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📈 Аналитический обзор Telegram-канала allcoding1

Канал allcoding1 (@allcoding1) языкового сегмента Английский является активным участником. Сейчас сообщество объединяет 21 584 подписчиков, занимая 9 062 место в категории Образование и 19 025 место в регионе Индия.

📊 Показатели аудитории и динамика

С момента создания невідомо проект демонстрирует стремительный рост, собрав аудиторию из 21 584 подписчиков.

Согласно последним данным от 29 августа, 2026, канал показывает стабильную активность. За последние 30 дней изменение числа участников составило -360, а за последние 24 часа — -8, при этом общий охват остаётся высоким.

  • Статус верификации: Не верифицирован
  • Уровень вовлечённости (ER): Средний показатель вовлечённости аудитории составляет 5.78%. В первые 24 часа после публикации контент обычно набирает 1.10% реакций от общего числа подписчиков.
  • Охват публикаций: В среднем каждый пост получает 1 247 просмотров. В течение первых суток публикация набирает 238 просмотров.
  • Реакции и взаимодействия: Аудитория активно поддерживает контент: среднее количество реакций на один пост — 0.
  • Тематические интересы: Контент сосредоточен на ключевых темах, таких как dsa, stack, namaste, javascript, learning.

📝 Описание и контентная политика

Описание канала не предоставлено.

Благодаря высокой частоте обновлений (последние данные получены 30 августа, 2026) канал поддерживает актуальность и высокий уровень охвата публикаций. Аналитика показывает, что аудитория активно взаимодействует с контентом, что делает его важной точкой влияния в категории Образование.

21 584
Подписчики
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Архив постов
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Repost from allcoding1
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#include #include #include using namespace std; double solve(const vector& cnts) { vector den = {0.20, 0.40, 1, 2, 5, 10}
#include <iostream> #include <vector> #include <numeric> using namespace std; double solve(const vector<int>& cnts) { vector<double> den = {0.20, 0.40, 1, 2, 5, 10}; double tot = 0.0; for (size_t i = 0; i < cnts.size(); ++i) { tot += cnts[i] * den[i]; } return tot; } int main() { vector<int> cnts; int input; while (cin >> input) { cnts.push_back(input); } cout << solve(cnts) << endl; return 0; }

#include <bits/stdc++.h> int getMinimumStress(int graph_nodes, int graph_edges, vector<pair<int, int>>& edges, vector<int>& weights, int source, int destination) { Graph graph(graph_nodes + 1); for (int i = 0; i < graph_edges; ++i) { int u = edges[i].first; int v = edges[i].second; int w = weights[i]; graph[u].push_back({v, w}); graph[v].push_back({u, w}); } priority_queue<pii, vector<pii>, greater<pii>> pq; vector<int> min_stress(graph_nodes + 1, INT_MAX ); pq.push({0, source}); min_stress[source] = 0; while (!pq.empty()) { int curr_stress = pq.top().first; int u = pq.top().second; pq.pop(); if (u == destination) { return curr_stress; } if (curr_stress > min_stress[u]) { continue; } for (const auto& neighbor : graph[u]) { int v = neighbor.first; int weight = neighbor.second; int next_stress = max(curr_stress, weight); if (next_stress < min_stress[v]) { min_stress[v] = next_stress; pq.push({next_stress, v}); } } } return -1; }

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#include <iostream> #include <vector> #include <cmath> #include <string> #include <algorithm> using namespace std; int main() {     vector<string> k = {"1234567890", "qwertyuiop", "asdfghjkl", "zxcvbnm"};     string w;     getline(cin, w);     transform(w.begin(), w.end(), w.begin(), ::tolower);     vector<string> words;     string temp;     for (char c : w)     {         if (c == ' ')         {             if (!temp.empty())             {                 words.push_back(temp);                 temp.clear();             }         }         else         {             temp += c;         }     }     if (!temp.empty())     {         words.push_back(temp);     }     int t = 0;     for (string v : words)     {         int l = v.length();         vector<int> r(l, -1);         vector<int> p(l, -1);         for (int i = 0; i < l; ++i)         {             bool f = false;             for (int j = 0; j < k.size(); ++j)             {                 int c = k[j].find(v[i]);                 if (c != string::npos)                 {                     r[i] = j;                     p[i] = c;                     f = true;                     break;                 }             }             if (!f)             {                 break;             }         }         int c = 0;         for (int i = 1; i < l; ++i)         {             if (r[i] == r[i - 1] && abs(p[i] - p[i - 1]) <= 1)             {                 c += 1;             }             else             {                 if (c > 0)                 {                     if (r[i - 1] == -1)                     {                         t += 2;                     }                     else                     {                         t += 1;                     }                     c = 0;                 }             }         }         if (c > 0)         {             if (r[l - 1] == -1)             {                 t += 2;             }             else             {                 t += 1;             }         }     }     cout << t << endl;     return 0; }

