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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 601 obunachidan iborat bo'lib, Taʼlim toifasida 8 831-o'rinni va Hindiston mintaqasida 19 534-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 22 601 obunachiga ega bo‘ldi.

10 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -430 ga, so‘nggi 24 soatda esa -7 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 5.78% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.40% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 307 marta ko‘riladi; birinchi sutkada odatda 317 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 11 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

22 601
Obunachilar
-724 soatlar
-907 kunlar
-43030 kunlar
Postlar arxiv
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) ** 2 start_section = end_section = None for idx, section in enumerate(sections): for row in section: if 'S' in row: start_section = idx if 'D' in row: end_section = idx other_sections = [i for i in range(total_sections) if i not in {start_section, end_section}] min_path = float('inf') for perm in itertools.permutations(other_sections): order = [start_section] + list(perm) + [end_section] rebuilt_grid = rebuild_grid(order, sections, size, block_size) min_path = min(min_path, shortest_path(rebuilt_grid, size)) return min_path if name == "main": print(main()) ALTERNATING STRING import java.util.Scanner; public class AlternatingStringProcessor { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String binaryString = scanner.nextLine(); int length = binaryString.length(); int[] values = new int[length]; for (int i = 0; i < length; i++) { values[i] = scanner.nextInt(); } int result = 0; int currentDigit = binaryString.charAt(0) - '0'; int lastValue = values[0]; for (int i = 1; i < length; i++) { int nextDigit = binaryString.charAt(i) - '0'; if (nextDigit == currentDigit) { result += Math.min(lastValue, values[i]); lastValue = Math.max(lastValue, values[i]); } else { currentDigit = nextDigit; lastValue = values[i]; } } System.out.println(result); } } TCS CodeVita @itjobsservices

target_idx += 1 sub_idx += 1 total_deletions = len(sub_str) - match_length return match_length, total_deletions def process_input(): inp = sys.stdin.read().splitlines() pos = 0 num_strings = int(inp[pos].strip()) pos += 1 Office rostering code #include <iostream> #include <vector> #include <set> #include <algorithm> using namespace std; int main() { int n, m, k, days = 1, activeCount = 0; cin >> n >> m; vector<set<int>> connections(n); for (int i = 0, u, v; i < m; ++i) { cin >> u >> v; connections[u].insert(v); connections[v].insert(u); } cin >> k; vector<bool> active(n, true); activeCount = n; while (activeCount < k) { vector<bool> nextState(n, false); for (int i = 0; i < n; ++i) { int neighborCount = 0; for (int neighbor : connections[i]) { neighborCount += active[neighbor]; } if (active[i] && neighborCount == 3) { nextState[i] = true; } else if (!active[i] && neighborCount < 3) { nextState[i] = true; } } active = nextState; activeCount += count(active.begin(), active.end(), true); ++days; } cout << days; return 0; } BUZZ DAY SALE #include <iostream> #include <vector> #include <algorithm> using namespace std; int main() { int n; cin >> n; vector<int> ids(n), costs(n); for (int i = 0; i < n; i++) cin >> ids[i]; for (int i = 0; i < n; i++) cin >> costs[i]; int budget; cin >> budget; int maxItems = 0, minCost = 0; for (int i = 0; i < n; i++) { int itemCost = costs[i]; int quantity = budget / itemCost; if (quantity > 0) { int currentItems = 0, currentCost = 0; for (int j = 0; j < n; j++) { if (i != j && ids[i] % ids[j] == 0) { currentItems += quantity; currentCost += costs[j] * quantity; } } if (currentItems > maxItems || (currentItems == maxItems && currentCost > minCost)) { maxItems = currentItems; minCost = currentCost; } } } cout << maxItems << " " << minCost << endl; return 0; } Arrange map code from collections import deque import itertools def shortest_path(grid, n): start, end = None, None for i in range(n): for j in range(n): if grid[i][j] == 'S': start = (i, j) elif grid[i][j] == 'D': end = (i, j) queue = deque([(start, 0)]) visited = {start} while queue: (x, y), distance = queue.popleft() if (x, y) == end: return distance for nx, ny in [(x+1, y), (x-1, y), (x, y+1), (x, y-1)]: if 0 <= nx < n and 0 <= ny < n and (nx, ny) not in visited and grid[nx][ny] != 'T': visited.add((nx, ny)) queue.append(((nx, ny), distance + 1)) return float('inf') def split_grid(grid, size, block): sections = [] for i in range(0, size, block): for j in range(0, size, block): block_section = [grid[x][j:j+block] for x in range(i, i+block)] sections.append(block_section) return sections def rebuild_grid(order, sections, size, block): full_grid = [["" for _ in range(size)] for _ in range(size)] num_blocks = size // block for index, section_index in enumerate(order): section = sections[section_index] row_offset = (index // num_blocks) * block col_offset = (index % num_blocks) * block for i in range(block): for j in range(block): full_grid[row_offset + i][col_offset + j] = section[i][j] return full_grid def main(): size, block_size = map(int, input().split()) original_grid = [list(input().strip()) for _ in range(size)] sections = split_grid(original_grid, size, block_size) total_sections = (size // block_size

