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CODING SOLUTION - Placement Jobs & Materials

CODING SOLUTION - Placement Jobs & Materials

前往频道在 Telegram

🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “ Contact Admin: Mail me for collab offcampusjobsindiaadmin@gmail.com instagram.com/offcampusjobsindia_it Our Website : www.offcampusjobsindia.com

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📈 Telegram 频道 CODING SOLUTION - Placement Jobs & Materials 的分析概览

频道 CODING SOLUTION - Placement Jobs & Materials (@codingsolution_it) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 129 376 名订阅者,在 职业 类别中位列第 152,并在 印度 地区排名第 1 684 位。

📊 受众指标与增长动态

自 невідомо 创建以来,项目保持高速增长,吸引了 129 376 名订阅者。

根据 24 十月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -889,过去 24 小时变化为 -37,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 1.39%。内容发布后 24 小时内通常能获得 0.44% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 1 793 次浏览,首日通常累积 565 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 0。
  • 主题关注点: 内容集中在 t.me/codingsolution_it, vector, codevita, string, graduate 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
“🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “ Contact Admin: Mail me for collab offcampusjobsindiaadmin@gmail.com instagram.com/offcampusjobsindia_it Our Website : www.offcampusjobsindia.com”

凭借高频更新(最新数据采集于 25 十月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 职业 类别中的关键影响点。

129 376
订阅者
-3724 小时
-5037 天
-88930 天
帖子存档
#include <iostream> #include <vector> #include <algorithm> using namespace std; long long solve(int n, vector<vector<int>>& g) { if (n == 0) return 0; vector<vector<long long>> dp(n, vector<long long>(n, -2e18)); dp[0][0] = g[0][0]; for (int s = 1; s <= 2 * n - 2; ++s) { vector<vector<long long>> ndp(n, vector<long long>(n, -2e18)); int mn = max(0, s - n + 1); int mx = min(s, n - 1); for (int x1 = mn; x1 <= mx; ++x1) { for (int x2 = mn; x2 <= mx; ++x2) { int y1 = s - x1; int y2 = s - x2; long long prv = -2e18; if (x1 > 0 && x2 > 0) prv = max(prv, dp[x1 - 1][x2 - 1]); if (x1 > 0 && y2 > 0) prv = max(prv, dp[x1 - 1][x2]); if (y1 > 0 && x2 > 0) prv = max(prv, dp[x1][x2 - 1]); if (y1 > 0 && y2 > 0) prv = max(prv, dp[x1][x2]); if (prv != -2e18) { long long val = g[x1][y1]; if (x1 != x2) val += g[x2][y2]; ndp[x1][x2] = prv + val; } } } dp = ndp; } return dp[n - 1][n - 1]; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n; if (cin >> n) { vector<vector<int>> g(n, vector<int>(n)); for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { cin >> g[i][j]; } } auto result = solve(n, g); cout << result << "\n"; } return 0; } Infosys ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📢 DM @Codemaster004

#include #include using namespace std; bool chk(int m, int n, int k, const string&amp; o) { long long c = 0; int lst = 0; for
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#include <iostream> #include <string> using namespace std; bool chk(int m, int n, int k, const string& o) { long long c = 0; int lst = 0; for (int i = 0; i < n; ++i) { if (o[i] == '1') { int cur = i + 1; c += (cur - lst - 1) / m; lst = cur; } } c += (n + 1 - lst - 1) / m; return c <= k; } int solve(int n, int k, string o) { int l = 1, r = n + 1; int ans = r; while (l <= r) { int m = l + (r - l) / 2; if (chk(m, n, k, o)) { ans = m; r = m - 1; } else { l = m + 1; } } return ans; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n, k; if (cin >> n >> k) { string o; cin >> o; cout << solve(n, k, o) << "\n"; } return 0; } Infosys ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📢 DN @Codemaster004

