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📈 Аналітичний огляд Telegram-каналу allcoding1

Канал allcoding1 (@allcoding1) у мовному сегменті Англійська є активним учасником. На даний момент спільнота об'єднує 22 601 підписників, посідаючи 8 831 місце в категорії Освіта та 19 534 місце у регіоні Індія.

📊 Показники аудиторії та динаміка

З моменту свого створення невідомо, проект продемонстрував стрімке зростання, зібравши аудиторію у 22 601 підписників.

За останніми даними від 10 червня, 2026, канал демонструє стабільну активність. Хоча за останні 30 днів спостерігається зміна кількості учасників на -430, а за останні 24 години на -7, загальне охоплення залишається високим.

  • Статус верифікації: Не верифікований
  • Рівень залученості (ER): Середній показник залученості аудиторії становить 5.78%. Протягом перших 24 годин після публікації контент зазвичай збирає 1.40% реакцій від загальної кількості підписників.
  • Охоплення публікацій: В середньому кожен допис отримує 1 307 переглядів. Протягом першої доби публікація в середньому набирає 317 переглядів.
  • Реакції та взаємодія: Аудиторія активно підтримує контент: середня кількість реакцій на один пост – 2.
  • Тематичні інтереси: Контент зосереджений навколо ключових тем, таких як dsa, stack, namaste, javascript, learning.

📝 Опис та контентна політика

Опис каналу не надано.

Завдяки високій частоті оновлень (останні дані отримано 11 червня, 2026), канал підтримує актуальність та високий рівень охоплення публікацій. Аналітика показує, що аудиторія активно взаємодіє з контентом, що робить його важливою точкою впливу в категорії Освіта.

22 601
Підписники
-724 години
-907 днів
-43030 день
Архів дописів
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) ** 2 start_section = end_section = None for idx, section in enumerate(sections): for row in section: if 'S' in row: start_section = idx if 'D' in row: end_section = idx other_sections = [i for i in range(total_sections) if i not in {start_section, end_section}] min_path = float('inf') for perm in itertools.permutations(other_sections): order = [start_section] + list(perm) + [end_section] rebuilt_grid = rebuild_grid(order, sections, size, block_size) min_path = min(min_path, shortest_path(rebuilt_grid, size)) return min_path if name == "main": print(main()) ALTERNATING STRING import java.util.Scanner; public class AlternatingStringProcessor { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String binaryString = scanner.nextLine(); int length = binaryString.length(); int[] values = new int[length]; for (int i = 0; i < length; i++) { values[i] = scanner.nextInt(); } int result = 0; int currentDigit = binaryString.charAt(0) - '0'; int lastValue = values[0]; for (int i = 1; i < length; i++) { int nextDigit = binaryString.charAt(i) - '0'; if (nextDigit == currentDigit) { result += Math.min(lastValue, values[i]); lastValue = Math.max(lastValue, values[i]); } else { currentDigit = nextDigit; lastValue = values[i]; } } System.out.println(result); } } TCS CodeVita @itjobsservices

