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allcoding1

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📈 Analytical overview of Telegram channel allcoding1

Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 22 601 subscribers, ranking 8 831 in the Education category and 19 534 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 22 601 subscribers.

According to the latest data from 10 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -430 over the last 30 days and by -7 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 5.78%. Within the first 24 hours after publication, content typically collects 1.40% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 307 views. Within the first day, a publication typically gains 317 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
  • Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 11 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

22 601
Subscribers
-724 hours
-907 days
-43030 days
Posts Archive
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) ** 2 start_section = end_section = None for idx, section in enumerate(sections): for row in section: if 'S' in row: start_section = idx if 'D' in row: end_section = idx other_sections = [i for i in range(total_sections) if i not in {start_section, end_section}] min_path = float('inf') for perm in itertools.permutations(other_sections): order = [start_section] + list(perm) + [end_section] rebuilt_grid = rebuild_grid(order, sections, size, block_size) min_path = min(min_path, shortest_path(rebuilt_grid, size)) return min_path if name == "main": print(main()) ALTERNATING STRING import java.util.Scanner; public class AlternatingStringProcessor { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String binaryString = scanner.nextLine(); int length = binaryString.length(); int[] values = new int[length]; for (int i = 0; i < length; i++) { values[i] = scanner.nextInt(); } int result = 0; int currentDigit = binaryString.charAt(0) - '0'; int lastValue = values[0]; for (int i = 1; i < length; i++) { int nextDigit = binaryString.charAt(i) - '0'; if (nextDigit == currentDigit) { result += Math.min(lastValue, values[i]); lastValue = Math.max(lastValue, values[i]); } else { currentDigit = nextDigit; lastValue = values[i]; } } System.out.println(result); } } TCS CodeVita @itjobsservices

target_idx += 1 sub_idx += 1 total_deletions = len(sub_str) - match_length return match_length, total_deletions def process_input(): inp = sys.stdin.read().splitlines() pos = 0 num_strings = int(inp[pos].strip()) pos += 1 Office rostering code #include <iostream> #include <vector> #include <set> #include <algorithm> using namespace std; int main() { int n, m, k, days = 1, activeCount = 0; cin >> n >> m; vector<set<int>> connections(n); for (int i = 0, u, v; i < m; ++i) { cin >> u >> v; connections[u].insert(v); connections[v].insert(u); } cin >> k; vector<bool> active(n, true); activeCount = n; while (activeCount < k) { vector<bool> nextState(n, false); for (int i = 0; i < n; ++i) { int neighborCount = 0; for (int neighbor : connections[i]) { neighborCount += active[neighbor]; } if (active[i] && neighborCount == 3) { nextState[i] = true; } else if (!active[i] && neighborCount < 3) { nextState[i] = true; } } active = nextState; activeCount += count(active.begin(), active.end(), true); ++days; } cout << days; return 0; } BUZZ DAY SALE #include <iostream> #include <vector> #include <algorithm> using namespace std; int main() { int n; cin >> n; vector<int> ids(n), costs(n); for (int i = 0; i < n; i++) cin >> ids[i]; for (int i = 0; i < n; i++) cin >> costs[i]; int budget; cin >> budget; int maxItems = 0, minCost = 0; for (int i = 0; i < n; i++) { int itemCost = costs[i]; int quantity = budget / itemCost; if (quantity > 0) { int currentItems = 0, currentCost = 0; for (int j = 0; j < n; j++) { if (i != j && ids[i] % ids[j] == 0) { currentItems += quantity; currentCost += costs[j] * quantity; } } if (currentItems > maxItems || (currentItems == maxItems && currentCost > minCost)) { maxItems = currentItems; minCost = currentCost; } } } cout << maxItems << " " << minCost << endl; return 0; } Arrange map code from collections import deque import itertools def shortest_path(grid, n): start, end = None, None for i in range(n): for j in range(n): if grid[i][j] == 'S': start = (i, j) elif grid[i][j] == 'D': end = (i, j) queue = deque([(start, 0)]) visited = {start} while queue: (x, y), distance = queue.popleft() if (x, y) == end: return distance for nx, ny in [(x+1, y), (x-1, y), (x, y+1), (x, y-1)]: if 0 <= nx < n and 0 <= ny < n and (nx, ny) not in visited and grid[nx][ny] != 'T': visited.add((nx, ny)) queue.append(((nx, ny), distance + 1)) return float('inf') def split_grid(grid, size, block): sections = [] for i in range(0, size, block): for j in range(0, size, block): block_section = [grid[x][j:j+block] for x in range(i, i+block)] sections.append(block_section) return sections def rebuild_grid(order, sections, size, block): full_grid = [["" for _ in range(size)] for _ in range(size)] num_blocks = size // block for index, section_index in enumerate(order): section = sections[section_index] row_offset = (index // num_blocks) * block col_offset = (index % num_blocks) * block for i in range(block): for j in range(block): full_grid[row_offset + i][col_offset + j] = section[i][j] return full_grid def main(): size, block_size = map(int, input().split()) original_grid = [list(input().strip()) for _ in range(size)] sections = split_grid(original_grid, size, block_size) total_sections = (size // block_size

