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allcoding1

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📈 نظرة تحليلية على قناة تيليجرام allcoding1

تُعد قناة allcoding1 (@allcoding1) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 22 601 مشتركاً، محتلاً المرتبة 8 831 في فئة التعليم والمرتبة 19 534 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 22 601 مشتركاً.

بحسب آخر البيانات بتاريخ 10 يونيو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -430، وفي آخر 24 ساعة بمقدار -7، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 5.78‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 1.40‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 1 307 مشاهدة. وخلال اليوم الأول يجمع عادةً 317 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 2.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل dsa, stack, namaste, javascript, learning.

📝 الوصف وسياسة المحتوى

وصف القناة غير متوفر.

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 11 يونيو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التعليم.

22 601
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-907 أيام
-43030 أيام
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) ** 2 start_section = end_section = None for idx, section in enumerate(sections): for row in section: if 'S' in row: start_section = idx if 'D' in row: end_section = idx other_sections = [i for i in range(total_sections) if i not in {start_section, end_section}] min_path = float('inf') for perm in itertools.permutations(other_sections): order = [start_section] + list(perm) + [end_section] rebuilt_grid = rebuild_grid(order, sections, size, block_size) min_path = min(min_path, shortest_path(rebuilt_grid, size)) return min_path if name == "main": print(main()) ALTERNATING STRING import java.util.Scanner; public class AlternatingStringProcessor { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String binaryString = scanner.nextLine(); int length = binaryString.length(); int[] values = new int[length]; for (int i = 0; i < length; i++) { values[i] = scanner.nextInt(); } int result = 0; int currentDigit = binaryString.charAt(0) - '0'; int lastValue = values[0]; for (int i = 1; i < length; i++) { int nextDigit = binaryString.charAt(i) - '0'; if (nextDigit == currentDigit) { result += Math.min(lastValue, values[i]); lastValue = Math.max(lastValue, values[i]); } else { currentDigit = nextDigit; lastValue = values[i]; } } System.out.println(result); } } TCS CodeVita @itjobsservices

target_idx += 1 sub_idx += 1 total_deletions = len(sub_str) - match_length return match_length, total_deletions def process_input(): inp = sys.stdin.read().splitlines() pos = 0 num_strings = int(inp[pos].strip()) pos += 1 Office rostering code #include <iostream> #include <vector> #include <set> #include <algorithm> using namespace std; int main() { int n, m, k, days = 1, activeCount = 0; cin >> n >> m; vector<set<int>> connections(n); for (int i = 0, u, v; i < m; ++i) { cin >> u >> v; connections[u].insert(v); connections[v].insert(u); } cin >> k; vector<bool> active(n, true); activeCount = n; while (activeCount < k) { vector<bool> nextState(n, false); for (int i = 0; i < n; ++i) { int neighborCount = 0; for (int neighbor : connections[i]) { neighborCount += active[neighbor]; } if (active[i] && neighborCount == 3) { nextState[i] = true; } else if (!active[i] && neighborCount < 3) { nextState[i] = true; } } active = nextState; activeCount += count(active.begin(), active.end(), true); ++days; } cout << days; return 0; } BUZZ DAY SALE #include <iostream> #include <vector> #include <algorithm> using namespace std; int main() { int n; cin >> n; vector<int> ids(n), costs(n); for (int i = 0; i < n; i++) cin >> ids[i]; for (int i = 0; i < n; i++) cin >> costs[i]; int budget; cin >> budget; int maxItems = 0, minCost = 0; for (int i = 0; i < n; i++) { int itemCost = costs[i]; int quantity = budget / itemCost; if (quantity > 0) { int currentItems = 0, currentCost = 0; for (int j = 0; j < n; j++) { if (i != j && ids[i] % ids[j] == 0) { currentItems += quantity; currentCost += costs[j] * quantity; } } if (currentItems > maxItems || (currentItems == maxItems && currentCost > minCost)) { maxItems = currentItems; minCost = currentCost; } } } cout << maxItems << " " << minCost << endl; return 0; } Arrange map code from collections import deque import itertools def shortest_path(grid, n): start, end = None, None for i in range(n): for j in range(n): if grid[i][j] == 'S': start = (i, j) elif grid[i][j] == 'D': end = (i, j) queue = deque([(start, 0)]) visited = {start} while queue: (x, y), distance = queue.popleft() if (x, y) == end: return distance for nx, ny in [(x+1, y), (x-1, y), (x, y+1), (x, y-1)]: if 0 <= nx < n and 0 <= ny < n and (nx, ny) not in visited and grid[nx][ny] != 'T': visited.add((nx, ny)) queue.append(((nx, ny), distance + 1)) return float('inf') def split_grid(grid, size, block): sections = [] for i in range(0, size, block): for j in range(0, size, block): block_section = [grid[x][j:j+block] for x in range(i, i+block)] sections.append(block_section) return sections def rebuild_grid(order, sections, size, block): full_grid = [["" for _ in range(size)] for _ in range(size)] num_blocks = size // block for index, section_index in enumerate(order): section = sections[section_index] row_offset = (index // num_blocks) * block col_offset = (index % num_blocks) * block for i in range(block): for j in range(block): full_grid[row_offset + i][col_offset + j] = section[i][j] return full_grid def main(): size, block_size = map(int, input().split()) original_grid = [list(input().strip()) for _ in range(size)] sections = split_grid(original_grid, size, block_size) total_sections = (size // block_size

