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CODING SOLUTION - Placement Jobs & Materials

CODING SOLUTION - Placement Jobs & Materials

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🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “ Contact Admin: Mail me for collab offcampusjobsindiaadmin@gmail.com instagram.com/offcampusjobsindia_it Our Website : www.offcampusjobsindia.com

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📈 Telegram kanali CODING SOLUTION - Placement Jobs & Materials analitikasi

CODING SOLUTION - Placement Jobs & Materials (@codingsolution_it) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 129 376 obunachidan iborat bo'lib, Karyera toifasida 152-o'rinni va Hindiston mintaqasida 1 684-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 129 376 obunachiga ega bo‘ldi.

24 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -889 ga, so‘nggi 24 soatda esa -37 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 1.39% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.44% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 793 marta ko‘riladi; birinchi sutkada odatda 565 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent t.me/codingsolution_it, vector, codevita, string, graduate kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “ Contact Admin: Mail me for collab offcampusjobsindiaadmin@gmail.com instagram.com/offcampusjobsindia_it Our Website : www.offcampusjobsindia.com”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 25 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Karyera toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

129 376
Obunachilar
-3724 soatlar
-5037 kun
-88930 kun
Postlar arxiv
#include <iostream> #include <vector> #include <algorithm> using namespace std; long long solve(int n, vector<vector<int>>& g) { if (n == 0) return 0; vector<vector<long long>> dp(n, vector<long long>(n, -2e18)); dp[0][0] = g[0][0]; for (int s = 1; s <= 2 * n - 2; ++s) { vector<vector<long long>> ndp(n, vector<long long>(n, -2e18)); int mn = max(0, s - n + 1); int mx = min(s, n - 1); for (int x1 = mn; x1 <= mx; ++x1) { for (int x2 = mn; x2 <= mx; ++x2) { int y1 = s - x1; int y2 = s - x2; long long prv = -2e18; if (x1 > 0 && x2 > 0) prv = max(prv, dp[x1 - 1][x2 - 1]); if (x1 > 0 && y2 > 0) prv = max(prv, dp[x1 - 1][x2]); if (y1 > 0 && x2 > 0) prv = max(prv, dp[x1][x2 - 1]); if (y1 > 0 && y2 > 0) prv = max(prv, dp[x1][x2]); if (prv != -2e18) { long long val = g[x1][y1]; if (x1 != x2) val += g[x2][y2]; ndp[x1][x2] = prv + val; } } } dp = ndp; } return dp[n - 1][n - 1]; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n; if (cin >> n) { vector<vector<int>> g(n, vector<int>(n)); for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { cin >> g[i][j]; } } auto result = solve(n, g); cout << result << "\n"; } return 0; } Infosys ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📢 DM @Codemaster004

#include #include using namespace std; bool chk(int m, int n, int k, const string&amp; o) { long long c = 0; int lst = 0; for
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#include <iostream> #include <string> using namespace std; bool chk(int m, int n, int k, const string& o) { long long c = 0; int lst = 0; for (int i = 0; i < n; ++i) { if (o[i] == '1') { int cur = i + 1; c += (cur - lst - 1) / m; lst = cur; } } c += (n + 1 - lst - 1) / m; return c <= k; } int solve(int n, int k, string o) { int l = 1, r = n + 1; int ans = r; while (l <= r) { int m = l + (r - l) / 2; if (chk(m, n, k, o)) { ans = m; r = m - 1; } else { l = m + 1; } } return ans; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n, k; if (cin >> n >> k) { string o; cin >> o; cout << solve(n, k, o) << "\n"; } return 0; } Infosys ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📢 DN @Codemaster004

import java.util.*; class Main { public static int solve(int n, int[] w1, int[] v1, int[] w2, int[] v2, int c) { int[] dp = new int[c + 1]; for (int i = 0; i < n; i++) { for (int w = c; w >= 0; w--) { int maxVal = dp[w]; if (w >= w1[i]) { maxVal = Math.max(maxVal, dp[w - w1[i]] + v1[i]); } if (w >= w2[i]) { maxVal = Math.max(maxVal, dp[w - w2[i]] + v2[i]); } dp[w] = maxVal; } } return dp[c]; } public static void main(String[] args) { Scanner sc = new Scanner(System.in); if (!sc.hasNextInt()) return; int n = sc.nextInt(); int[] w1 = new int[n]; for (int i = 0; i < n; i++) w1[i] = sc.nextInt(); int[] v1 = new int[n]; for (int i = 0; i < n; i++) v1[i] = sc.nextInt(); int[] w2 = new int[n]; for (int i = 0; i < n; i++) w2[i] = sc.nextInt(); int[] v2 = new int[n]; for (int i = 0; i < n; i++) v2[i] = sc.nextInt(); int c = sc.nextInt(); int result = solve(n, w1, v1, w2, v2, c); System.out.println(result); sc.close(); } } INFOSYS ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📢 DM @Codemaster004

