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OSSSC / OSSC MATH AND REASONING

OSSSC / OSSC MATH AND REASONING

前往频道在 Telegram

𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

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📈 Telegram 频道 OSSSC / OSSC MATH AND REASONING 的分析概览

频道 OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 11 518 名订阅者,在 教育 类别中位列第 17 080,并在 印度 地区排名第 33 491

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 11 518 名订阅者。

根据 21 九月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 210,过去 24 小时变化为 16,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 15.56%。内容发布后 24 小时内通常能获得 5.83% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 1 792 次浏览,首日通常累积 671 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 2
  • 主题关注点: 内容集中在 ʜᴇʀᴇ, cgle, cgl, mcqs, mcq 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

凭借高频更新(最新数据采集于 22 九月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

11 518
订阅者
+1624 小时
+237 天
+21030 天
帖子存档
14 : 56 :: 44 : ?
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13 : 39 :: 20 : ?
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11 : 11 : 24 : ?
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12 : 24 :: 36 : ?
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50 : 60 :: 75 : ?
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220 : 219 :: 100 : ?
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50 : 43 :: 65 : ?
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67 : 70 :: 58 : ?
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Q- √0.0081 = ?
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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA, B, C together invest Rs.50, 000 for a business. A invests Rs.4,000 more than B and B invests Rs.5,000 more than C. Out of a total profit of Rs.35,000, what is the share of A ?
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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA certain sum on compound interest becomes ₹56,180 when compounded annually after 2 years and ₹59,550.80 after 3 years. Find the sum (in ₹).
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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA certain sum on compound interest becomes 256,180, when compounded annually after 2 years and 59550. 80 after 3 years. Find the sum (in ).
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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA temple has five bells which ring at intervals of 12, 15,16, 20 and 25 minutes respectively. If they ring together at midnight, then at what time next will they ring together ?
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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤThe smallest five digit number which is divisible by 12, 18 and 21 is:
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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA man plants 5184 orange trees in his garden and arranges them so that there are as many rows as there are orange trees in a row. How many rows are there in the garden ?
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ALL 30 QUESTIONS SET A SCEW EXAM MATH 1. 72 (√5184 = 72) 2. 30256 (LCM of 12, 18, and 21 = 252, smallest multiple in 5 digits = 30256) 3. 8:30 PM (LCM of 12, 15, 16, 20, 25 = 240 min = 4 hours) 4. 50000 (Using compound interest formula) 5. 1:2 (Solving for the required ratio) 6. 0.3125 7. Rs. 18 (Solving mistake in fraction division) 8. Rs. 13,000 (Investment and profit-sharing ratio) 9. 10 hours (Using work and time concepts) 10. 16 km (Using speed-distance-time equation) 11. 5% (Calculating gain with simple interest) 12. 2 ¼ times (Solving age-based ratio equation) 13. 81 (Checking given conditions for digits sum property) 14. 600 (Applying percentage concepts) 15. 1.5 liters (Mixture and alligation concept) 16. 44 (LCM-based time calculation) 17. 15:8 (Ratio-based simplification) 18. 8% (Using simple interest formula) 19. 45 (Finding a two-digit number with reversed sum condition) 20. 204 (Next four even numbers sum = 180 + 24) 21. 3 (For divisibility by 9, sum of digits must be a multiple of 9) 22. 5 (Solving for number of 2-mark questions correctly attempted) 23. Rs. 250 (Reverse calculation of successive discounts) 24. 11:19 (Solving for savings ratio using income and expenditure ratio) 25. Rs. 4280 (Partnership profit-sharing calculation) 26. 9 km/hr (Using relaPERCENTAGE formula in still water) 27. 108 (Scaling typing speed to 6 minutes) 28. 1250 (Using percentage formula to find total candidates) 29. 25 (Setting up cost equations and solving for number of balls) 30. 200 (Using proportion method for food distribution) Join- https://shorturl.at/Ulwjw