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📈 Аналітичний огляд Telegram-каналу allcoding1

Канал allcoding1 (@allcoding1) у мовному сегменті Англійська є активним учасником. На даний момент спільнота об'єднує 21 584 підписників, посідаючи 9 062 місце в категорії Освіта та 19 025 місце у регіоні Індія.

📊 Показники аудиторії та динаміка

З моменту свого створення невідомо, проект продемонстрував стрімке зростання, зібравши аудиторію у 21 584 підписників.

За останніми даними від 29 серпня, 2026, канал демонструє стабільну активність. Хоча за останні 30 днів спостерігається зміна кількості учасників на -360, а за останні 24 години на -8, загальне охоплення залишається високим.

  • Статус верифікації: Не верифікований
  • Рівень залученості (ER): Середній показник залученості аудиторії становить 5.78%. Протягом перших 24 годин після публікації контент зазвичай збирає 1.10% реакцій від загальної кількості підписників.
  • Охоплення публікацій: В середньому кожен допис отримує 1 247 переглядів. Протягом першої доби публікація в середньому набирає 238 переглядів.
  • Реакції та взаємодія: Аудиторія активно підтримує контент: середня кількість реакцій на один пост – 0.
  • Тематичні інтереси: Контент зосереджений навколо ключових тем, таких як dsa, stack, namaste, javascript, learning.

📝 Опис та контентна політика

Опис каналу не надано.

Завдяки високій частоті оновлень (останні дані отримано 30 серпня, 2026), канал підтримує актуальність та високий рівень охоплення публікацій. Аналітика показує, що аудиторія активно взаємодіє з контентом, що робить його важливою точкою впливу в категорії Освіта.

21 584
Підписники
-824 години
-787 днів
-36030 день
Архів дописів
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Repost from allcoding1_official
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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses @ 70 rupees Contact:- @meterials_available

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Repost from allcoding1
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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses (100 rupees) Contact:- @meterials_available

#include #include #include using namespace std; double solve(const vector& cnts) { vector den = {0.20, 0.40, 1, 2, 5, 10}
#include <iostream> #include <vector> #include <numeric> using namespace std; double solve(const vector<int>& cnts) { vector<double> den = {0.20, 0.40, 1, 2, 5, 10}; double tot = 0.0; for (size_t i = 0; i < cnts.size(); ++i) { tot += cnts[i] * den[i]; } return tot; } int main() { vector<int> cnts; int input; while (cin >> input) { cnts.push_back(input); } cout << solve(cnts) << endl; return 0; }

#include <bits/stdc++.h> int getMinimumStress(int graph_nodes, int graph_edges, vector<pair<int, int>>& edges, vector<int>& weights, int source, int destination) { Graph graph(graph_nodes + 1); for (int i = 0; i < graph_edges; ++i) { int u = edges[i].first; int v = edges[i].second; int w = weights[i]; graph[u].push_back({v, w}); graph[v].push_back({u, w}); } priority_queue<pii, vector<pii>, greater<pii>> pq; vector<int> min_stress(graph_nodes + 1, INT_MAX ); pq.push({0, source}); min_stress[source] = 0; while (!pq.empty()) { int curr_stress = pq.top().first; int u = pq.top().second; pq.pop(); if (u == destination) { return curr_stress; } if (curr_stress > min_stress[u]) { continue; } for (const auto& neighbor : graph[u]) { int v = neighbor.first; int weight = neighbor.second; int next_stress = max(curr_stress, weight); if (next_stress < min_stress[v]) { min_stress[v] = next_stress; pq.push({next_stress, v}); } } } return -1; }