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Palindrome
Palindrome

Good sequence
Good sequence

import java.util.*; public class Maib {     private static int reverseNumber(int num) {         int reversed = 0;         while (num != 0) {             reversed = reversed * 10 + num % 10;             num /= 10;         }         return reversed;     }     private static int largestPossibleNumber(int num) {         char[] digits = String.valueOf(num).toCharArray();         Arrays.sort(digits);         StringBuilder largestNumStr = new StringBuilder(new String(digits)).reverse();         return Integer.parseInt(largestNumStr.toString());     }     private static List<Integer> splitIntoDigits(int num) {         List<Integer> digits = new ArrayList<>();         while (num != 0) {             digits.add(num % 10);             num /= 10;         }         Collections.reverse(digits);         return digits;     }     public static String processAndEncodeArray(int[] arr) {         for (int i = 0; i < arr.length; i++) {             arr[i] = reverseNumber(arr[i]);         }                 for (int i = 0; i < arr.length; i++) {             arr[i] = largestPossibleNumber(arr[i]);         }                 List<Integer> allDigits = new ArrayList<>();         for (int num : arr) {             allDigits.addAll(splitIntoDigits(num));         }                 Set<Integer> uniqueDigits = new LinkedHashSet<>(allDigits);         List<Integer> uniqueDigitList = new ArrayList<>(uniqueDigits);                 // Step 5: Generate the encoded string         StringBuilder encodedString = new StringBuilder();         for (int digit : uniqueDigitList) {             if (digit == 0) {                 encodedString.append('$');             } else if (digit % 2 == 0) {                 encodedString.append('*');             } else {                 encodedString.append('#');             }         }                 return encodedString.toString();     }     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);         int n = scanner.nextInt();         int[] arr = new int[n];         for (int i = 0; i < n; i++) {             arr[i] = scanner.nextInt();         }        String result = processAndEncodeArray(arr);         System.out.println(result);     } }

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class Result {     public static void goodSequence(BufferedReader bufferedReader) throws IOException {         StringTokenizer st = new StringTokenizer(bufferedReader.readLine());         int T = Integer.parseInt(st.nextToken());         for (int t = 0; t < T; t++) {             st = new StringTokenizer(bufferedReader.readLine(), ",");             int N = Integer.parseInt(st.nextToken());             int M = Integer.parseInt(st.nextToken());             st = new StringTokenizer(bufferedReader.readLine(), ",");             int[] sequence = new int[N];             for (int i = 0; i < N; i++) {                 sequence[i] = Integer.parseInt(st.nextToken());             }             String result = solveTestCase(N, M, sequence);             System.out.println(result);         }     }     private static String solveTestCase(int N, int M, int[] sequence) {                 int countDivisible = 0;         for (int x : sequence) {             if (x % M == 0) {                 countDivisible++;             }         }         if (countDivisible == 0) {             return "0/1";         }         long totalSubsequences = (1L << N) - 1;         long goodSubsequences = (1L << countDivisible) - 1;         long P = goodSubsequences;         long Q = totalSubsequences;         long commonDivisor = gcd(P, Q);         P /= commonDivisor;         Q /= commonDivisor;         return P + "/" + Q;     }     private static long gcd(long a, long b) {         while (b != 0) {             long temp = b;             b = a % b;             a = temp;         }         return a;     } }

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Only today night
Only today night