Pecutan (Laju bertambah). av < 0 bermaksud Nyahpecutan (Laju berkurang). Di mana a ialah pecutan dan v ialah halaju.

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