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allcoding1

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تُعد قناة allcoding1 (@allcoding1) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 21 584 مشتركاً، محتلاً المرتبة 9 062 في فئة التعليم والمرتبة 19 025 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 21 584 مشتركاً.

بحسب آخر البيانات بتاريخ 29 أغسطس, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -360، وفي آخر 24 ساعة بمقدار -8، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 5.78‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 1.10‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 1 247 مشاهدة. وخلال اليوم الأول يجمع عادةً 238 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 0.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل dsa, stack, namaste, javascript, learning.

📝 الوصف وسياسة المحتوى

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بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 30 أغسطس, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التعليم.

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Repost from allcoding1_official
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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses @ 70 rupees Contact:- @meterials_available

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Repost from allcoding1
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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses (100 rupees) Contact:- @meterials_available

#include #include #include using namespace std; double solve(const vector& cnts) { vector den = {0.20, 0.40, 1, 2, 5, 10}
#include <iostream> #include <vector> #include <numeric> using namespace std; double solve(const vector<int>& cnts) { vector<double> den = {0.20, 0.40, 1, 2, 5, 10}; double tot = 0.0; for (size_t i = 0; i < cnts.size(); ++i) { tot += cnts[i] * den[i]; } return tot; } int main() { vector<int> cnts; int input; while (cin >> input) { cnts.push_back(input); } cout << solve(cnts) << endl; return 0; }

#include <bits/stdc++.h> int getMinimumStress(int graph_nodes, int graph_edges, vector<pair<int, int>>& edges, vector<int>& weights, int source, int destination) { Graph graph(graph_nodes + 1); for (int i = 0; i < graph_edges; ++i) { int u = edges[i].first; int v = edges[i].second; int w = weights[i]; graph[u].push_back({v, w}); graph[v].push_back({u, w}); } priority_queue<pii, vector<pii>, greater<pii>> pq; vector<int> min_stress(graph_nodes + 1, INT_MAX ); pq.push({0, source}); min_stress[source] = 0; while (!pq.empty()) { int curr_stress = pq.top().first; int u = pq.top().second; pq.pop(); if (u == destination) { return curr_stress; } if (curr_stress > min_stress[u]) { continue; } for (const auto& neighbor : graph[u]) { int v = neighbor.first; int weight = neighbor.second; int next_stress = max(curr_stress, weight); if (next_stress < min_stress[v]) { min_stress[v] = next_stress; pq.push({next_stress, v}); } } } return -1; }

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#include <iostream> #include <vector> #include <cmath> #include <string> #include <algorithm> using namespace std; int main() {     vector<string> k = {"1234567890", "qwertyuiop", "asdfghjkl", "zxcvbnm"};     string w;     getline(cin, w);     transform(w.begin(), w.end(), w.begin(), ::tolower);     vector<string> words;     string temp;     for (char c : w)     {         if (c == ' ')         {             if (!temp.empty())             {                 words.push_back(temp);                 temp.clear();             }         }         else         {             temp += c;         }     }     if (!temp.empty())     {         words.push_back(temp);     }     int t = 0;     for (string v : words)     {         int l = v.length();         vector<int> r(l, -1);         vector<int> p(l, -1);         for (int i = 0; i < l; ++i)         {             bool f = false;             for (int j = 0; j < k.size(); ++j)             {                 int c = k[j].find(v[i]);                 if (c != string::npos)                 {                     r[i] = j;                     p[i] = c;                     f = true;                     break;                 }             }             if (!f)             {                 break;             }         }         int c = 0;         for (int i = 1; i < l; ++i)         {             if (r[i] == r[i - 1] && abs(p[i] - p[i - 1]) <= 1)             {                 c += 1;             }             else             {                 if (c > 0)                 {                     if (r[i - 1] == -1)                     {                         t += 2;                     }                     else                     {                         t += 1;                     }                     c = 0;                 }             }         }         if (c > 0)         {             if (r[l - 1] == -1)             {                 t += 2;             }             else             {                 t += 1;             }         }     }     cout << t << endl;     return 0; }

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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses (100 rupees) Contact:- @meterials_available

Palindrome
Palindrome

Good sequence
Good sequence

import java.util.*; public class Maib {     private static int reverseNumber(int num) {         int reversed = 0;         while (num != 0) {             reversed = reversed * 10 + num % 10;             num /= 10;         }         return reversed;     }     private static int largestPossibleNumber(int num) {         char[] digits = String.valueOf(num).toCharArray();         Arrays.sort(digits);         StringBuilder largestNumStr = new StringBuilder(new String(digits)).reverse();         return Integer.parseInt(largestNumStr.toString());     }     private static List<Integer> splitIntoDigits(int num) {         List<Integer> digits = new ArrayList<>();         while (num != 0) {             digits.add(num % 10);             num /= 10;         }         Collections.reverse(digits);         return digits;     }     public static String processAndEncodeArray(int[] arr) {         for (int i = 0; i < arr.length; i++) {             arr[i] = reverseNumber(arr[i]);         }                 for (int i = 0; i < arr.length; i++) {             arr[i] = largestPossibleNumber(arr[i]);         }                 List<Integer> allDigits = new ArrayList<>();         for (int num : arr) {             allDigits.addAll(splitIntoDigits(num));         }                 Set<Integer> uniqueDigits = new LinkedHashSet<>(allDigits);         List<Integer> uniqueDigitList = new ArrayList<>(uniqueDigits);                 // Step 5: Generate the encoded string         StringBuilder encodedString = new StringBuilder();         for (int digit : uniqueDigitList) {             if (digit == 0) {                 encodedString.append('$');             } else if (digit % 2 == 0) {                 encodedString.append('*');             } else {                 encodedString.append('#');             }         }                 return encodedString.toString();     }     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);         int n = scanner.nextInt();         int[] arr = new int[n];         for (int i = 0; i < n; i++) {             arr[i] = scanner.nextInt();         }        String result = processAndEncodeArray(arr);         System.out.println(result);     } }

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class Result {     public static void goodSequence(BufferedReader bufferedReader) throws IOException {         StringTokenizer st = new StringTokenizer(bufferedReader.readLine());         int T = Integer.parseInt(st.nextToken());         for (int t = 0; t < T; t++) {             st = new StringTokenizer(bufferedReader.readLine(), ",");             int N = Integer.parseInt(st.nextToken());             int M = Integer.parseInt(st.nextToken());             st = new StringTokenizer(bufferedReader.readLine(), ",");             int[] sequence = new int[N];             for (int i = 0; i < N; i++) {                 sequence[i] = Integer.parseInt(st.nextToken());             }             String result = solveTestCase(N, M, sequence);             System.out.println(result);         }     }     private static String solveTestCase(int N, int M, int[] sequence) {                 int countDivisible = 0;         for (int x : sequence) {             if (x % M == 0) {                 countDivisible++;             }         }         if (countDivisible == 0) {             return "0/1";         }         long totalSubsequences = (1L << N) - 1;         long goodSubsequences = (1L << countDivisible) - 1;         long P = goodSubsequences;         long Q = totalSubsequences;         long commonDivisor = gcd(P, Q);         P /= commonDivisor;         Q /= commonDivisor;         return P + "/" + Q;     }     private static long gcd(long a, long b) {         while (b != 0) {             long temp = b;             b = a % b;             a = temp;         }         return a;     } }

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Only today night
Only today night