target_idx += 1 sub_idx += 1 total_deletions = len(sub_str) - match_length return match_length, total_deletions def process_input(): inp = sys.stdin.read().splitlines() pos = 0 num_strings = int(inp[pos].strip()) pos += 1 Office rostering code #include <iostream> #include <vector> #include <set> #include <algorithm> using namespace std; int main() { int n, m, k, days = 1, activeCount = 0; cin >> n >> m; vector<set<int>> connections(n); for (int i = 0, u, v; i < m; ++i) { cin >> u >> v; connections[u].insert(v); connections[v].insert(u); } cin >> k; vector<bool> active(n, true); activeCount = n; while (activeCount < k) { vector<bool> nextState(n, false); for (int i = 0; i < n; ++i) { int neighborCount = 0; for (int neighbor : connections[i]) { neighborCount += active[neighbor]; } if (active[i] && neighborCount == 3) { nextState[i] = true; } else if (!active[i] && neighborCount < 3) { nextState[i] = true; } } active = nextState; activeCount += count(active.begin(), active.end(), true); ++days; } cout << days; return 0; } BUZZ DAY SALE #include <iostream> #include <vector> #include <algorithm> using namespace std; int main() { int n; cin >> n; vector<int> ids(n), costs(n); for (int i = 0; i < n; i++) cin >> ids[i]; for (int i = 0; i < n; i++) cin >> costs[i]; int budget; cin >> budget; int maxItems = 0, minCost = 0; for (int i = 0; i < n; i++) { int itemCost = costs[i]; int quantity = budget / itemCost; if (quantity > 0) { int currentItems = 0, currentCost = 0; for (int j = 0; j < n; j++) { if (i != j && ids[i] % ids[j] == 0) { currentItems += quantity; currentCost += costs[j] * quantity; } } if (currentItems > maxItems || (currentItems == maxItems && currentCost > minCost)) { maxItems = currentItems; minCost = currentCost; } } } cout << maxItems << " " << minCost << endl; return 0; } Arrange map code from collections import deque import itertools def shortest_path(grid, n): start, end = None, None for i in range(n): for j in range(n): if grid[i][j] == 'S': start = (i, j) elif grid[i][j] == 'D': end = (i, j) queue = deque([(start, 0)]) visited = {start} while queue: (x, y), distance = queue.popleft() if (x, y) == end: return distance for nx, ny in [(x+1, y), (x-1, y), (x, y+1), (x, y-1)]: if 0 <= nx < n and 0 <= ny < n and (nx, ny) not in visited and grid[nx][ny] != 'T': visited.add((nx, ny)) queue.append(((nx, ny), distance + 1)) return float('inf') def split_grid(grid, size, block): sections = [] for i in range(0, size, block): for j in range(0, size, block): block_section = [grid[x][j:j+block] for x in range(i, i+block)] sections.append(block_section) return sections def rebuild_grid(order, sections, size, block): full_grid = [["" for _ in range(size)] for _ in range(size)] num_blocks = size // block for index, section_index in enumerate(order): section = sections[section_index] row_offset = (index // num_blocks) * block col_offset = (index % num_blocks) * block for i in range(block): for j in range(block): full_grid[row_offset + i][col_offset + j] = section[i][j] return full_grid def main(): size, block_size = map(int, input().split()) original_grid = [list(input().strip()) for _ in range(size)] sections = split_grid(original_grid, size, block_size) total_sections = (size // block_size

"10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10001", "10010", "00001", "00100", "10001", "01010", "10101", "00000", "00001", "00000"}, {"10001", "11111", "11111", "11111", "11111", "10000", "11111", "10001", "11111", "11111", "10001", "11111", "10001", "10001", "01110", "10000", "11111", "10001", "11111", "00100", "11111", "00100", "11111", "10001", "11111", "11111"} }; vector code(26, ""); for (int row = 0; row < 9; row++) { for (int col = 0; col < 26; col++) { code[col] += A[row][col]; } } map mp; for (char ch = 'A'; ch <= 'Z'; ch++) { mp[code[ch - 'A']] = ch; } vector B; for (string s; cin >> s; B.push_back(s)); for (int L = 0, R = 0; R < (int)B[0].size(); R++) { int zeros = 0; for (int row = 0; row < 9; row++) { zeros += B[row][R] == '0'; } if (zeros == 9) { L = R + 1; } else if (R - L + 1 == 5) { string pl; for (int row = 0; row < 9; row++) { pl += B[row].substr(L, 5); } if (mp.count(pl)) { cout << mp[pl]; } L = R + 1; } } return 0; } Matrix rotation def rotate_layer(layer, pos, direction, odd_layer): n = len(layer) rotated_layer = [None] * n if direction == "clockwise": for i in range(n): rotated_layer[(i + pos) % n] = layer[i] else: for i in range(n): rotated_layer[(i - pos) % n] = layer[i] for i in range(n): if odd_layer: rotated_layer[i] = chr(((ord(rotated_layer[i]) - ord('A') - 1) % 26) + ord('A')) else: rotated_layer[i] = chr(((ord(rotated_layer[i]) - ord('A') + 1) % 26) + ord('A')) return rotated_layer def adjust_query(plan, row, col, size): layers = [] for layer in range(size // 2): current_layer = [] for j in range(col + layer, col + size - layer): current_layer.append(plan[row + layer][j]) for i in range(row + layer + 1, row + size - layer - 1): current_layer.append(plan[i][col + size - layer - 1]) for j in range(col + size - layer - 1, col + layer - 1, -1): current_layer.append(plan[row + size - layer - 1][j]) for i in range(row + size - layer - 2, row + layer, -1): current_layer.append(plan[i][col + layer]) layers.append(current_layer) for lidx, layer in enumerate(layers): odd_layer = (lidx + 1) % 2 == 1 direction = "counterclockwise" if odd_layer else "clockwise" pos = lidx + 1 rotated_layer = rotate_layer(layer, pos, direction, odd_layer) idx = 0 for j in range(col + lidx, col + size - lidx): plan[row + lidx][j] = rotated_layer[idx] idx += 1 for i in range(row + lidx + 1, row + size - lidx - 1): plan[i][col + size - lidx - 1] = rotated_layer[idx] idx += 1 for j in range(col + size - lidx - 1, col + lidx - 1, -1): plan[row + size - lidx - 1][j] = rotated_layer[idx] idx += 1 for i in range(row + size - lidx - 2, row + lidx, -1): plan[i][col + lidx] = rotated_layer[idx] idx += 1 def perform_rotation(n, plan, queries): for row, col, size in queries: adjust_query(plan, row, col, size) return ''.join(''.join(row) for row in plan) n = int(input()) plan = [list(input().strip()) for _ in range(n)] q = int(input()) queries = [tuple(map(int, input().split())) for _ in range(q)] result = perform_rotation(n, plan, queries) print(result, end="") HELP RITIKA import sys import math def get_max_prefix_length_and_deletions(sub_str, target_str, start_idx): sub_idx, target_idx, match_length = 0, start_idx, 0 while sub_idx < len(sub_str) and target_idx < len(target_str): if sub_str[sub_idx] == target_str[target_idx]: match_length += 1

