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CODING SOLUTION - Placement Jobs & Materials

CODING SOLUTION - Placement Jobs & Materials

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🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “ Contact Admin: Mail me for collab offcampusjobsindiaadmin@gmail.com instagram.com/offcampusjobsindia_it Our Website : www.offcampusjobsindia.com

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📈 Analytical overview of Telegram channel CODING SOLUTION - Placement Jobs & Materials

Channel CODING SOLUTION - Placement Jobs & Materials (@codingsolution_it) in the English language segment is an active participant. Currently, the community unites 129 376 subscribers, ranking 152 in the Career category and 1 684 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 129 376 subscribers.

According to the latest data from 24 October, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -889 over the last 30 days and by -37 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 1.39%. Within the first 24 hours after publication, content typically collects 0.44% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 793 views. Within the first day, a publication typically gains 565 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
  • Thematic interests: Content is focused on key topics such as t.me/codingsolution_it, vector, codevita, string, graduate.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “ Contact Admin: Mail me for collab offcampusjobsindiaadmin@gmail.com instagram.com/offcampusjobsindia_it Our Website : www.offcampusjobsindia.com”

Thanks to the high frequency of updates (latest data received on 25 October, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Career category.

129 376
Subscribers
-3724 hours
-5037 days
-88930 days
Posts Archive
#include <iostream> #include <vector> #include <algorithm> using namespace std; long long solve(int n, vector<vector<int>>& g) { if (n == 0) return 0; vector<vector<long long>> dp(n, vector<long long>(n, -2e18)); dp[0][0] = g[0][0]; for (int s = 1; s <= 2 * n - 2; ++s) { vector<vector<long long>> ndp(n, vector<long long>(n, -2e18)); int mn = max(0, s - n + 1); int mx = min(s, n - 1); for (int x1 = mn; x1 <= mx; ++x1) { for (int x2 = mn; x2 <= mx; ++x2) { int y1 = s - x1; int y2 = s - x2; long long prv = -2e18; if (x1 > 0 && x2 > 0) prv = max(prv, dp[x1 - 1][x2 - 1]); if (x1 > 0 && y2 > 0) prv = max(prv, dp[x1 - 1][x2]); if (y1 > 0 && x2 > 0) prv = max(prv, dp[x1][x2 - 1]); if (y1 > 0 && y2 > 0) prv = max(prv, dp[x1][x2]); if (prv != -2e18) { long long val = g[x1][y1]; if (x1 != x2) val += g[x2][y2]; ndp[x1][x2] = prv + val; } } } dp = ndp; } return dp[n - 1][n - 1]; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n; if (cin >> n) { vector<vector<int>> g(n, vector<int>(n)); for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { cin >> g[i][j]; } } auto result = solve(n, g); cout << result << "\n"; } return 0; } Infosys ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📢 DM @Codemaster004

#include #include using namespace std; bool chk(int m, int n, int k, const string&amp; o) { long long c = 0; int lst = 0; for
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#include <iostream> #include <string> using namespace std; bool chk(int m, int n, int k, const string& o) { long long c = 0; int lst = 0; for (int i = 0; i < n; ++i) { if (o[i] == '1') { int cur = i + 1; c += (cur - lst - 1) / m; lst = cur; } } c += (n + 1 - lst - 1) / m; return c <= k; } int solve(int n, int k, string o) { int l = 1, r = n + 1; int ans = r; while (l <= r) { int m = l + (r - l) / 2; if (chk(m, n, k, o)) { ans = m; r = m - 1; } else { l = m + 1; } } return ans; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n, k; if (cin >> n >> k) { string o; cin >> o; cout << solve(n, k, o) << "\n"; } return 0; } Infosys ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📢 DN @Codemaster004

import java.util.*; class Main { public static int solve(int n, int[] w1, int[] v1, int[] w2, int[] v2, int c) { int[] dp = new int[c + 1]; for (int i = 0; i < n; i++) { for (int w = c; w >= 0; w--) { int maxVal = dp[w]; if (w >= w1[i]) { maxVal = Math.max(maxVal, dp[w - w1[i]] + v1[i]); } if (w >= w2[i]) { maxVal = Math.max(maxVal, dp[w - w2[i]] + v2[i]); } dp[w] = maxVal; } } return dp[c]; } public static void main(String[] args) { Scanner sc = new Scanner(System.in); if (!sc.hasNextInt()) return; int n = sc.nextInt(); int[] w1 = new int[n]; for (int i = 0; i < n; i++) w1[i] = sc.nextInt(); int[] v1 = new int[n]; for (int i = 0; i < n; i++) v1[i] = sc.nextInt(); int[] w2 = new int[n]; for (int i = 0; i < n; i++) w2[i] = sc.nextInt(); int[] v2 = new int[n]; for (int i = 0; i < n; i++) v2[i] = sc.nextInt(); int c = sc.nextInt(); int result = solve(n, w1, v1, w2, v2, c); System.out.println(result); sc.close(); } } INFOSYS ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📢 DM @Codemaster004