"10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10001", "10010", "00001", "00100", "10001", "01010", "10101", "00000", "00001", "00000"}, {"10001", "11111", "11111", "11111", "11111", "10000", "11111", "10001", "11111", "11111", "10001", "11111", "10001", "10001", "01110", "10000", "11111", "10001", "11111", "00100", "11111", "00100", "11111", "10001", "11111", "11111"} }; vector code(26, ""); for (int row = 0; row < 9; row++) { for (int col = 0; col < 26; col++) { code[col] += A[row][col]; } } map mp; for (char ch = 'A'; ch <= 'Z'; ch++) { mp[code[ch - 'A']] = ch; } vector B; for (string s; cin >> s; B.push_back(s)); for (int L = 0, R = 0; R < (int)B[0].size(); R++) { int zeros = 0; for (int row = 0; row < 9; row++) { zeros += B[row][R] == '0'; } if (zeros == 9) { L = R + 1; } else if (R - L + 1 == 5) { string pl; for (int row = 0; row < 9; row++) { pl += B[row].substr(L, 5); } if (mp.count(pl)) { cout << mp[pl]; } L = R + 1; } } return 0; } Matrix rotation def rotate_layer(layer, pos, direction, odd_layer): n = len(layer) rotated_layer = [None] * n if direction == "clockwise": for i in range(n): rotated_layer[(i + pos) % n] = layer[i] else: for i in range(n): rotated_layer[(i - pos) % n] = layer[i] for i in range(n): if odd_layer: rotated_layer[i] = chr(((ord(rotated_layer[i]) - ord('A') - 1) % 26) + ord('A')) else: rotated_layer[i] = chr(((ord(rotated_layer[i]) - ord('A') + 1) % 26) + ord('A')) return rotated_layer def adjust_query(plan, row, col, size): layers = [] for layer in range(size // 2): current_layer = [] for j in range(col + layer, col + size - layer): current_layer.append(plan[row + layer][j]) for i in range(row + layer + 1, row + size - layer - 1): current_layer.append(plan[i][col + size - layer - 1]) for j in range(col + size - layer - 1, col + layer - 1, -1): current_layer.append(plan[row + size - layer - 1][j]) for i in range(row + size - layer - 2, row + layer, -1): current_layer.append(plan[i][col + layer]) layers.append(current_layer) for lidx, layer in enumerate(layers): odd_layer = (lidx + 1) % 2 == 1 direction = "counterclockwise" if odd_layer else "clockwise" pos = lidx + 1 rotated_layer = rotate_layer(layer, pos, direction, odd_layer) idx = 0 for j in range(col + lidx, col + size - lidx): plan[row + lidx][j] = rotated_layer[idx] idx += 1 for i in range(row + lidx + 1, row + size - lidx - 1): plan[i][col + size - lidx - 1] = rotated_layer[idx] idx += 1 for j in range(col + size - lidx - 1, col + lidx - 1, -1): plan[row + size - lidx - 1][j] = rotated_layer[idx] idx += 1 for i in range(row + size - lidx - 2, row + lidx, -1): plan[i][col + lidx] = rotated_layer[idx] idx += 1 def perform_rotation(n, plan, queries): for row, col, size in queries: adjust_query(plan, row, col, size) return ''.join(''.join(row) for row in plan) n = int(input()) plan = [list(input().strip()) for _ in range(n)] q = int(input()) queries = [tuple(map(int, input().split())) for _ in range(q)] result = perform_rotation(n, plan, queries) print(result, end="") HELP RITIKA import sys import math def get_max_prefix_length_and_deletions(sub_str, target_str, start_idx): sub_idx, target_idx, match_length = 0, start_idx, 0 while sub_idx < len(sub_str) and target_idx < len(target_str): if sub_str[sub_idx] == target_str[target_idx]: match_length += 1