Count press #include <iostream> #include <string> #include <vector> #include <unordered_map> using namespace std; int dp(string& s, vector<string>& v, unordered_map<string, int>& memo) { if (memo.count(s)) return memo[s]; int maxRemoval = 0; for (auto& x : v) { size_t pos = s.find(x); if (pos != string::npos) { string new_string = s.substr(0, pos) + s.substr(pos + x.size()); maxRemoval = max(maxRemoval, 1 + dp(new_string, v, memo)); } } return memo[s] = maxRemoval; } int main() { int n; cin >> n; vector<string> substrings(n); for (int i = 0; i < n; ++i) { cin >> substrings[i]; } string mainString; cin >> mainString; unordered_map<string, int> memo; cout << dp(mainString, substrings, memo); return 0; } FOLDER AREA #include <iostream> #include <cmath> #include <set> #include <iomanip> #include <vector> #include <utility> using namespace std; pair<double, double> reflectPoint(double px, double py, double x1, double y1, double x2, double y2) { double A = y2 - y1; double B = x1 - x2; double C = x2 * y1 - x1 * y2; double distance = (A * px + B * py + C) / sqrt(A * A + B * B); double reflectedX = px - 2 * distance * (A / sqrt(A * A + B * B)); double reflectedY = py - 2 * distance * (B / sqrt(A * A + B * B)); return {reflectedX, reflectedY}; } int main() { double area; cout << "Enter area of the square: "; cin >> area; double x1, y1, x2, y2; cout << "Enter the coordinates of the line (x1 y1 x2 y2): "; cin >> x1 >> y1 >> x2 >> y2; double side = sqrt(area); vector<pair<double, double>> corners = { {0, 0}, {0, side}, {side, side}, {side, 0} }; set<pair<double, double>> uniquePoints(corners.begin(), corners.end()); for (const auto& corner : corners) { auto [rx, ry] = reflectPoint(corner.first, corner.second, x1, y1, x2, y2); uniquePoints.insert({rx, ry}); } for (const auto& point : uniquePoints) { cout << fixed << setprecision(2) << point.first << " " << point.second << endl; } return 0; } Segment display #include <bits/stdc++.h> using namespace std; int main() { vector<vector<string>> A = { {"11111", "11111", "11111", "11111", "11111", "11111", "11111", "10001", "11111", "11111", "10001", "10000", "11111", "10001", "01110", "11111", "11111", "11111", "11111", "11111", "10001", "10001", "10001", "10001", "10001", "11111"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10010", "10000", "10101", "11001", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10100", "10000", "10101", "10101", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "01010", "10001", "00010"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "11000", "10000", "10101", "10011", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"11111", "11111", "10000", "10001", "11111", "11111", "10111", "11111", "00100", "10001", "11111", "10000", "10101", "10001", "10001", "11111", "10101", "11111", "11111", "00100", "10001", "10001", "10101", "00100", "11111", "00100"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10001", "11000", "00001", "00100", "10001", "10001", "10101", "00000", "00001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10011", "10100", "00001", "00100", "10001", "10001", "10101", "01010", "00001", "01000"}, {"10001", "10001", "10000", "10001", "10000", "10000",

