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CODING SOLUTION - Placement Jobs & Materials

CODING SOLUTION - Placement Jobs & Materials

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🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “ Contact Admin: Mail me for collab offcampusjobsindiaadmin@gmail.com instagram.com/offcampusjobsindia_it Our Website : www.offcampusjobsindia.com

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📈 Análisis del canal de Telegram CODING SOLUTION - Placement Jobs & Materials

El canal CODING SOLUTION - Placement Jobs & Materials (@codingsolution_it) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 129 376 suscriptores, ocupando la posición 152 en la categoría Carrera profesional y el puesto 1 684 en la región India.

📊 Métricas de audiencia y dinámica

Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 129 376 suscriptores.

Según los últimos datos del 24 octubre, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de -889, y en las últimas 24 horas de -37, conservando un alto alcance.

  • Estado de verificación: No verificado
  • Tasa de interacción (ER): El promedio de interacción de la audiencia es 1.39%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 0.44% de reacciones respecto al total de suscriptores.
  • Alcance de las publicaciones: Cada publicación recibe en promedio 1 793 visualizaciones. En el primer día suele acumular 565 visualizaciones.
  • Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 0.
  • Intereses temáticos: El contenido se centra en temas clave como t.me/codingsolution_it, vector, codevita, string, graduate.

📝 Descripción y política de contenido

El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “ Contact Admin: Mail me for collab offcampusjobsindiaadmin@gmail.com instagram.com/offcampusjobsindia_it Our Website : www.offcampusjobsindia.com”

Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 25 octubre, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Carrera profesional.

129 376
Suscriptores
-3724 horas
-5037 días
-88930 días
Archivo de publicaciones
#include <iostream> #include <vector> #include <algorithm> using namespace std; long long solve(int n, vector<vector<int>>& g) { if (n == 0) return 0; vector<vector<long long>> dp(n, vector<long long>(n, -2e18)); dp[0][0] = g[0][0]; for (int s = 1; s <= 2 * n - 2; ++s) { vector<vector<long long>> ndp(n, vector<long long>(n, -2e18)); int mn = max(0, s - n + 1); int mx = min(s, n - 1); for (int x1 = mn; x1 <= mx; ++x1) { for (int x2 = mn; x2 <= mx; ++x2) { int y1 = s - x1; int y2 = s - x2; long long prv = -2e18; if (x1 > 0 && x2 > 0) prv = max(prv, dp[x1 - 1][x2 - 1]); if (x1 > 0 && y2 > 0) prv = max(prv, dp[x1 - 1][x2]); if (y1 > 0 && x2 > 0) prv = max(prv, dp[x1][x2 - 1]); if (y1 > 0 && y2 > 0) prv = max(prv, dp[x1][x2]); if (prv != -2e18) { long long val = g[x1][y1]; if (x1 != x2) val += g[x2][y2]; ndp[x1][x2] = prv + val; } } } dp = ndp; } return dp[n - 1][n - 1]; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n; if (cin >> n) { vector<vector<int>> g(n, vector<int>(n)); for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { cin >> g[i][j]; } } auto result = solve(n, g); cout << result << "\n"; } return 0; } Infosys ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📢 DM @Codemaster004

#include #include using namespace std; bool chk(int m, int n, int k, const string&amp; o) { long long c = 0; int lst = 0; for
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#include <iostream> #include <string> using namespace std; bool chk(int m, int n, int k, const string& o) { long long c = 0; int lst = 0; for (int i = 0; i < n; ++i) { if (o[i] == '1') { int cur = i + 1; c += (cur - lst - 1) / m; lst = cur; } } c += (n + 1 - lst - 1) / m; return c <= k; } int solve(int n, int k, string o) { int l = 1, r = n + 1; int ans = r; while (l <= r) { int m = l + (r - l) / 2; if (chk(m, n, k, o)) { ans = m; r = m - 1; } else { l = m + 1; } } return ans; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n, k; if (cin >> n >> k) { string o; cin >> o; cout << solve(n, k, o) << "\n"; } return 0; } Infosys ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📢 DN @Codemaster004