"10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10001", "10010", "00001", "00100", "10001", "01010", "10101", "00000", "00001", "00000"}, {"10001", "11111", "11111", "11111", "11111", "10000", "11111", "10001", "11111", "11111", "10001", "11111", "10001", "10001", "01110", "10000", "11111", "10001", "11111", "00100", "11111", "00100", "11111", "10001", "11111", "11111"} }; vector code(26, ""); for (int row = 0; row < 9; row++) { for (int col = 0; col < 26; col++) { code[col] += A[row][col]; } } map mp; for (char ch = 'A'; ch <= 'Z'; ch++) { mp[code[ch - 'A']] = ch; } vector B; for (string s; cin >> s; B.push_back(s)); for (int L = 0, R = 0; R < (int)B[0].size(); R++) { int zeros = 0; for (int row = 0; row < 9; row++) { zeros += B[row][R] == '0'; } if (zeros == 9) { L = R + 1; } else if (R - L + 1 == 5) { string pl; for (int row = 0; row < 9; row++) { pl += B[row].substr(L, 5); } if (mp.count(pl)) { cout << mp[pl]; } L = R + 1; } } return 0; } Matrix rotation def rotate_layer(layer, pos, direction, odd_layer): n = len(layer) rotated_layer = [None] * n if direction == "clockwise": for i in range(n): rotated_layer[(i + pos) % n] = layer[i] else: for i in range(n): rotated_layer[(i - pos) % n] = layer[i] for i in range(n): if odd_layer: rotated_layer[i] = chr(((ord(rotated_layer[i]) - ord('A') - 1) % 26) + ord('A')) else: rotated_layer[i] = chr(((ord(rotated_layer[i]) - ord('A') + 1) % 26) + ord('A')) return rotated_layer def adjust_query(plan, row, col, size): layers = [] for layer in range(size // 2): current_layer = [] for j in range(col + layer, col + size - layer): current_layer.append(plan[row + layer][j]) for i in range(row + layer + 1, row + size - layer - 1): current_layer.append(plan[i][col + size - layer - 1]) for j in range(col + size - layer - 1, col + layer - 1, -1): current_layer.append(plan[row + size - layer - 1][j]) for i in range(row + size - layer - 2, row + layer, -1): current_layer.append(plan[i][col + layer]) layers.append(current_layer) for lidx, layer in enumerate(layers): odd_layer = (lidx + 1) % 2 == 1 direction = "counterclockwise" if odd_layer else "clockwise" pos = lidx + 1 rotated_layer = rotate_layer(layer, pos, direction, odd_layer) idx = 0 for j in range(col + lidx, col + size - lidx): plan[row + lidx][j] = rotated_layer[idx] idx += 1 for i in range(row + lidx + 1, row + size - lidx - 1): plan[i][col + size - lidx - 1] = rotated_layer[idx] idx += 1 for j in range(col + size - lidx - 1, col + lidx - 1, -1): plan[row + size - lidx - 1][j] = rotated_layer[idx] idx += 1 for i in range(row + size - lidx - 2, row + lidx, -1): plan[i][col + lidx] = rotated_layer[idx] idx += 1 def perform_rotation(n, plan, queries): for row, col, size in queries: adjust_query(plan, row, col, size) return ''.join(''.join(row) for row in plan) n = int(input()) plan = [list(input().strip()) for _ in range(n)] q = int(input()) queries = [tuple(map(int, input().split())) for _ in range(q)] result = perform_rotation(n, plan, queries) print(result, end="") HELP RITIKA import sys import math def get_max_prefix_length_and_deletions(sub_str, target_str, start_idx): sub_idx, target_idx, match_length = 0, start_idx, 0 while sub_idx < len(sub_str) and target_idx < len(target_str): if sub_str[sub_idx] == target_str[target_idx]: match_length += 1