🔥 HCLTech is Hiring! 🔥 💻 Role: * Freshers Hiring / Off-Campus Drive * India 🎓 Eligibility: * Batch: 2026 * Freshers 📌 Ke
🔥 HCLTech is Hiring! 🔥 💻 Role: * Freshers Hiring / Off-Campus Drive * India 🎓 Eligibility: * Batch: 2026 * Freshers 📌 Key Requirements: * Good understanding of foundational software engineering concepts * Strong analytical and communication skills 👇 Click below to apply: 🔗 Application Link : https://freshers.hcltech.com/?utm_source=OffCampus&utm_medium=OffCampus_T1Institutions_Batch2026&utm_campaign=OffCampus_T1Institutions_Batch2026&utm_term=HCLTech 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📩 DM: @codemaster004

Wells Fargo ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons 📩 DM: @codemaster004
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Wells Fargo ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons 📩 DM: @codemaster004

import requests def findSpeedster(marathon, sex): url = f"https://jsonmock.hackerrank.com/api/marathon?sex={sex}" best_n = ""
+1
import requests def findSpeedster(marathon, sex): url = f"https://jsonmock.hackerrank.com/api/marathon?sex={sex}" best_n = "" best_s = -1.0 best_st = float('inf') curr_p = 1 total_p = 1 while curr_p <= total_p: resp = requests.get(f"{url}&page={curr_p}").json() if curr_p == 1: total_p = resp['total_pages'] for r in resp['data']: if r['marathon_name'] == marathon: s = float(r['top_speed']) st = int(r['stops_taken']) if s > best_s: best_s = s best_st = st best_n = r['name'] elif s == best_s: if st < best_st: best_st = st best_n = r['name'] curr_p += 1 return best_n IBM ✅ _ 💻 Live Coding | Projects | Interviews | OA & Hackathons Help 📩 DM: @codemaster004

def maximizePacketSum(packetSizes, k): n = len(packetSizes) if k > n: return -1 d = {} s = 0 m = -1 for i in range(n): v = pa
+1
def maximizePacketSum(packetSizes, k): n = len(packetSizes) if k > n: return -1 d = {} s = 0 m = -1 for i in range(n): v = packetSizes[i] s += v d[v] = d.get(v, 0) + 1 if i >= k: o = packetSizes[i - k] s -= o d[o] -= 1 if d[o] == 0: del d[o] if i >= k - 1: if len(d) == k: if s > m: m = s return m IBM ✅ ____ 💻 Live Coding | Projects | Interviews | OA & Hackathons Help 📩 DM: @codemaster004

#include #include using namespace std; bool c(const vector&amp; a, const vector&amp; b) { return a[0] &gt; b[0]; } int solve(
#include <vector> #include <algorithm> using namespace std; bool c(const vector<int>& a, const vector<int>& b) { return a[0] > b[0]; } int solve(int n, int t, vector<vector<int>>& d) { sort(d.begin(), d.end(), c); long long r = t; long long ans = 0; while (r > 0) { int p = -1; for (int i = 0; i < n; ++i) { if (d[i][1] > 0 && r % d[i][0] == 0) { p = i; break; } } if (p == -1) return -1; long long u = min(r / d[p][0], (long long)d[p][1]); r -= u * d[p][0]; ans += u; d[p][1] -= u; } return ans; } Infosys SP ✅ 🚨 Need Help with Coding? 💻 Live Coding | Projects | Interviews | OA & Hackathons 💯 Expert Assistance Available 📩 DM: @codemaster004

