OSSSC / OSSC MATH AND REASONING
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11 492
Obunachilar
-224 soatlar
+547 kun
+22130 kun
Postlar arxiv
Let the numbers be x and y respectively.
According to the question,
x + y = 50..........(i)
xy = 525
(x + y)2
– 4xy = (x – y)2
(50)2
– 4 × 525 = (x – y)2
2500 – 2100 = (x – y)2
(x – y)2
= 400
x – y = 20 .........(ii)
From equation (i) and (ii),
x + y = 50
x – y = 20
2x = 70
x = 35
On putting the x = 35 value of x in equation (i),
y = 50 – 35
y = 15
LCM of 15 and 35 = 3 × 5 × 7
= 105
The sum of two number is 50 and their product is 525. The LCM of the two numbers is:
.(a) Given that –
Two prime number = A, B
LCM of number = 209
According to the question, ∵ HCF of two prime number = 1
∴ Product of number = LCM × HCF
⇒ A × B = 209 ×1
⇒ A × B = 19 × 11
Where, A = 19 {∵ A > B }
B = 11
∴ A2
– B = 192
– 11
= 361 – 11
= 350
A and B are two prime numbers such that A > B and their LCM is 209. The value of A2 – B is:
Find the smallest number which should be added to the smallest number divisible by 6, 9 and 15 to make it a perfect square.
Which is the largest six digit number, which when divided by 12, 15, 20, 24 and 30 leaves the remainder 8, 11, 16, 20 and 26 respectively:
𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤIf the time in clock is 12: 23. What is the time in mirror?
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