Count press #include <iostream> #include <string> #include <vector> #include <unordered_map> using namespace std; int dp(string& s, vector<string>& v, unordered_map<string, int>& memo) { if (memo.count(s)) return memo[s]; int maxRemoval = 0; for (auto& x : v) { size_t pos = s.find(x); if (pos != string::npos) { string new_string = s.substr(0, pos) + s.substr(pos + x.size()); maxRemoval = max(maxRemoval, 1 + dp(new_string, v, memo)); } } return memo[s] = maxRemoval; } int main() { int n; cin >> n; vector<string> substrings(n); for (int i = 0; i < n; ++i) { cin >> substrings[i]; } string mainString; cin >> mainString; unordered_map<string, int> memo; cout << dp(mainString, substrings, memo); return 0; } FOLDER AREA #include <iostream> #include <cmath> #include <set> #include <iomanip> #include <vector> #include <utility> using namespace std; pair<double, double> reflectPoint(double px, double py, double x1, double y1, double x2, double y2) { double A = y2 - y1; double B = x1 - x2; double C = x2 * y1 - x1 * y2; double distance = (A * px + B * py + C) / sqrt(A * A + B * B); double reflectedX = px - 2 * distance * (A / sqrt(A * A + B * B)); double reflectedY = py - 2 * distance * (B / sqrt(A * A + B * B)); return {reflectedX, reflectedY}; } int main() { double area; cout << "Enter area of the square: "; cin >> area; double x1, y1, x2, y2; cout << "Enter the coordinates of the line (x1 y1 x2 y2): "; cin >> x1 >> y1 >> x2 >> y2; double side = sqrt(area); vector<pair<double, double>> corners = { {0, 0}, {0, side}, {side, side}, {side, 0} }; set<pair<double, double>> uniquePoints(corners.begin(), corners.end()); for (const auto& corner : corners) { auto [rx, ry] = reflectPoint(corner.first, corner.second, x1, y1, x2, y2); uniquePoints.insert({rx, ry}); } for (const auto& point : uniquePoints) { cout << fixed << setprecision(2) << point.first << " " << point.second << endl; } return 0; } Segment display #include <bits/stdc++.h> using namespace std; int main() { vector<vector<string>> A = { {"11111", "11111", "11111", "11111", "11111", "11111", "11111", "10001", "11111", "11111", "10001", "10000", "11111", "10001", "01110", "11111", "11111", "11111", "11111", "11111", "10001", "10001", "10001", "10001", "10001", "11111"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10010", "10000", "10101", "11001", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10100", "10000", "10101", "10101", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "01010", "10001", "00010"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "11000", "10000", "10101", "10011", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"11111", "11111", "10000", "10001", "11111", "11111", "10111", "11111", "00100", "10001", "11111", "10000", "10101", "10001", "10001", "11111", "10101", "11111", "11111", "00100", "10001", "10001", "10101", "00100", "11111", "00100"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10001", "11000", "00001", "00100", "10001", "10001", "10101", "00000", "00001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10011", "10100", "00001", "00100", "10001", "10001", "10101", "01010", "00001", "01000"}, {"10001", "10001", "10000", "10001", "10000", "10000",