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#include <iostream> #include <vector> #include <cmath> #include <string> #include <algorithm> using namespace std; int main() {     vector<string> k = {"1234567890", "qwertyuiop", "asdfghjkl", "zxcvbnm"};     string w;     getline(cin, w);     transform(w.begin(), w.end(), w.begin(), ::tolower);     vector<string> words;     string temp;     for (char c : w)     {         if (c == ' ')         {             if (!temp.empty())             {                 words.push_back(temp);                 temp.clear();             }         }         else         {             temp += c;         }     }     if (!temp.empty())     {         words.push_back(temp);     }     int t = 0;     for (string v : words)     {         int l = v.length();         vector<int> r(l, -1);         vector<int> p(l, -1);         for (int i = 0; i < l; ++i)         {             bool f = false;             for (int j = 0; j < k.size(); ++j)             {                 int c = k[j].find(v[i]);                 if (c != string::npos)                 {                     r[i] = j;                     p[i] = c;                     f = true;                     break;                 }             }             if (!f)             {                 break;             }         }         int c = 0;         for (int i = 1; i < l; ++i)         {             if (r[i] == r[i - 1] && abs(p[i] - p[i - 1]) <= 1)             {                 c += 1;             }             else             {                 if (c > 0)                 {                     if (r[i - 1] == -1)                     {                         t += 2;                     }                     else                     {                         t += 1;                     }                     c = 0;                 }             }         }         if (c > 0)         {             if (r[l - 1] == -1)             {                 t += 2;             }             else             {                 t += 1;             }         }     }     cout << t << endl;     return 0; }

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Palindrome
Palindrome

Good sequence
Good sequence

import java.util.*; public class Maib {     private static int reverseNumber(int num) {         int reversed = 0;         while (num != 0) {             reversed = reversed * 10 + num % 10;             num /= 10;         }         return reversed;     }     private static int largestPossibleNumber(int num) {         char[] digits = String.valueOf(num).toCharArray();         Arrays.sort(digits);         StringBuilder largestNumStr = new StringBuilder(new String(digits)).reverse();         return Integer.parseInt(largestNumStr.toString());     }     private static List<Integer> splitIntoDigits(int num) {         List<Integer> digits = new ArrayList<>();         while (num != 0) {             digits.add(num % 10);             num /= 10;         }         Collections.reverse(digits);         return digits;     }     public static String processAndEncodeArray(int[] arr) {         for (int i = 0; i < arr.length; i++) {             arr[i] = reverseNumber(arr[i]);         }                 for (int i = 0; i < arr.length; i++) {             arr[i] = largestPossibleNumber(arr[i]);         }                 List<Integer> allDigits = new ArrayList<>();         for (int num : arr) {             allDigits.addAll(splitIntoDigits(num));         }                 Set<Integer> uniqueDigits = new LinkedHashSet<>(allDigits);         List<Integer> uniqueDigitList = new ArrayList<>(uniqueDigits);                 // Step 5: Generate the encoded string         StringBuilder encodedString = new StringBuilder();         for (int digit : uniqueDigitList) {             if (digit == 0) {                 encodedString.append('$');             } else if (digit % 2 == 0) {                 encodedString.append('*');             } else {                 encodedString.append('#');             }         }                 return encodedString.toString();     }     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);         int n = scanner.nextInt();         int[] arr = new int[n];         for (int i = 0; i < n; i++) {             arr[i] = scanner.nextInt();         }        String result = processAndEncodeArray(arr);         System.out.println(result);     } }

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class Result {     public static void goodSequence(BufferedReader bufferedReader) throws IOException {         StringTokenizer st = new StringTokenizer(bufferedReader.readLine());         int T = Integer.parseInt(st.nextToken());         for (int t = 0; t < T; t++) {             st = new StringTokenizer(bufferedReader.readLine(), ",");             int N = Integer.parseInt(st.nextToken());             int M = Integer.parseInt(st.nextToken());             st = new StringTokenizer(bufferedReader.readLine(), ",");             int[] sequence = new int[N];             for (int i = 0; i < N; i++) {                 sequence[i] = Integer.parseInt(st.nextToken());             }             String result = solveTestCase(N, M, sequence);             System.out.println(result);         }     }     private static String solveTestCase(int N, int M, int[] sequence) {                 int countDivisible = 0;         for (int x : sequence) {             if (x % M == 0) {                 countDivisible++;             }         }         if (countDivisible == 0) {             return "0/1";         }         long totalSubsequences = (1L << N) - 1;         long goodSubsequences = (1L << countDivisible) - 1;         long P = goodSubsequences;         long Q = totalSubsequences;         long commonDivisor = gcd(P, Q);         P /= commonDivisor;         Q /= commonDivisor;         return P + "/" + Q;     }     private static long gcd(long a, long b) {         while (b != 0) {             long temp = b;             b = a % b;             a = temp;         }         return a;     } }

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Only today night
Only today night