C Programming Language || Hands On Coding

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Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii

India31 202 Technologies & Applications9 572...

📈 Analytical overview of Telegram channel C Programming Language || Hands On Coding

Channel C Programming Language || Hands On Coding (@c_programming_language_coding) in the English language segment is an active participant. Currently, the community unites 12 822 subscribers, ranking 9 572 in the Technologies & Applications category and 31 202 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 12 822 subscribers.

According to the latest data from 27 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -217 over the last 30 days and by -11 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 6.62%. Within the first 24 hours after publication, content typically collects 2.42% reactions from the total number of subscribers.
Post reach: On average, each post receives 849 views. Within the first day, a publication typically gains 310 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii”

Thanks to the high frequency of updates (latest data received on 28 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

12 822

Subscribers

-1124 hours

-367 days

-21730 days

849

Post views

~ 31024 hours

~ 40048 hours

6.62%

Engagement rate

No data

Posts per day

Ads index

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Posts Archive

12 822

💻 Sum of Digits of a Number

#include <stdio.h>

int main() {
  int num, sum = 0, digit;

  printf("Enter a positive integer: ");
  scanf("%d", &num);

  if (num < 0) {
    printf("Please enter a positive integer.n");
    return 1;
  }

  for (; num != 0; num /= 10) {
    digit = num % 10;
    sum += digit;
  }

  printf("Sum of digits = %dn", sum);

  return 0;
}

📤 Output:

Input: 12345
Output: Enter a positive integer: Sum of digits = 15

Input: 9876
Output: Enter a positive integer: Sum of digits = 30

Input: 0
Output: Enter a positive integer: Sum of digits = 0

Input: -123
Output: Enter a positive integer: Please enter a positive integer.

12 822

💻 Print Multiplication Table

#include <stdio.h>

int main() {
    int num, i;

    printf("Enter an integer: ");
    scanf("%d", &num);

    for (i = 1; i <= 10; i++) {
        printf("%d * %d = %dn", num, i, num * i);
    }

    return 0;
}

📤 Output:

Input: 5
Output: Enter an integer: 5 * 1 = 5
5 * 2 = 10
5 * 3 = 15
5 * 4 = 20
5 * 5 = 25
5 * 6 = 30
5 * 7 = 35
5 * 8 = 40
5 * 9 = 45
5 * 10 = 50

12 822

🔧 Loops - For

12 822

💻 Find GCD/HCF of Two Numbers

#include <stdio.h>

int main() {
    int num1, num2, gcd;

    printf("Enter two integers: ");
    scanf("%d %d", &num1, &num2);

    while (num1 != num2) {
        if (num1 > num2) {
            num1 -= num2;
        } else {
            num2 -= num1;
        }
    }

    gcd = num1;

    printf("GCD = %d", gcd);

    return 0;
}

📤 Output:

Input: 12 18
Output: Enter two integers: GCD = 6
Input: 25 15
Output: Enter two integers: GCD = 5
Input: 10 10
Output: Enter two integers: GCD = 10
Input: 48 18
Output: Enter two integers: GCD = 6

12 822

💻 Find First N Fibonacci Numbers

#include <stdio.h>

int main() {
    int n, i;
    long long first = 0, second = 1, next;

    printf("Enter the number of Fibonacci numbers to generate: ");
    scanf("%d", &n);

    printf("First %d Fibonacci numbers are:
", n);

    i = 0;
    while (i < n) {
        printf("%lld ", first);
        next = first + second;
        first = second;
        second = next;
        i++;
    }

    printf("
");
    return 0;
}

📤 Output:

Input: 10
Output: Enter the number of Fibonacci numbers to generate: First 10 Fibonacci numbers are:
0 1 1 2 3 5 8 13 21 34

12 822

💻 Print Multiplication Table

#include <stdio.h>

int main() {
    int num, i = 1;

    printf("Enter a number: ");
    scanf("%d", &num);

    while (i <= 10) {
        printf("%d * %d = %dn", num, i, num * i);
        i++;
    }

    return 0;
}

📤 Output:

Input: 5
Output: Enter a number: 5 * 1 = 5
5 * 2 = 10
5 * 3 = 15
5 * 4 = 20
5 * 5 = 25
5 * 6 = 30
5 * 7 = 35
5 * 8 = 40
5 * 9 = 45
5 * 10 = 50

12 822

💻 Check if Number is Armstrong

#include <stdio.h>
#include <math.h>

int main() {
    int number, originalNumber, remainder, n = 0;
    float result = 0.0;

    printf("Enter an integer: ");
    scanf("%d", &number);

    originalNumber = number;

    // Count number of digits
    while (originalNumber != 0) {
        originalNumber /= 10;
        ++n;
    }

    originalNumber = number;

    // Calculate result
    while (originalNumber != 0) {
        remainder = originalNumber % 10;
        result += pow(remainder, n);
        originalNumber /= 10;
    }

    // Check if number is Armstrong
    if ((int)result == number)
        printf("%d is an Armstrong number.", number);
    else
        printf("%d is not an Armstrong number.", number);

    return 0;
}

📤 Output:

Input: 153
Output: 153 is an Armstrong number.

Input: 121
Output: 121 is not an Armstrong number.

Input: 370
Output: 370 is an Armstrong number.

Input: 1634
Output: 1634 is an Armstrong number.

Input: 123
Output: 123 is not an Armstrong number.

12 822

💻 Check if Number is Palindrome

#include <stdio.h>

int main() {
    int n, reversed = 0, remainder, original;

    printf("Enter an integer: ");
    scanf("%d", &n);

    original = n;

    while (n != 0) {
        remainder = n % 10;
        reversed = reversed * 10 + remainder;
        n /= 10;
    }

    if (original == reversed)
        printf("%d is a palindrome.n", original);
    else
        printf("%d is not a palindrome.n", original);

    return 0;
}

📤 Output:

Input: 121
Output: 121 is a palindrome.

Input: 123
Output: 123 is not a palindrome.

Input: 12321
Output: 12321 is a palindrome.

Input: 10
Output: 10 is not a palindrome.

12 822

💻 Sum of Digits of a Number

#include <stdio.h>

int main() {
    int num, sum = 0, digit;

    printf("Enter a number: ");
    scanf("%d", &num);

    while (num > 0) {
        digit = num % 10;
        sum += digit;
        num /= 10;
    }

    printf("Sum of digits: %dn", sum);

    return 0;
}

📤 Output:

Input: 12345
Output: Enter a number: Sum of digits: 15

Input: 9876
Output: Enter a number: Sum of digits: 30

Input: 0
Output: Enter a number: Sum of digits: 0

Input: 1
Output: Enter a number: Sum of digits: 1

12 822

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12 822

💻 Count Digits in a Number

#include <stdio.h>

int main() {
    int number, count = 0;

    printf("Enter an integer: ");
    scanf("%d", &number);

    if (number == 0) {
        count = 1;
    } else {
        while (number != 0) {
            number /= 10;
            count++;
        }
    }

    printf("Number of digits: %dn", count);

    return 0;
}

📤 Output:

Input: 12345
Output: Number of digits: 5

Input: 0
Output: Number of digits: 1

Input: -987
Output: Number of digits: 3

Input: 10
Output: Number of digits: 2

12 822

💻 Reverse a Number

#include <stdio.h>

int main() {
  int n, reversed = 0, remainder;

  printf("Enter an integer: ");
  scanf("%d", &n);

  while (n != 0) {
    remainder = n % 10;
    reversed = reversed * 10 + remainder;
    n /= 10;
  }

  printf("Reversed number = %d", reversed);

  return 0;
}

📤 Output:

Input: 123
Output: Reversed number = 321

Input: -456
Output: Reversed number = -654

Input: 0
Output: Reversed number = 0

Input: 1200
Output: Reversed number = 21

12 822

💻 Factorial of a Number

#include <stdio.h>

int main() {
  int n;
  unsigned long long factorial = 1;

  printf("Enter an integer: ");
  scanf("%d", &n);

  if (n < 0) {
    printf("Factorial is not defined for negative numbers.n");
  } else {
    int i = 1;
    while (i <= n) {
      factorial *= i;
      i++;
    }
    printf("Factorial of %d = %llun", n, factorial);
  }

  return 0;
}

📤 Output:

Input: 5
Output: Enter an integer: Factorial of 5 = 120

Input: -2
Output: Enter an integer: Factorial is not defined for negative numbers.