import java.util.*; class Main { public static int solve(int n, int[] w1, int[] v1, int[] w2, int[] v2, int c) { int[] dp = new int[c + 1]; for (int i = 0; i < n; i++) { for (int w = c; w >= 0; w--) { int maxVal = dp[w]; if (w >= w1[i]) { maxVal = Math.max(maxVal, dp[w - w1[i]] + v1[i]); } if (w >= w2[i]) { maxVal = Math.max(maxVal, dp[w - w2[i]] + v2[i]); } dp[w] = maxVal; } } return dp[c]; } public static void main(String[] args) { Scanner sc = new Scanner(System.in); if (!sc.hasNextInt()) return; int n = sc.nextInt(); int[] w1 = new int[n]; for (int i = 0; i < n; i++) w1[i] = sc.nextInt(); int[] v1 = new int[n]; for (int i = 0; i < n; i++) v1[i] = sc.nextInt(); int[] w2 = new int[n]; for (int i = 0; i < n; i++) w2[i] = sc.nextInt(); int[] v2 = new int[n]; for (int i = 0; i < n; i++) v2[i] = sc.nextInt(); int c = sc.nextInt(); int result = solve(n, w1, v1, w2, v2, c); System.out.println(result); sc.close(); } } INFOSYS ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📢 DM @Codemaster004

🔥 HCLTech is Hiring! 🔥 💻 Role: * Freshers Hiring / Off-Campus Drive * India 🎓 Eligibility: * Batch: 2026 * Freshers 📌 Ke
🔥 HCLTech is Hiring! 🔥 💻 Role: * Freshers Hiring / Off-Campus Drive * India 🎓 Eligibility: * Batch: 2026 * Freshers 📌 Key Requirements: * Good understanding of foundational software engineering concepts * Strong analytical and communication skills 👇 Click below to apply: 🔗 Application Link : https://freshers.hcltech.com/?utm_source=OffCampus&utm_medium=OffCampus_T1Institutions_Batch2026&utm_campaign=OffCampus_T1Institutions_Batch2026&utm_term=HCLTech 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📩 DM: @codemaster004

Wells Fargo ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons 📩 DM: @codemaster004
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Wells Fargo ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons 📩 DM: @codemaster004

import requests def findSpeedster(marathon, sex): url = f"https://jsonmock.hackerrank.com/api/marathon?sex={sex}" best_n = ""
+1
import requests def findSpeedster(marathon, sex): url = f"https://jsonmock.hackerrank.com/api/marathon?sex={sex}" best_n = "" best_s = -1.0 best_st = float('inf') curr_p = 1 total_p = 1 while curr_p <= total_p: resp = requests.get(f"{url}&page={curr_p}").json() if curr_p == 1: total_p = resp['total_pages'] for r in resp['data']: if r['marathon_name'] == marathon: s = float(r['top_speed']) st = int(r['stops_taken']) if s > best_s: best_s = s best_st = st best_n = r['name'] elif s == best_s: if st < best_st: best_st = st best_n = r['name'] curr_p += 1 return best_n IBM ✅ _ 💻 Live Coding | Projects | Interviews | OA & Hackathons Help 📩 DM: @codemaster004

def maximizePacketSum(packetSizes, k): n = len(packetSizes) if k > n: return -1 d = {} s = 0 m = -1 for i in range(n): v = pa
+1
def maximizePacketSum(packetSizes, k): n = len(packetSizes) if k > n: return -1 d = {} s = 0 m = -1 for i in range(n): v = packetSizes[i] s += v d[v] = d.get(v, 0) + 1 if i >= k: o = packetSizes[i - k] s -= o d[o] -= 1 if d[o] == 0: del d[o] if i >= k - 1: if len(d) == k: if s > m: m = s return m IBM ✅ ____ 💻 Live Coding | Projects | Interviews | OA & Hackathons Help 📩 DM: @codemaster004

#include #include using namespace std; bool c(const vector&amp; a, const vector&amp; b) { return a[0] &gt; b[0]; } int solve(
#include <vector> #include <algorithm> using namespace std; bool c(const vector<int>& a, const vector<int>& b) { return a[0] > b[0]; } int solve(int n, int t, vector<vector<int>>& d) { sort(d.begin(), d.end(), c); long long r = t; long long ans = 0; while (r > 0) { int p = -1; for (int i = 0; i < n; ++i) { if (d[i][1] > 0 && r % d[i][0] == 0) { p = i; break; } } if (p == -1) return -1; long long u = min(r / d[p][0], (long long)d[p][1]); r -= u * d[p][0]; ans += u; d[p][1] -= u; } return ans; } Infosys SP ✅ 🚨 Need Help with Coding? 💻 Live Coding | Projects | Interviews | OA & Hackathons 💯 Expert Assistance Available 📩 DM: @codemaster004

