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📈 Аналітичний огляд Telegram-каналу allcoding1

Канал allcoding1 (@allcoding1) у мовному сегменті Англійська є активним учасником. На даний момент спільнота об'єднує 21 584 підписників, посідаючи 9 062 місце в категорії Освіта та 19 025 місце у регіоні Індія.

📊 Показники аудиторії та динаміка

З моменту свого створення невідомо, проект продемонстрував стрімке зростання, зібравши аудиторію у 21 584 підписників.

За останніми даними від 29 серпня, 2026, канал демонструє стабільну активність. Хоча за останні 30 днів спостерігається зміна кількості учасників на -360, а за останні 24 години на -8, загальне охоплення залишається високим.

  • Статус верифікації: Не верифікований
  • Рівень залученості (ER): Середній показник залученості аудиторії становить 5.78%. Протягом перших 24 годин після публікації контент зазвичай збирає 1.10% реакцій від загальної кількості підписників.
  • Охоплення публікацій: В середньому кожен допис отримує 1 247 переглядів. Протягом першої доби публікація в середньому набирає 238 переглядів.
  • Реакції та взаємодія: Аудиторія активно підтримує контент: середня кількість реакцій на один пост – 0.
  • Тематичні інтереси: Контент зосереджений навколо ключових тем, таких як dsa, stack, namaste, javascript, learning.

📝 Опис та контентна політика

Опис каналу не надано.

Завдяки високій частоті оновлень (останні дані отримано 30 серпня, 2026), канал підтримує актуальність та високий рівень охоплення публікацій. Аналітика показує, що аудиторія активно взаємодіє з контентом, що робить його важливою точкою впливу в категорії Освіта.

21 584
Підписники
-824 години
-787 днів
-36030 день
Архів дописів
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public static int findMaximumGreatness(int[] arr) { int n = arr.length; Arrays.sort(arr); int greatness = 0; int j = 0; boole
public static int findMaximumGreatness(int[] arr) { int n = arr.length; Arrays.sort(arr); int greatness = 0; int j = 0; boolean[] used = new boolean[n]; for (int i = 0; i < n; i++) { while (j < n && (used[j] || arr[j] <= arr[i])) { j++; } if (j < n && arr[j] > arr[i]) { used[j] = true; greatness++; j++; } } return greatness; }

public static int findEarliestMeetingTime(List&gt; schedules, int length) { int DAY_END = 24 * 60; List allMeetings = new Arr
public static int findEarliestMeetingTime(List<List<int[]>> schedules, int length) { int DAY_END = 24 * 60; List<int[]> allMeetings = new ArrayList<>(); for (List<int[]> employeeMeetings : schedules) { allMeetings.addAll(employeeMeetings); } Collections.sort(allMeetings, (a, b) -> Integer.compare(a[0], b[0])); int earliestAvailable = 0; for (int[] meeting : allMeetings) { if (earliestAvailable + length <= meeting[0]) { return earliestAvailable; } earliestAvailable = Math.max(earliestAvailable, meeting[1]); } if (earliestAvailable + length <= DAY_END) { return earliestAvailable; } return -1; }

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MountBlue1-10.pdf1.86 KB

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