INFOSYS SP ✅ ━━━━━━━━━━━━━━━ 🚨 Need Help with Coding Exams, Projects, or Technical Interviews? 💯 Get Expert 1-on-1 Assistan
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INFOSYS SP ✅ ━━━━━━━━━━━━━━━ 🚨 Need Help with Coding Exams, Projects, or Technical Interviews? 💯 Get Expert 1-on-1 Assistance 📩 DM Now ➜ @codemaster004 ⚡ Live Coding Assessments ⚡ Online Assessments (OA) ⚡ Technical Interviews ⚡ Projects & Assignments ⚡ Hackathons & Coding Challenges

Amazon Hackathon ✅
+2
Amazon Hackathon ✅

#include #include using namespace std; vector p; int f(int x) { if (p[x] == x) return x; return p[x] = f(p[x]); } void m(int
#include <iostream> #include <vector> using namespace std; vector<int> p; int f(int x) { if (p[x] == x) return x; return p[x] = f(p[x]); } void m(int x, int y) { int rx = f(x); int ry = f(y); if (rx != ry) { p[rx] = ry; } } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n, q; if (cin >> n >> q) { p.resize(n + 1); for (int i = 0; i <= n; ++i) { p[i] = i; } for (int i = 0; i < q; ++i) { int l, r; cin >> l >> r; m(l - 1, r); } if (f(0) == f(n)) { cout << "Yes\n"; } else { cout << "No\n"; } } return 0; } Amazon Hackathon ✅

SELECT SUM(BALANCE) AS TOTAL_BALANCE, COUNT(ACCOUNT_ID) AS ACCOUNT_COUNT FROM ACCOUNTS WHERE ACCOUNT_TYPE = 'Savings' AND ACC
SELECT SUM(BALANCE) AS TOTAL_BALANCE, COUNT(ACCOUNT_ID) AS ACCOUNT_COUNT FROM ACCOUNTS WHERE ACCOUNT_TYPE = 'Savings' AND ACCOUNT_ID IN ( SELECT ACCOUNT_ID FROM TRANSACTIONS WHERE TRANSACTION_TYPE = 'Deposit' ); Amazon Hackathon ✅

This is literally the cheapest way to learn from top IITs while still in college! 🎓 Masai Unlimited now at ₹99/week - for a
This is literally the cheapest way to learn from top IITs while still in college! 🎓 Masai Unlimited now at ₹99/week - for a limited time only ⚡ ✅ AI, Data Science, ML, Product & more ⚡ iHub IIT Certifications 🤖 24×7 AI Tutor - ask doubts anytime 🌍 Learn in your Mother Tongue No excuses left. Your future’s worth ₹99/week. 🔥 Join before prices go up! 👉 Sign up NOW: https://tinyurl.com/masai-unlimited-registration

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This is literally the cheapest chance to learn from Top IITs while still in college! 🎓 Get Masai Unlimited & unlock: ✅ AI, Data Science, ML, Product Management & more ⚡ iHub IIT Certifications 🤖 24×7 AI Tutor — ask doubts anytime 🌍 Learn in YOUR language No excuses. ₹1 isn’t the barrier, your mindset is. 🔥 Don’t wait — this offer can expire anytime. 👉 Sign up NOW: https://tinyurl.com/masai-unlimited-registration

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This is literally the cheapest chance to learn from Top IITs while still in college! 🎓 Get Masai Unlimited & unlock: ✅ AI, Data Science, ML, Product Management & more ⚡ iHub IIT Certifications 🤖 24×7 AI Tutor — ask doubts anytime 🌍 Learn in YOUR language No excuses. ₹1 isn’t the barrier, your mindset is. 🔥 Don’t wait — this offer can expire anytime. 👉 Sign up NOW: https://www.masaischool.com/unlimited

Accenture off Campus Drive Job Profile : Application Support Engineers 🎖 Eligibility : Any Bachelor's Degree 🎖Batch - 2023,
Accenture off Campus Drive Job Profile : Application Support Engineers 🎖 Eligibility : Any Bachelor's Degree 🎖Batch -  2023,  2024,  2025 ➡️ Detail Explanatin Video 👇 Youtube - https://youtube.com/@offcampusjobsindia?si=i0EsNHXL-OlG3GuL WhatsApp -  https://tinyurl.com/bdcr25cv Instagram   - https://www.instagram.com/offcampusjobsindia_it 🔗Apply Link        https://www.accenture.com/in-en/careers/jobdetails?id=ATCI-4817203-S1853038_en&title=Application+Support+Engineer