INFOSYS SP ✅ ━━━━━━━━━━━━━━━ 🚨 Need Help with Coding Exams, Projects, or Technical Interviews? 💯 Get Expert 1-on-1 Assistan
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INFOSYS SP ✅ ━━━━━━━━━━━━━━━ 🚨 Need Help with Coding Exams, Projects, or Technical Interviews? 💯 Get Expert 1-on-1 Assistance 📩 DM Now ➜ @codemaster004 ⚡ Live Coding Assessments ⚡ Online Assessments (OA) ⚡ Technical Interviews ⚡ Projects & Assignments ⚡ Hackathons & Coding Challenges

Amazon Hackathon ✅
+2
Amazon Hackathon ✅

#include #include using namespace std; vector p; int f(int x) { if (p[x] == x) return x; return p[x] = f(p[x]); } void m(int
#include <iostream> #include <vector> using namespace std; vector<int> p; int f(int x) { if (p[x] == x) return x; return p[x] = f(p[x]); } void m(int x, int y) { int rx = f(x); int ry = f(y); if (rx != ry) { p[rx] = ry; } } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n, q; if (cin >> n >> q) { p.resize(n + 1); for (int i = 0; i <= n; ++i) { p[i] = i; } for (int i = 0; i < q; ++i) { int l, r; cin >> l >> r; m(l - 1, r); } if (f(0) == f(n)) { cout << "Yes\n"; } else { cout << "No\n"; } } return 0; } Amazon Hackathon ✅

SELECT SUM(BALANCE) AS TOTAL_BALANCE, COUNT(ACCOUNT_ID) AS ACCOUNT_COUNT FROM ACCOUNTS WHERE ACCOUNT_TYPE = 'Savings' AND ACC
SELECT SUM(BALANCE) AS TOTAL_BALANCE, COUNT(ACCOUNT_ID) AS ACCOUNT_COUNT FROM ACCOUNTS WHERE ACCOUNT_TYPE = 'Savings' AND ACCOUNT_ID IN ( SELECT ACCOUNT_ID FROM TRANSACTIONS WHERE TRANSACTION_TYPE = 'Deposit' ); Amazon Hackathon ✅

This is literally the cheapest way to learn from top IITs while still in college! 🎓 Masai Unlimited now at ₹99/week - for a
This is literally the cheapest way to learn from top IITs while still in college! 🎓 Masai Unlimited now at ₹99/week - for a limited time only ⚡ ✅ AI, Data Science, ML, Product & more ⚡ iHub IIT Certifications 🤖 24×7 AI Tutor - ask doubts anytime 🌍 Learn in your Mother Tongue No excuses left. Your future’s worth ₹99/week. 🔥 Join before prices go up! 👉 Sign up NOW: https://tinyurl.com/masai-unlimited-registration

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This is literally the cheapest chance to learn from Top IITs while still in college! 🎓 Get Masai Unlimited & unlock: ✅ AI, Data Science, ML, Product Management & more ⚡ iHub IIT Certifications 🤖 24×7 AI Tutor — ask doubts anytime 🌍 Learn in YOUR language No excuses. ₹1 isn’t the barrier, your mindset is. 🔥 Don’t wait — this offer can expire anytime. 👉 Sign up NOW: https://tinyurl.com/masai-unlimited-registration

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Accenture off Campus Drive Job Profile : Application Support Engineers 🎖 Eligibility : Any Bachelor's Degree 🎖Batch - 2023,
Accenture off Campus Drive Job Profile : Application Support Engineers 🎖 Eligibility : Any Bachelor's Degree 🎖Batch -  2023,  2024,  2025 ➡️ Detail Explanatin Video 👇 Youtube - https://youtube.com/@offcampusjobsindia?si=i0EsNHXL-OlG3GuL WhatsApp -  https://tinyurl.com/bdcr25cv Instagram   - https://www.instagram.com/offcampusjobsindia_it 🔗Apply Link        https://www.accenture.com/in-en/careers/jobdetails?id=ATCI-4817203-S1853038_en&title=Application+Support+Engineer