🔥 HCLTech is Hiring! 🔥 💻 Role: * Freshers Hiring / Off-Campus Drive * India 🎓 Eligibility: * Batch: 2026 * Freshers 📌 Ke
🔥 HCLTech is Hiring! 🔥 💻 Role: * Freshers Hiring / Off-Campus Drive * India 🎓 Eligibility: * Batch: 2026 * Freshers 📌 Key Requirements: * Good understanding of foundational software engineering concepts * Strong analytical and communication skills 👇 Click below to apply: 🔗 Application Link : https://freshers.hcltech.com/?utm_source=OffCampus&utm_medium=OffCampus_T1Institutions_Batch2026&utm_campaign=OffCampus_T1Institutions_Batch2026&utm_term=HCLTech 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📩 DM: @codemaster004

Wells Fargo ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons 📩 DM: @codemaster004
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Wells Fargo ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons 📩 DM: @codemaster004

import requests def findSpeedster(marathon, sex): url = f"https://jsonmock.hackerrank.com/api/marathon?sex={sex}" best_n = ""
+1
import requests def findSpeedster(marathon, sex): url = f"https://jsonmock.hackerrank.com/api/marathon?sex={sex}" best_n = "" best_s = -1.0 best_st = float('inf') curr_p = 1 total_p = 1 while curr_p <= total_p: resp = requests.get(f"{url}&page={curr_p}").json() if curr_p == 1: total_p = resp['total_pages'] for r in resp['data']: if r['marathon_name'] == marathon: s = float(r['top_speed']) st = int(r['stops_taken']) if s > best_s: best_s = s best_st = st best_n = r['name'] elif s == best_s: if st < best_st: best_st = st best_n = r['name'] curr_p += 1 return best_n IBM ✅ _ 💻 Live Coding | Projects | Interviews | OA & Hackathons Help 📩 DM: @codemaster004

def maximizePacketSum(packetSizes, k): n = len(packetSizes) if k > n: return -1 d = {} s = 0 m = -1 for i in range(n): v = pa
+1
def maximizePacketSum(packetSizes, k): n = len(packetSizes) if k > n: return -1 d = {} s = 0 m = -1 for i in range(n): v = packetSizes[i] s += v d[v] = d.get(v, 0) + 1 if i >= k: o = packetSizes[i - k] s -= o d[o] -= 1 if d[o] == 0: del d[o] if i >= k - 1: if len(d) == k: if s > m: m = s return m IBM ✅ ____ 💻 Live Coding | Projects | Interviews | OA & Hackathons Help 📩 DM: @codemaster004

#include #include using namespace std; bool c(const vector&amp; a, const vector&amp; b) { return a[0] &gt; b[0]; } int solve(
#include <vector> #include <algorithm> using namespace std; bool c(const vector<int>& a, const vector<int>& b) { return a[0] > b[0]; } int solve(int n, int t, vector<vector<int>>& d) { sort(d.begin(), d.end(), c); long long r = t; long long ans = 0; while (r > 0) { int p = -1; for (int i = 0; i < n; ++i) { if (d[i][1] > 0 && r % d[i][0] == 0) { p = i; break; } } if (p == -1) return -1; long long u = min(r / d[p][0], (long long)d[p][1]); r -= u * d[p][0]; ans += u; d[p][1] -= u; } return ans; } Infosys SP ✅ 🚨 Need Help with Coding? 💻 Live Coding | Projects | Interviews | OA & Hackathons 💯 Expert Assistance Available 📩 DM: @codemaster004