import java.util.*; class Main { public static int solve(int n, int[] w1, int[] v1, int[] w2, int[] v2, int c) { int[] dp = new int[c + 1]; for (int i = 0; i < n; i++) { for (int w = c; w >= 0; w--) { int maxVal = dp[w]; if (w >= w1[i]) { maxVal = Math.max(maxVal, dp[w - w1[i]] + v1[i]); } if (w >= w2[i]) { maxVal = Math.max(maxVal, dp[w - w2[i]] + v2[i]); } dp[w] = maxVal; } } return dp[c]; } public static void main(String[] args) { Scanner sc = new Scanner(System.in); if (!sc.hasNextInt()) return; int n = sc.nextInt(); int[] w1 = new int[n]; for (int i = 0; i < n; i++) w1[i] = sc.nextInt(); int[] v1 = new int[n]; for (int i = 0; i < n; i++) v1[i] = sc.nextInt(); int[] w2 = new int[n]; for (int i = 0; i < n; i++) w2[i] = sc.nextInt(); int[] v2 = new int[n]; for (int i = 0; i < n; i++) v2[i] = sc.nextInt(); int c = sc.nextInt(); int result = solve(n, w1, v1, w2, v2, c); System.out.println(result); sc.close(); } } INFOSYS ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📢 DM @Codemaster004

🔥 HCLTech is Hiring! 🔥 💻 Role: * Freshers Hiring / Off-Campus Drive * India 🎓 Eligibility: * Batch: 2026 * Freshers 📌 Ke
🔥 HCLTech is Hiring! 🔥 💻 Role: * Freshers Hiring / Off-Campus Drive * India 🎓 Eligibility: * Batch: 2026 * Freshers 📌 Key Requirements: * Good understanding of foundational software engineering concepts * Strong analytical and communication skills 👇 Click below to apply: 🔗 Application Link : https://freshers.hcltech.com/?utm_source=OffCampus&utm_medium=OffCampus_T1Institutions_Batch2026&utm_campaign=OffCampus_T1Institutions_Batch2026&utm_term=HCLTech 💻 Live Coding Test | Projects | Interviews | OA & Hackathons Help 📩 DM: @codemaster004

Wells Fargo ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons 📩 DM: @codemaster004
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Wells Fargo ✅ 💻 Live Coding Test | Projects | Interviews | OA & Hackathons 📩 DM: @codemaster004

import requests def findSpeedster(marathon, sex): url = f"https://jsonmock.hackerrank.com/api/marathon?sex={sex}" best_n = ""
+1
import requests def findSpeedster(marathon, sex): url = f"https://jsonmock.hackerrank.com/api/marathon?sex={sex}" best_n = "" best_s = -1.0 best_st = float('inf') curr_p = 1 total_p = 1 while curr_p <= total_p: resp = requests.get(f"{url}&page={curr_p}").json() if curr_p == 1: total_p = resp['total_pages'] for r in resp['data']: if r['marathon_name'] == marathon: s = float(r['top_speed']) st = int(r['stops_taken']) if s > best_s: best_s = s best_st = st best_n = r['name'] elif s == best_s: if st < best_st: best_st = st best_n = r['name'] curr_p += 1 return best_n IBM ✅ _ 💻 Live Coding | Projects | Interviews | OA & Hackathons Help 📩 DM: @codemaster004

def maximizePacketSum(packetSizes, k): n = len(packetSizes) if k > n: return -1 d = {} s = 0 m = -1 for i in range(n): v = pa
+1
def maximizePacketSum(packetSizes, k): n = len(packetSizes) if k > n: return -1 d = {} s = 0 m = -1 for i in range(n): v = packetSizes[i] s += v d[v] = d.get(v, 0) + 1 if i >= k: o = packetSizes[i - k] s -= o d[o] -= 1 if d[o] == 0: del d[o] if i >= k - 1: if len(d) == k: if s > m: m = s return m IBM ✅ ____ 💻 Live Coding | Projects | Interviews | OA & Hackathons Help 📩 DM: @codemaster004

#include #include using namespace std; bool c(const vector&amp; a, const vector&amp; b) { return a[0] &gt; b[0]; } int solve(
#include <vector> #include <algorithm> using namespace std; bool c(const vector<int>& a, const vector<int>& b) { return a[0] > b[0]; } int solve(int n, int t, vector<vector<int>>& d) { sort(d.begin(), d.end(), c); long long r = t; long long ans = 0; while (r > 0) { int p = -1; for (int i = 0; i < n; ++i) { if (d[i][1] > 0 && r % d[i][0] == 0) { p = i; break; } } if (p == -1) return -1; long long u = min(r / d[p][0], (long long)d[p][1]); r -= u * d[p][0]; ans += u; d[p][1] -= u; } return ans; } Infosys SP ✅ 🚨 Need Help with Coding? 💻 Live Coding | Projects | Interviews | OA & Hackathons 💯 Expert Assistance Available 📩 DM: @codemaster004