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Count press #include <iostream> #include <string> #include <vector> #include <unordered_map> using namespace std; int dp(string& s, vector<string>& v, unordered_map<string, int>& memo) { if (memo.count(s)) return memo[s]; int maxRemoval = 0; for (auto& x : v) { size_t pos = s.find(x); if (pos != string::npos) { string new_string = s.substr(0, pos) + s.substr(pos + x.size()); maxRemoval = max(maxRemoval, 1 + dp(new_string, v, memo)); } } return memo[s] = maxRemoval; } int main() { int n; cin >> n; vector<string> substrings(n); for (int i = 0; i < n; ++i) { cin >> substrings[i]; } string mainString; cin >> mainString; unordered_map<string, int> memo; cout << dp(mainString, substrings, memo); return 0; } FOLDER AREA #include <iostream> #include <cmath> #include <set> #include <iomanip> #include <vector> #include <utility> using namespace std; pair<double, double> reflectPoint(double px, double py, double x1, double y1, double x2, double y2) { double A = y2 - y1; double B = x1 - x2; double C = x2 * y1 - x1 * y2; double distance = (A * px + B * py + C) / sqrt(A * A + B * B); double reflectedX = px - 2 * distance * (A / sqrt(A * A + B * B)); double reflectedY = py - 2 * distance * (B / sqrt(A * A + B * B)); return {reflectedX, reflectedY}; } int main() { double area; cout << "Enter area of the square: "; cin >> area; double x1, y1, x2, y2; cout << "Enter the coordinates of the line (x1 y1 x2 y2): "; cin >> x1 >> y1 >> x2 >> y2; double side = sqrt(area); vector<pair<double, double>> corners = { {0, 0}, {0, side}, {side, side}, {side, 0} }; set<pair<double, double>> uniquePoints(corners.begin(), corners.end()); for (const auto& corner : corners) { auto [rx, ry] = reflectPoint(corner.first, corner.second, x1, y1, x2, y2); uniquePoints.insert({rx, ry}); } for (const auto& point : uniquePoints) { cout << fixed << setprecision(2) << point.first << " " << point.second << endl; } return 0; } Segment display #include <bits/stdc++.h> using namespace std; int main() { vector<vector<string>> A = { {"11111", "11111", "11111", "11111", "11111", "11111", "11111", "10001", "11111", "11111", "10001", "10000", "11111", "10001", "01110", "11111", "11111", "11111", "11111", "11111", "10001", "10001", "10001", "10001", "10001", "11111"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10010", "10000", "10101", "11001", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10100", "10000", "10101", "10101", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "01010", "10001", "00010"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "11000", "10000", "10101", "10011", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"11111", "11111", "10000", "10001", "11111", "11111", "10111", "11111", "00100", "10001", "11111", "10000", "10101", "10001", "10001", "11111", "10101", "11111", "11111", "00100", "10001", "10001", "10101", "00100", "11111", "00100"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10001", "11000", "00001", "00100", "10001", "10001", "10101", "00000", "00001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10011", "10100", "00001", "00100", "10001", "10001", "10101", "01010", "00001", "01000"}, {"10001", "10001", "10000", "10001", "10000", "10000",

) ** 2     start_section = end_section = None     for idx, section in enumerate(sections):         for row in section:             if 'S' in row:                 start_section = idx             if 'D' in row:                 end_section = idx     other_sections = [i for i in range(total_sections) if i not in {start_section, end_section}]     min_path = float('inf')     for perm in itertools.permutations(other_sections):         order = [start_section] + list(perm) + [end_section]         rebuilt_grid = rebuild_grid(order, sections, size, block_size)         min_path = min(min_path, shortest_path(rebuilt_grid, size))     return min_path if name == "main":     print(main()) ALTERNATING STRING import java.util.Scanner; public class AlternatingStringProcessor {     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);                 String binaryString = scanner.nextLine();         int length = binaryString.length();         int[] values = new int[length];         for (int i = 0; i < length; i++) {             values[i] = scanner.nextInt();         }         int result = 0;         int currentDigit = binaryString.charAt(0) - '0';         int lastValue = values[0];         for (int i = 1; i < length; i++) {             int nextDigit = binaryString.charAt(i) - '0';             if (nextDigit == currentDigit) {                 result += Math.min(lastValue, values[i]);                 lastValue = Math.max(lastValue, values[i]);             } else {                 currentDigit = nextDigit;                 lastValue = values[i];             }         }         System.out.println(result);     } } TCS CodeVita @itjobsservices

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