INFOSYS SP ✅ ━━━━━━━━━━━━━━━ 🚨 Need Help with Coding Exams, Projects, or Technical Interviews? 💯 Get Expert 1-on-1 Assistan
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INFOSYS SP ✅ ━━━━━━━━━━━━━━━ 🚨 Need Help with Coding Exams, Projects, or Technical Interviews? 💯 Get Expert 1-on-1 Assistance 📩 DM Now ➜ @codemaster004 ⚡ Live Coding Assessments ⚡ Online Assessments (OA) ⚡ Technical Interviews ⚡ Projects & Assignments ⚡ Hackathons & Coding Challenges

Amazon Hackathon ✅
+2
Amazon Hackathon ✅

#include #include using namespace std; vector p; int f(int x) { if (p[x] == x) return x; return p[x] = f(p[x]); } void m(int
#include <iostream> #include <vector> using namespace std; vector<int> p; int f(int x) { if (p[x] == x) return x; return p[x] = f(p[x]); } void m(int x, int y) { int rx = f(x); int ry = f(y); if (rx != ry) { p[rx] = ry; } } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n, q; if (cin >> n >> q) { p.resize(n + 1); for (int i = 0; i <= n; ++i) { p[i] = i; } for (int i = 0; i < q; ++i) { int l, r; cin >> l >> r; m(l - 1, r); } if (f(0) == f(n)) { cout << "Yes\n"; } else { cout << "No\n"; } } return 0; } Amazon Hackathon ✅

SELECT SUM(BALANCE) AS TOTAL_BALANCE, COUNT(ACCOUNT_ID) AS ACCOUNT_COUNT FROM ACCOUNTS WHERE ACCOUNT_TYPE = 'Savings' AND ACC
SELECT SUM(BALANCE) AS TOTAL_BALANCE, COUNT(ACCOUNT_ID) AS ACCOUNT_COUNT FROM ACCOUNTS WHERE ACCOUNT_TYPE = 'Savings' AND ACCOUNT_ID IN ( SELECT ACCOUNT_ID FROM TRANSACTIONS WHERE TRANSACTION_TYPE = 'Deposit' ); Amazon Hackathon ✅

This is literally the cheapest way to learn from top IITs while still in college! 🎓 Masai Unlimited now at ₹99/week - for a
This is literally the cheapest way to learn from top IITs while still in college! 🎓 Masai Unlimited now at ₹99/week - for a limited time only ⚡ ✅ AI, Data Science, ML, Product & more ⚡ iHub IIT Certifications 🤖 24×7 AI Tutor - ask doubts anytime 🌍 Learn in your Mother Tongue No excuses left. Your future’s worth ₹99/week. 🔥 Join before prices go up! 👉 Sign up NOW: https://tinyurl.com/masai-unlimited-registration

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This is literally the cheapest chance to learn from Top IITs while still in college! 🎓 Get Masai Unlimited & unlock: ✅ AI, Data Science, ML, Product Management & more ⚡ iHub IIT Certifications 🤖 24×7 AI Tutor — ask doubts anytime 🌍 Learn in YOUR language No excuses. ₹1 isn’t the barrier, your mindset is. 🔥 Don’t wait — this offer can expire anytime. 👉 Sign up NOW: https://tinyurl.com/masai-unlimited-registration

This is literally the cheapest chance to learn from Top IITs while still in college! 🎓 Get Masai Unlimited & unlock: ✅ AI, D
This is literally the cheapest chance to learn from Top IITs while still in college! 🎓 Get Masai Unlimited & unlock: ✅ AI, Data Science, ML, Product Management & more ⚡ iHub IIT Certifications 🤖 24×7 AI Tutor — ask doubts anytime 🌍 Learn in YOUR language No excuses. ₹1 isn’t the barrier, your mindset is. 🔥 Don’t wait — this offer can expire anytime. 👉 Sign up NOW: https://www.masaischool.com/unlimited

Accenture off Campus Drive Job Profile : Application Support Engineers 🎖 Eligibility : Any Bachelor's Degree 🎖Batch - 2023,
Accenture off Campus Drive Job Profile : Application Support Engineers 🎖 Eligibility : Any Bachelor's Degree 🎖Batch -  2023,  2024,  2025 ➡️ Detail Explanatin Video 👇 Youtube - https://youtube.com/@offcampusjobsindia?si=i0EsNHXL-OlG3GuL WhatsApp -  https://tinyurl.com/bdcr25cv Instagram   - https://www.instagram.com/offcampusjobsindia_it 🔗Apply Link        https://www.accenture.com/in-en/careers/jobdetails?id=ATCI-4817203-S1853038_en&title=Application+Support+Engineer