Count press #include <iostream> #include <string> #include <vector> #include <unordered_map> using namespace std; int dp(string& s, vector<string>& v, unordered_map<string, int>& memo) { if (memo.count(s)) return memo[s]; int maxRemoval = 0; for (auto& x : v) { size_t pos = s.find(x); if (pos != string::npos) { string new_string = s.substr(0, pos) + s.substr(pos + x.size()); maxRemoval = max(maxRemoval, 1 + dp(new_string, v, memo)); } } return memo[s] = maxRemoval; } int main() { int n; cin >> n; vector<string> substrings(n); for (int i = 0; i < n; ++i) { cin >> substrings[i]; } string mainString; cin >> mainString; unordered_map<string, int> memo; cout << dp(mainString, substrings, memo); return 0; } FOLDER AREA #include <iostream> #include <cmath> #include <set> #include <iomanip> #include <vector> #include <utility> using namespace std; pair<double, double> reflectPoint(double px, double py, double x1, double y1, double x2, double y2) { double A = y2 - y1; double B = x1 - x2; double C = x2 * y1 - x1 * y2; double distance = (A * px + B * py + C) / sqrt(A * A + B * B); double reflectedX = px - 2 * distance * (A / sqrt(A * A + B * B)); double reflectedY = py - 2 * distance * (B / sqrt(A * A + B * B)); return {reflectedX, reflectedY}; } int main() { double area; cout << "Enter area of the square: "; cin >> area; double x1, y1, x2, y2; cout << "Enter the coordinates of the line (x1 y1 x2 y2): "; cin >> x1 >> y1 >> x2 >> y2; double side = sqrt(area); vector<pair<double, double>> corners = { {0, 0}, {0, side}, {side, side}, {side, 0} }; set<pair<double, double>> uniquePoints(corners.begin(), corners.end()); for (const auto& corner : corners) { auto [rx, ry] = reflectPoint(corner.first, corner.second, x1, y1, x2, y2); uniquePoints.insert({rx, ry}); } for (const auto& point : uniquePoints) { cout << fixed << setprecision(2) << point.first << " " << point.second << endl; } return 0; } Segment display #include <bits/stdc++.h> using namespace std; int main() { vector<vector<string>> A = { {"11111", "11111", "11111", "11111", "11111", "11111", "11111", "10001", "11111", "11111", "10001", "10000", "11111", "10001", "01110", "11111", "11111", "11111", "11111", "11111", "10001", "10001", "10001", "10001", "10001", "11111"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10010", "10000", "10101", "11001", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10100", "10000", "10101", "10101", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "01010", "10001", "00010"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "11000", "10000", "10101", "10011", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"11111", "11111", "10000", "10001", "11111", "11111", "10111", "11111", "00100", "10001", "11111", "10000", "10101", "10001", "10001", "11111", "10101", "11111", "11111", "00100", "10001", "10001", "10101", "00100", "11111", "00100"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10001", "11000", "00001", "00100", "10001", "10001", "10101", "00000", "00001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10011", "10100", "00001", "00100", "10001", "10001", "10101", "01010", "00001", "01000"}, {"10001", "10001", "10000", "10001", "10000", "10000",