"10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10001", "10010", "00001", "00100", "10001", "01010", "10101", "00000", "00001", "00000"}, {"10001", "11111", "11111", "11111", "11111", "10000", "11111", "10001", "11111", "11111", "10001", "11111", "10001", "10001", "01110", "10000", "11111", "10001", "11111", "00100", "11111", "00100", "11111", "10001", "11111", "11111"} }; vector code(26, ""); for (int row = 0; row < 9; row++) { for (int col = 0; col < 26; col++) { code[col] += A[row][col]; } } map mp; for (char ch = 'A'; ch <= 'Z'; ch++) { mp[code[ch - 'A']] = ch; } vector B; for (string s; cin >> s; B.push_back(s)); for (int L = 0, R = 0; R < (int)B[0].size(); R++) { int zeros = 0; for (int row = 0; row < 9; row++) { zeros += B[row][R] == '0'; } if (zeros == 9) { L = R + 1; } else if (R - L + 1 == 5) { string pl; for (int row = 0; row < 9; row++) { pl += B[row].substr(L, 5); } if (mp.count(pl)) { cout << mp[pl]; } L = R + 1; } } return 0; } Matrix rotation def rotate_layer(layer, pos, direction, odd_layer): n = len(layer) rotated_layer = [None] * n if direction == "clockwise": for i in range(n): rotated_layer[(i + pos) % n] = layer[i] else: for i in range(n): rotated_layer[(i - pos) % n] = layer[i] for i in range(n): if odd_layer: rotated_layer[i] = chr(((ord(rotated_layer[i]) - ord('A') - 1) % 26) + ord('A')) else: rotated_layer[i] = chr(((ord(rotated_layer[i]) - ord('A') + 1) % 26) + ord('A')) return rotated_layer def adjust_query(plan, row, col, size): layers = [] for layer in range(size // 2): current_layer = [] for j in range(col + layer, col + size - layer): current_layer.append(plan[row + layer][j]) for i in range(row + layer + 1, row + size - layer - 1): current_layer.append(plan[i][col + size - layer - 1]) for j in range(col + size - layer - 1, col + layer - 1, -1): current_layer.append(plan[row + size - layer - 1][j]) for i in range(row + size - layer - 2, row + layer, -1): current_layer.append(plan[i][col + layer]) layers.append(current_layer) for lidx, layer in enumerate(layers): odd_layer = (lidx + 1) % 2 == 1 direction = "counterclockwise" if odd_layer else "clockwise" pos = lidx + 1 rotated_layer = rotate_layer(layer, pos, direction, odd_layer) idx = 0 for j in range(col + lidx, col + size - lidx): plan[row + lidx][j] = rotated_layer[idx] idx += 1 for i in range(row + lidx + 1, row + size - lidx - 1): plan[i][col + size - lidx - 1] = rotated_layer[idx] idx += 1 for j in range(col + size - lidx - 1, col + lidx - 1, -1): plan[row + size - lidx - 1][j] = rotated_layer[idx] idx += 1 for i in range(row + size - lidx - 2, row + lidx, -1): plan[i][col + lidx] = rotated_layer[idx] idx += 1 def perform_rotation(n, plan, queries): for row, col, size in queries: adjust_query(plan, row, col, size) return ''.join(''.join(row) for row in plan) n = int(input()) plan = [list(input().strip()) for _ in range(n)] q = int(input()) queries = [tuple(map(int, input().split())) for _ in range(q)] result = perform_rotation(n, plan, queries) print(result, end="") HELP RITIKA import sys import math def get_max_prefix_length_and_deletions(sub_str, target_str, start_idx): sub_idx, target_idx, match_length = 0, start_idx, 0 while sub_idx < len(sub_str) and target_idx < len(target_str): if sub_str[sub_idx] == target_str[target_idx]: match_length += 1

