AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

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Tarmoq:Sejarah spmnetic!™Hindiston12 519 Taʼlim5 671...

📈 Telegram kanali AddMath Spmnetic!™⚡️ analitikasi

AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 33 716 obunachidan iborat bo'lib, Taʼlim toifasida 5 671-o'rinni va Hindiston mintaqasida 12 519-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 33 716 obunachiga ega bo‘ldi.

15 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 635 ga, so‘nggi 24 soatda esa -19 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 12.65% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 5.51% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 4 265 marta ko‘riladi; birinchi sutkada odatda 1 859 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 12 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 16 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

33 716

Obunachilar

-1924 soatlar

+217 kunlar

+63530 kunlar

4 265

Post ko'rishlar

~ 1 85924 soatlar

~ 2 35448 soatlar

12.65%

Muloqot nisbati

~ 2

Kuniga postlar

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Postlar arxiv

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here are the answers for your reference ☺️

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1 Addmath Question a Day: Functions F4C1 Credits: Cikgu Noorul & Cikgu Zainab - Soalan Percubaan SPM Negeri 2024

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this competition will be for 5 days more only, so daftar ASAP...thankss

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Lol guys help our GOAT Jason to get an iPhone by forwarding the same link to more ppl 🔥 🔥

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Those who want devices to study can join this PTTI competition, U also have to send the link to others in order to increase your rank...

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https://contest.ptti.my/belajarbersamaptti?referralCode=ma80cy9&refSource=copy

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5 HARI LAGI BAKAL TAMAT! Peluang besar masih ada untuk menang iPad, Macbook dan iPhone 17 Pro! Hanya perlu sharekan link awak kepada kawan-kawan. Makin ramai kawan yang join, makin besar peluang awak untuk menang. Layari https://contest.ptti.my/belajarbersamaptti untuk sertai peraduan dan dapatkan link awak.

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There ya’ go 🙌🏻

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Just extra info, I also dk much about it..but y'all can research about it and learn more

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(e) When pp(x)=x, p(x) is a function such that p^-1(x)=p(x). Draw a ring around the function that has this property. f(x)=2x-1 , g(x)=3x+2, h(x)=1/x, x not equal to 0, j(x)=x^2 level: hard

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(d) Find hf(x) +gh(x), giving your answer in a single fraction in its simplest form.

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(a) j(-1), (b) find x when f(x) +g(x)=0, (c) gg(x), giving your answer in its simplest form.

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try 🤓

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Question 1: Functions & Quadratic Equations Given that f(x)=2x-3 and g(x)=x^2+4x+1. (a) find: (i) f^-1(x) [2 marks] (ii) gf(x) [2 marks] (b) solve the equation gf(x)=6. [3 marks] (c) find the range of values of k for which the equation g(x)=k has no real roots. [ 3 marks ]