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Count press #include <iostream> #include <string> #include <vector> #include <unordered_map> using namespace std; int dp(string& s, vector<string>& v, unordered_map<string, int>& memo) { if (memo.count(s)) return memo[s]; int maxRemoval = 0; for (auto& x : v) { size_t pos = s.find(x); if (pos != string::npos) { string new_string = s.substr(0, pos) + s.substr(pos + x.size()); maxRemoval = max(maxRemoval, 1 + dp(new_string, v, memo)); } } return memo[s] = maxRemoval; } int main() { int n; cin >> n; vector<string> substrings(n); for (int i = 0; i < n; ++i) { cin >> substrings[i]; } string mainString; cin >> mainString; unordered_map<string, int> memo; cout << dp(mainString, substrings, memo); return 0; } FOLDER AREA #include <iostream> #include <cmath> #include <set> #include <iomanip> #include <vector> #include <utility> using namespace std; pair<double, double> reflectPoint(double px, double py, double x1, double y1, double x2, double y2) { double A = y2 - y1; double B = x1 - x2; double C = x2 * y1 - x1 * y2; double distance = (A * px + B * py + C) / sqrt(A * A + B * B); double reflectedX = px - 2 * distance * (A / sqrt(A * A + B * B)); double reflectedY = py - 2 * distance * (B / sqrt(A * A + B * B)); return {reflectedX, reflectedY}; } int main() { double area; cout << "Enter area of the square: "; cin >> area; double x1, y1, x2, y2; cout << "Enter the coordinates of the line (x1 y1 x2 y2): "; cin >> x1 >> y1 >> x2 >> y2; double side = sqrt(area); vector<pair<double, double>> corners = { {0, 0}, {0, side}, {side, side}, {side, 0} }; set<pair<double, double>> uniquePoints(corners.begin(), corners.end()); for (const auto& corner : corners) { auto [rx, ry] = reflectPoint(corner.first, corner.second, x1, y1, x2, y2); uniquePoints.insert({rx, ry}); } for (const auto& point : uniquePoints) { cout << fixed << setprecision(2) << point.first << " " << point.second << endl; } return 0; } Segment display #include <bits/stdc++.h> using namespace std; int main() { vector<vector<string>> A = { {"11111", "11111", "11111", "11111", "11111", "11111", "11111", "10001", "11111", "11111", "10001", "10000", "11111", "10001", "01110", "11111", "11111", "11111", "11111", "11111", "10001", "10001", "10001", "10001", "10001", "11111"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10010", "10000", "10101", "11001", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "10100", "10000", "10101", "10101", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "01010", "10001", "00010"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10000", "10001", "00100", "00001", "11000", "10000", "10101", "10011", "10001", "10001", "10001", "10001", "10000", "00100", "10001", "10001", "10001", "00000", "10001", "00000"}, {"11111", "11111", "10000", "10001", "11111", "11111", "10111", "11111", "00100", "10001", "11111", "10000", "10101", "10001", "10001", "11111", "10101", "11111", "11111", "00100", "10001", "10001", "10101", "00100", "11111", "00100"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10001", "11000", "00001", "00100", "10001", "10001", "10101", "00000", "00001", "00000"}, {"10001", "10001", "10000", "10001", "10000", "10000", "10001", "10001", "00100", "10001", "10001", "10000", "10001", "10001", "10001", "10000", "10011", "10100", "00001", "00100", "10001", "10001", "10101", "01010", "00001", "01000"}, {"10001", "10001", "10000", "10001", "10000", "10000",

) ** 2     start_section = end_section = None     for idx, section in enumerate(sections):         for row in section:             if 'S' in row:                 start_section = idx             if 'D' in row:                 end_section = idx     other_sections = [i for i in range(total_sections) if i not in {start_section, end_section}]     min_path = float('inf')     for perm in itertools.permutations(other_sections):         order = [start_section] + list(perm) + [end_section]         rebuilt_grid = rebuild_grid(order, sections, size, block_size)         min_path = min(min_path, shortest_path(rebuilt_grid, size))     return min_path if name == "main":     print(main()) ALTERNATING STRING import java.util.Scanner; public class AlternatingStringProcessor {     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);                 String binaryString = scanner.nextLine();         int length = binaryString.length();         int[] values = new int[length];         for (int i = 0; i < length; i++) {             values[i] = scanner.nextInt();         }         int result = 0;         int currentDigit = binaryString.charAt(0) - '0';         int lastValue = values[0];         for (int i = 1; i < length; i++) {             int nextDigit = binaryString.charAt(i) - '0';             if (nextDigit == currentDigit) {                 result += Math.min(lastValue, values[i]);                 lastValue = Math.max(lastValue, values[i]);             } else {                 currentDigit = nextDigit;                 lastValue = values[i];             }         }         System.out.println(result);     } } TCS CodeVita @itjobsservices

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