OSSSC / OSSC MATH AND REASONING

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𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

Network:ଓଡ଼ିଆ ବ୍ୟାକରଣ India33 552 Education17 095...

📈 Analytical overview of Telegram channel OSSSC / OSSC MATH AND REASONING

Channel OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) in the English language segment is an active participant. Currently, the community unites 11 515 subscribers, ranking 17 095 in the Education category and 33 552 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 11 515 subscribers.

According to the latest data from 20 September, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 202 over the last 30 days and by 8 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 13.83%. Within the first 24 hours after publication, content typically collects 5.66% reactions from the total number of subscribers.
Post reach: On average, each post receives 1 590 views. Within the first day, a publication typically gains 651 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 1.
Thematic interests: Content is focused on key topics such as ʜᴇʀᴇ, cgle, cgl, mcqs, mcq.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”

Thanks to the high frequency of updates (latest data received on 21 September, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

11 515

Subscribers

+824 hours

+57 days

+20230 days

1 590

Post views

~ 65124 hours

~ 81448 hours

13.83%

Engagement rate

~ 1

Posts per day

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14 : 56 :: 44 : ?

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Q- √0.0081 = ?

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PARLIAMENT MCQ Lok Sabha And Rajyasabha MCQ POLITY IMPORTANT PYQ Watch here 👇👇 https://youtu.be/zaUGjmwhuPw?si=HlcUBeqrz5C_4byw

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Important MCQ ON PRESIDENT AND VICE PRESIDENT OF INDIA POLITY MCQ WATCH here 👇 https://youtu.be/8IbGrK4LFE0?si=BapgKl-nwYF8c6XK

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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA, B, C together invest Rs.50, 000 for a business. A invests Rs.4,000 more than B and B invests Rs.5,000 more than C. Out of a total profit of Rs.35,000, what is the share of A ?

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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA certain sum on compound interest becomes ₹56,180 when compounded annually after 2 years and ₹59,550.80 after 3 years. Find the sum (in ₹).

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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA certain sum on compound interest becomes 256,180, when compounded annually after 2 years and 59550. 80 after 3 years. Find the sum (in ).

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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA temple has five bells which ring at intervals of 12, 15,16, 20 and 25 minutes respectively. If they ring together at midnight, then at what time next will they ring together ?

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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤThe smallest five digit number which is divisible by 12, 18 and 21 is:

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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA man plants 5184 orange trees in his garden and arranges them so that there are as many rows as there are orange trees in a row. How many rows are there in the garden ?

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🔥 ODISHA POLICE SI EXAM 🔥 🔥OSSC CGLE 🔥 All IN ONE BATCH Key Features: 📝 Daily Topic-wise MCQs (300+) 📚 Complete Syllabus Coverage 📖 Class Notes & Study Material 📝 Weekly Tests & Full Mock Tests 🎙 Voice Discussions 💥 Price: ₹149/- 🚨 For Serious Aspirants Only! ⚡ No casual inquiries, please. 📲 Contact: @bunnytapas Scew exam check what we do what questions asked for 😍

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35-60 ALL DI QUESTION ANS SET A SCEW EXAM 31. 27% (Percentage increase in production from 2009 to 2010) 32. 73% (Sales of company A in 2009 as a percentage of its production) 33. 649 (Average production of company B from 2006 to 2011) 34. 81:55 (Total production ratio of A to total sales of A) 35. 3:4 (Ratio of production of company B in 2006 to 2008) 36. 289:42 37. 34% 38. 14.46% 39. F (City with the highest number of failing students) 40. 11000 41. 1700 42. 45:7:87 43. 880 44. C 45. 35% 46. 70 crore rupees 47. 90 crore rupees 48. 2006 49. 41% 50. 8% 51. 2007 52. 2009 53. Rs 71.5 lakhs 54. 45% 55. 2008 56. 12.1% 57. 75% 58. 37.1% 59. Rs 8000000 60. Rs 450000

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ALL 30 QUESTIONS SET A SCEW EXAM MATH 1. 72 (√5184 = 72) 2. 30256 (LCM of 12, 18, and 21 = 252, smallest multiple in 5 digits = 30256) 3. 8:30 PM (LCM of 12, 15, 16, 20, 25 = 240 min = 4 hours) 4. 50000 (Using compound interest formula) 5. 1:2 (Solving for the required ratio) 6. 0.3125 7. Rs. 18 (Solving mistake in fraction division) 8. Rs. 13,000 (Investment and profit-sharing ratio) 9. 10 hours (Using work and time concepts) 10. 16 km (Using speed-distance-time equation) 11. 5% (Calculating gain with simple interest) 12. 2 ¼ times (Solving age-based ratio equation) 13. 81 (Checking given conditions for digits sum property) 14. 600 (Applying percentage concepts) 15. 1.5 liters (Mixture and alligation concept) 16. 44 (LCM-based time calculation) 17. 15:8 (Ratio-based simplification) 18. 8% (Using simple interest formula) 19. 45 (Finding a two-digit number with reversed sum condition) 20. 204 (Next four even numbers sum = 180 + 24) 21. 3 (For divisibility by 9, sum of digits must be a multiple of 9) 22. 5 (Solving for number of 2-mark questions correctly attempted) 23. Rs. 250 (Reverse calculation of successive discounts) 24. 11:19 (Solving for savings ratio using income and expenditure ratio) 25. Rs. 4280 (Partnership profit-sharing calculation) 26. 9 km/hr (Using relaPERCENTAGE formula in still water) 27. 108 (Scaling typing speed to 6 minutes) 28. 1250 (Using percentage formula to find total candidates) 29. 25 (Setting up cost equations and solving for number of balls) 30. 200 (Using proportion method for food distribution) Join- https://shorturl.at/Ulwjw