Count press #include <iostream> #include <string> #include <vector> #include <unordered_map> using namespace std; int dp(string& s, vector<string>& v, unordered_map<string, int>& memo) { if (memo.count(s)) return memo[s]; int maxRemoval = 0; for (auto& x : v) { size_t pos = s.find(x); if (pos != string::npos) { string new_string = s.substr(0, pos) + s.substr(pos + x.size()); maxRemoval = max(maxRemoval, 1 + dp(new_string, v, memo)); } } return memo[s] = maxRemoval; } int main() { int n; cin >> n; vector<string> substrings(n); for (int i = 0; i < n; ++i) { cin >> substrings[i]; } string mainString; cin >> mainString; unordered_map<string, int> memo; cout << dp(mainString, substrings, memo); return 0; } FOLDER AREA #include <iostream> #include <cmath> #include <set> #include <iomanip> #include <vector> #include <utility> using namespace std; pair<double, double> reflectPoint(double px, double py, double x1, double y1, double x2, double y2) { double A = y2 - y1; double B = x1 - x2; double C = x2 * y1 - x1 * y2; double distance = (A * px + B * py + C) / sqrt(A * A + B * B); double reflectedX = px - 2 * distance * (A / sqrt(A * A + B * B)); double reflectedY = py - 2 * distance * (B / sqrt(A * A + B * B)); return {reflectedX, reflectedY}; } int main() { double area; cout << "Enter area of the square: "; cin >> area; double x1, y1, x2, y2; cout << "Enter the coordinates of the line (x1 y1 x2 y2): "; cin >> x1 >> y1 >> x2 >> y2; double side = sqrt(area); vector<pair<double, double>> corners = { {0, 0}, {0, side}, {side, side}, {side, 0} }; set<pair<double, double>> uniquePoints(corners.begin(), corners.end()); for (const auto& corner : corners) { auto [rx, ry] = reflectPoint(corner.first, corner.second, x1, y1, x2, y2); uniquePoints.insert({rx, ry}); } for (const auto& point : uniquePoints) { cout << fixed << setprecision(2) << point.first << " " << point.second << endl; } return 0; } Segment display #include <bits/stdc++.h> using namespace std; int main() { vector<vector<string>> A = { {"11111", "11111", "11111", "11111", "11111", "11111", "11111", "10001", "11111", "11111", "10001", "10000", "11111", "10001", "01110", "11111", "11111", "11111", "11111", "11111", "10001", "10001", "10001", "10001", "10001", "11111"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10010", "10000", "10101", "11001", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10100", "10000", "10101", "10101", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "01010", "10001", "00010"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "11000", "10000", "10101", "10011", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"11111", "11111", "10000", "10001", "11111", "11111", "10111", "11111", "00100", "10001", "11111", "10000", "10101", "10001", "10001", "11111", "10101", "11111", "11111", "00100", "10001", "10001", "10101", "00100", "11111", "00100"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10001", "11000", "00001", "00100", "10001", "10001", "10101", "00000", "00001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10011", "10100", "00001", "00100", "10001", "10001", "10101", "01010", "00001", "01000"}, {"10001", "10001", "10000", "10001", "10000", "10000",