INFOSYS SP ✅ ━━━━━━━━━━━━━━━ 🚨 Need Help with Coding Exams, Projects, or Technical Interviews? 💯 Get Expert 1-on-1 Assistan
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INFOSYS SP ✅ ━━━━━━━━━━━━━━━ 🚨 Need Help with Coding Exams, Projects, or Technical Interviews? 💯 Get Expert 1-on-1 Assistance 📩 DM Now ➜ @codemaster004 ⚡ Live Coding Assessments ⚡ Online Assessments (OA) ⚡ Technical Interviews ⚡ Projects & Assignments ⚡ Hackathons & Coding Challenges

Amazon Hackathon ✅
+2
Amazon Hackathon ✅

#include #include using namespace std; vector p; int f(int x) { if (p[x] == x) return x; return p[x] = f(p[x]); } void m(int
#include <iostream> #include <vector> using namespace std; vector<int> p; int f(int x) { if (p[x] == x) return x; return p[x] = f(p[x]); } void m(int x, int y) { int rx = f(x); int ry = f(y); if (rx != ry) { p[rx] = ry; } } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n, q; if (cin >> n >> q) { p.resize(n + 1); for (int i = 0; i <= n; ++i) { p[i] = i; } for (int i = 0; i < q; ++i) { int l, r; cin >> l >> r; m(l - 1, r); } if (f(0) == f(n)) { cout << "Yes\n"; } else { cout << "No\n"; } } return 0; } Amazon Hackathon ✅

SELECT SUM(BALANCE) AS TOTAL_BALANCE, COUNT(ACCOUNT_ID) AS ACCOUNT_COUNT FROM ACCOUNTS WHERE ACCOUNT_TYPE = 'Savings' AND ACC
SELECT SUM(BALANCE) AS TOTAL_BALANCE, COUNT(ACCOUNT_ID) AS ACCOUNT_COUNT FROM ACCOUNTS WHERE ACCOUNT_TYPE = 'Savings' AND ACCOUNT_ID IN ( SELECT ACCOUNT_ID FROM TRANSACTIONS WHERE TRANSACTION_TYPE = 'Deposit' ); Amazon Hackathon ✅

This is literally the cheapest way to learn from top IITs while still in college! 🎓 Masai Unlimited now at ₹99/week - for a
This is literally the cheapest way to learn from top IITs while still in college! 🎓 Masai Unlimited now at ₹99/week - for a limited time only ⚡ ✅ AI, Data Science, ML, Product & more ⚡ iHub IIT Certifications 🤖 24×7 AI Tutor - ask doubts anytime 🌍 Learn in your Mother Tongue No excuses left. Your future’s worth ₹99/week. 🔥 Join before prices go up! 👉 Sign up NOW: https://tinyurl.com/masai-unlimited-registration

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This is literally the cheapest chance to learn from Top IITs while still in college! 🎓 Get Masai Unlimited & unlock: ✅ AI, Data Science, ML, Product Management & more ⚡ iHub IIT Certifications 🤖 24×7 AI Tutor — ask doubts anytime 🌍 Learn in YOUR language No excuses. ₹1 isn’t the barrier, your mindset is. 🔥 Don’t wait — this offer can expire anytime. 👉 Sign up NOW: https://tinyurl.com/masai-unlimited-registration

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This is literally the cheapest chance to learn from Top IITs while still in college! 🎓 Get Masai Unlimited & unlock: ✅ AI, Data Science, ML, Product Management & more ⚡ iHub IIT Certifications 🤖 24×7 AI Tutor — ask doubts anytime 🌍 Learn in YOUR language No excuses. ₹1 isn’t the barrier, your mindset is. 🔥 Don’t wait — this offer can expire anytime. 👉 Sign up NOW: https://www.masaischool.com/unlimited

Accenture off Campus Drive Job Profile : Application Support Engineers 🎖 Eligibility : Any Bachelor's Degree 🎖Batch - 2023,
Accenture off Campus Drive Job Profile : Application Support Engineers 🎖 Eligibility : Any Bachelor's Degree 🎖Batch -  2023,  2024,  2025 ➡️ Detail Explanatin Video 👇 Youtube - https://youtube.com/@offcampusjobsindia?si=i0EsNHXL-OlG3GuL WhatsApp -  https://tinyurl.com/bdcr25cv Instagram   - https://www.instagram.com/offcampusjobsindia_it 🔗Apply Link        https://www.accenture.com/in-en/careers/jobdetails?id=ATCI-4817203-S1853038_en&title=Application+Support+Engineer