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OSSSC / OSSC MATH AND REASONING

OSSSC / OSSC MATH AND REASONING

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📈 Análisis del canal de Telegram OSSSC / OSSC MATH AND REASONING

El canal OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 11 492 suscriptores, ocupando la posición 17 127 en la categoría Educación y el puesto 33 653 en la región India.

📊 Métricas de audiencia y dinámica

Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 11 492 suscriptores.

Según los últimos datos del 14 septiembre, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de 221, y en las últimas 24 horas de -2, conservando un alto alcance.

  • Estado de verificación: No verificado
  • Tasa de interacción (ER): El promedio de interacción de la audiencia es 11.68%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 5.33% de reacciones respecto al total de suscriptores.
  • Alcance de las publicaciones: Cada publicación recibe en promedio 1 342 visualizaciones. En el primer día suele acumular 612 visualizaciones.
  • Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 1.
  • Intereses temáticos: El contenido se centra en temas clave como ʜᴇʀᴇ, cgle, cgl, mcqs, mcq.

📝 Descripción y política de contenido

El autor describe el recurso como un espacio para expresar opiniones subjetivas:
𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 15 septiembre, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Educación.

11 492
Suscriptores
-224 horas
+547 días
+22130 días
Archivo de publicaciones
Let the numbers be x and y respectively. According to the question, x + y = 50..........(i) xy = 525 (x + y)2 – 4xy = (x – y)2 (50)2 – 4 × 525 = (x – y)2 2500 – 2100 = (x – y)2 (x – y)2 = 400 x – y = 20 .........(ii) From equation (i) and (ii), x + y = 50 x – y = 20 2x = 70 x = 35 On putting the x = 35 value of x in equation (i), y = 50 – 35 y = 15 LCM of 15 and 35 = 3 × 5 × 7 = 105

The sum of two number is 50 and their product is 525. The LCM of the two numbers is:
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.(a) Given that – Two prime number = A, B LCM of number = 209 According to the question, ∵ HCF of two prime number = 1 ∴ Product of number = LCM × HCF ⇒ A × B = 209 ×1 ⇒ A × B = 19 × 11 Where, A = 19 {∵ A > B } B = 11 ∴ A2 – B = 192 – 11 = 361 – 11 = 350

A and B are two prime numbers such that A > B and their LCM is 209. The value of A2 – B is:
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What is the LCM of 3.6, 1.8 and 0.144?
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Find the smallest number which should be added to the smallest number divisible by 6, 9 and 15 to make it a perfect square.
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Which is the largest six digit number, which when divided by 12, 15, 20, 24 and 30 leaves the remainder 8, 11, 16, 20 and 26 respectively:
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𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤIf the time in clock is 12: 23. What is the time in mirror?
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The greatest number by which 2300 and 3500 are divided leaving the remainders of 32 and 56 respectively is
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Which is the least number of square tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
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The number between 4000 and 5000 that is divisible by each of 12, 18, 21 and 32 is
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The largest number, which divides 25, 73 and 97 to leave the same remainder in each case is
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