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Count press #include <iostream> #include <string> #include <vector> #include <unordered_map> using namespace std; int dp(string& s, vector<string>& v, unordered_map<string, int>& memo) { if (memo.count(s)) return memo[s]; int maxRemoval = 0; for (auto& x : v) { size_t pos = s.find(x); if (pos != string::npos) { string new_string = s.substr(0, pos) + s.substr(pos + x.size()); maxRemoval = max(maxRemoval, 1 + dp(new_string, v, memo)); } } return memo[s] = maxRemoval; } int main() { int n; cin >> n; vector<string> substrings(n); for (int i = 0; i < n; ++i) { cin >> substrings[i]; } string mainString; cin >> mainString; unordered_map<string, int> memo; cout << dp(mainString, substrings, memo); return 0; } FOLDER AREA #include <iostream> #include <cmath> #include <set> #include <iomanip> #include <vector> #include <utility> using namespace std; pair<double, double> reflectPoint(double px, double py, double x1, double y1, double x2, double y2) { double A = y2 - y1; double B = x1 - x2; double C = x2 * y1 - x1 * y2; double distance = (A * px + B * py + C) / sqrt(A * A + B * B); double reflectedX = px - 2 * distance * (A / sqrt(A * A + B * B)); double reflectedY = py - 2 * distance * (B / sqrt(A * A + B * B)); return {reflectedX, reflectedY}; } int main() { double area; cout << "Enter area of the square: "; cin >> area; double x1, y1, x2, y2; cout << "Enter the coordinates of the line (x1 y1 x2 y2): "; cin >> x1 >> y1 >> x2 >> y2; double side = sqrt(area); vector<pair<double, double>> corners = { {0, 0}, {0, side}, {side, side}, {side, 0} }; set<pair<double, double>> uniquePoints(corners.begin(), corners.end()); for (const auto& corner : corners) { auto [rx, ry] = reflectPoint(corner.first, corner.second, x1, y1, x2, y2); uniquePoints.insert({rx, ry}); } for (const auto& point : uniquePoints) { cout << fixed << setprecision(2) << point.first << " " << point.second << endl; } return 0; } Segment display #include <bits/stdc++.h> using namespace std; int main() { vector<vector<string>> A = { {"11111", "11111", "11111", "11111", "11111", "11111", "11111", "10001", "11111", "11111", "10001", "10000", "11111", "10001", "01110", "11111", "11111", "11111", "11111", "11111", "10001", "10001", "10001", "10001", "10001", "11111"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10010", "10000", "10101", "11001", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10100", "10000", "10101", "10101", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "01010", "10001", "00010"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "11000", "10000", "10101", "10011", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"11111", "11111", "10000", "10001", "11111", "11111", "10111", "11111", "00100", "10001", "11111", "10000", "10101", "10001", "10001", "11111", "10101", "11111", "11111", "00100", "10001", "10001", "10101", "00100", "11111", "00100"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10001", "11000", "00001", "00100", "10001", "10001", "10101", "00000", "00001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10011", "10100", "00001", "00100", "10001", "10001", "10101", "01010", "00001", "01000"}, {"10001", "10001", "10000", "10001", "10000", "10000",

) ** 2     start_section = end_section = None     for idx, section in enumerate(sections):         for row in section:             if 'S' in row:                 start_section = idx             if 'D' in row:                 end_section = idx     other_sections = [i for i in range(total_sections) if i not in {start_section, end_section}]     min_path = float('inf')     for perm in itertools.permutations(other_sections):         order = [start_section] + list(perm) + [end_section]         rebuilt_grid = rebuild_grid(order, sections, size, block_size)         min_path = min(min_path, shortest_path(rebuilt_grid, size))     return min_path if name == "main":     print(main()) ALTERNATING STRING import java.util.Scanner; public class AlternatingStringProcessor {     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);                 String binaryString = scanner.nextLine();         int length = binaryString.length();         int[] values = new int[length];         for (int i = 0; i < length; i++) {             values[i] = scanner.nextInt();         }         int result = 0;         int currentDigit = binaryString.charAt(0) - '0';         int lastValue = values[0];         for (int i = 1; i < length; i++) {             int nextDigit = binaryString.charAt(i) - '0';             if (nextDigit == currentDigit) {                 result += Math.min(lastValue, values[i]);                 lastValue = Math.max(lastValue, values[i]);             } else {                 currentDigit = nextDigit;                 lastValue = values[i];             }         }         System.out.println(result);     } } TCS CodeVita @itjobsservices

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