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Count press #include <iostream> #include <string> #include <vector> #include <unordered_map> using namespace std; int dp(string& s, vector<string>& v, unordered_map<string, int>& memo) { if (memo.count(s)) return memo[s]; int maxRemoval = 0; for (auto& x : v) { size_t pos = s.find(x); if (pos != string::npos) { string new_string = s.substr(0, pos) + s.substr(pos + x.size()); maxRemoval = max(maxRemoval, 1 + dp(new_string, v, memo)); } } return memo[s] = maxRemoval; } int main() { int n; cin >> n; vector<string> substrings(n); for (int i = 0; i < n; ++i) { cin >> substrings[i]; } string mainString; cin >> mainString; unordered_map<string, int> memo; cout << dp(mainString, substrings, memo); return 0; } FOLDER AREA #include <iostream> #include <cmath> #include <set> #include <iomanip> #include <vector> #include <utility> using namespace std; pair<double, double> reflectPoint(double px, double py, double x1, double y1, double x2, double y2) { double A = y2 - y1; double B = x1 - x2; double C = x2 * y1 - x1 * y2; double distance = (A * px + B * py + C) / sqrt(A * A + B * B); double reflectedX = px - 2 * distance * (A / sqrt(A * A + B * B)); double reflectedY = py - 2 * distance * (B / sqrt(A * A + B * B)); return {reflectedX, reflectedY}; } int main() { double area; cout << "Enter area of the square: "; cin >> area; double x1, y1, x2, y2; cout << "Enter the coordinates of the line (x1 y1 x2 y2): "; cin >> x1 >> y1 >> x2 >> y2; double side = sqrt(area); vector<pair<double, double>> corners = { {0, 0}, {0, side}, {side, side}, {side, 0} }; set<pair<double, double>> uniquePoints(corners.begin(), corners.end()); for (const auto& corner : corners) { auto [rx, ry] = reflectPoint(corner.first, corner.second, x1, y1, x2, y2); uniquePoints.insert({rx, ry}); } for (const auto& point : uniquePoints) { cout << fixed << setprecision(2) << point.first << " " << point.second << endl; } return 0; } Segment display #include <bits/stdc++.h> using namespace std; int main() { vector<vector<string>> A = { {"11111", "11111", "11111", "11111", "11111", "11111", "11111", "10001", "11111", "11111", "10001", "10000", "11111", "10001", "01110", "11111", "11111", "11111", "11111", "11111", "10001", "10001", "10001", "10001", "10001", "11111"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10010", "10000", "10101", "11001", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10100", "10000", "10101", "10101", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "01010", "10001", "00010"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "11000", "10000", "10101", "10011", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"11111", "11111", "10000", "10001", "11111", "11111", "10111", "11111", "00100", "10001", "11111", "10000", "10101", "10001", "10001", "11111", "10101", "11111", "11111", "00100", "10001", "10001", "10101", "00100", "11111", "00100"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10001", "11000", "00001", "00100", "10001", "10001", "10101", "00000", "00001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10011", "10100", "00001", "00100", "10001", "10001", "10101", "01010", "00001", "01000"}, {"10001", "10001", "10000", "10001", "10000", "10000",

) ** 2     start_section = end_section = None     for idx, section in enumerate(sections):         for row in section:             if 'S' in row:                 start_section = idx             if 'D' in row:                 end_section = idx     other_sections = [i for i in range(total_sections) if i not in {start_section, end_section}]     min_path = float('inf')     for perm in itertools.permutations(other_sections):         order = [start_section] + list(perm) + [end_section]         rebuilt_grid = rebuild_grid(order, sections, size, block_size)         min_path = min(min_path, shortest_path(rebuilt_grid, size))     return min_path if name == "main":     print(main()) ALTERNATING STRING import java.util.Scanner; public class AlternatingStringProcessor {     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);                 String binaryString = scanner.nextLine();         int length = binaryString.length();         int[] values = new int[length];         for (int i = 0; i < length; i++) {             values[i] = scanner.nextInt();         }         int result = 0;         int currentDigit = binaryString.charAt(0) - '0';         int lastValue = values[0];         for (int i = 1; i < length; i++) {             int nextDigit = binaryString.charAt(i) - '0';             if (nextDigit == currentDigit) {                 result += Math.min(lastValue, values[i]);                 lastValue = Math.max(lastValue, values[i]);             } else {                 currentDigit = nextDigit;                 lastValue = values[i];             }         }         System.out.println(result);     } } TCS CodeVita @itjobsservices

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