OSSSC / OSSC MATH AND REASONING

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𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

Network:ଓଡ଼ିଆ ବ୍ୟାକରଣ India33 653 Education17 127...

📈 Analytical overview of Telegram channel OSSSC / OSSC MATH AND REASONING

Channel OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) in the English language segment is an active participant. Currently, the community unites 11 492 subscribers, ranking 17 127 in the Education category and 33 653 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 11 492 subscribers.

According to the latest data from 14 September, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 221 over the last 30 days and by -2 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 11.68%. Within the first 24 hours after publication, content typically collects 5.33% reactions from the total number of subscribers.
Post reach: On average, each post receives 1 342 views. Within the first day, a publication typically gains 612 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 1.
Thematic interests: Content is focused on key topics such as ʜᴇʀᴇ, cgle, cgl, mcqs, mcq.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”

Thanks to the high frequency of updates (latest data received on 15 September, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

11 492

Subscribers

-224 hours

+547 days

+22130 days

1 342

Post views

~ 61224 hours

~ 75148 hours

11.68%

Engagement rate

~ 1

Posts per day

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Posts Archive

11 492

Let the numbers be x and y respectively. According to the question, x + y = 50..........(i) xy = 525 (x + y)2 – 4xy = (x – y)2 (50)2 – 4 × 525 = (x – y)2 2500 – 2100 = (x – y)2 (x – y)2 = 400 x – y = 20 .........(ii) From equation (i) and (ii), x + y = 50 x – y = 20 2x = 70 x = 35 On putting the x = 35 value of x in equation (i), y = 50 – 35 y = 15 LCM of 15 and 35 = 3 × 5 × 7 = 105

11 492

The sum of two number is 50 and their product is 525. The LCM of the two numbers is:

Anonymous voting

11 492

.(a) Given that – Two prime number = A, B LCM of number = 209 According to the question, ∵ HCF of two prime number = 1 ∴ Product of number = LCM × HCF ⇒ A × B = 209 ×1 ⇒ A × B = 19 × 11 Where, A = 19 {∵ A > B } B = 11 ∴ A2 – B = 192 – 11 = 361 – 11 = 350

11 492

A and B are two prime numbers such that A > B and their LCM is 209. The value of A2 – B is:

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11 492

What is the LCM of 3.6, 1.8 and 0.144?

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11 492

Find the smallest number which should be added to the smallest number divisible by 6, 9 and 15 to make it a perfect square.

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11 492

Which is the largest six digit number, which when divided by 12, 15, 20, 24 and 30 leaves the remainder 8, 11, 16, 20 and 26 respectively:

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11 492

𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤIf the time in clock is 12: 23. What is the time in mirror?

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11 492

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11 492

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11 492

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11 492

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11 492

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11 492

The greatest number by which 2300 and 3500 are divided leaving the remainders of 32 and 56 respectively is

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11 492

Which is the least number of square tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?

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11 492

The number between 4000 and 5000 that is divisible by each of 12, 18, 21 and 32 is

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11 492

The largest number, which divides 25, 73 and 97 to leave the same remainder in each case is

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