Input: 0
Output: Enter an integer: Factorial of 0 = 1

12 822

💻 Sum of Odd Numbers from 1 to N

#include <stdio.h>

int main() {
  int n, i, sum = 0;

  printf("Enter a positive integer: ");
  scanf("%d", &n);

  i = 1;
  while (i <= n) {
    if (i % 2 != 0) {
      sum += i;
    }
    i++;
  }

  printf("Sum of odd numbers from 1 to %d is: %dn", n, sum);

  return 0;
}

📤 Output:

Input: 10
Output: Sum of odd numbers from 1 to 10 is: 25

Input: 5
Output: Sum of odd numbers from 1 to 5 is: 9

Input: 1
Output: Sum of odd numbers from 1 to 1 is: 1

Input: 2
Output: Sum of odd numbers from 1 to 2 is: 1

12 822

💻 Sum of Even Numbers from 1 to N

#include <stdio.h>

int main() {
    int N, i, sum = 0;

    printf("Enter the value of N: ");
    scanf("%d", &N);

    i = 2;
    while (i <= N) {
        sum += i;
        i += 2;
    }

    printf("Sum of even numbers from 1 to %d is: %dn", N, sum);

    return 0;
}

📤 Output:

Input: 10
Output: Enter the value of N: Sum of even numbers from 1 to 10 is: 30
Input: 5
Output: Enter the value of N: Sum of even numbers from 1 to 5 is: 6
Input: 20
Output: Enter the value of N: Sum of even numbers from 1 to 20 is: 110
Input: 1
Output: Enter the value of N: Sum of even numbers from 1 to 1 is: 0

12 822

💻 Sum of First N Natural Numbers

#include <stdio.h>

int main() {
    int n, i = 1, sum = 0;

    printf("Enter a positive integer: ");
    scanf("%d", &n);

    while (i <= n) {
        sum += i;
        i++;
    }

    printf("Sum of first %d natural numbers = %dn", n, sum);

    return 0;
}

📤 Output:

Input: 5
Output: Enter a positive integer: Sum of first 5 natural numbers = 15

Input: 10
Output: Enter a positive integer: Sum of first 10 natural numbers = 55

Input: 1
Output: Enter a positive integer: Sum of first 1 natural numbers = 1

Input: 0
Output: Enter a positive integer: Sum of first 0 natural numbers = 0

12 822

💻 Print Odd Numbers from 1 to N

#include <stdio.h>

int main() {
    int n, i = 1;

    printf("Enter the value of N: ");
    scanf("%d", &n);

    while (i <= n) {
        if (i % 2 != 0) {
            printf("%d ", i);
        }
        i++;
    }

    printf("n");

    return 0;
}

📤 Output:

Input: 10
Output: Enter the value of N: 1 3 5 7 9

Input: 1
Output: Enter the value of N: 1

Input: 2
Output: Enter the value of N: 1

Input: 15
Output: Enter the value of N: 1 3 5 7 9 11 13 15

12 822

💻 Print Even Numbers from 1 to N

#include <stdio.h>

int main() {
  int N, i = 2;

  printf("Enter the value of N: ");
  scanf("%d", &N);

  while (i <= N) {
    printf("%d ", i);
    i += 2;
  }

  printf("n");

  return 0;
}

📤 Output:

Input: 10
Output: 2 4 6 8 10

Input: 15
Output: 2 4 6 8 10 12 14

Input: 1
Output:

Input: 0
Output:

Input: -5
Output:

12 822

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12 822

💻 Print Numbers from N to 1

#include <stdio.h>

int main() {
  int n;

  printf("Enter a number: ");
  scanf("%d", &n);

  while (n >= 1) {
    printf("%d ", n);
    n--;
  }
  printf("n");

  return 0;
}

📤 Output:

Input: 5
Output: 5 4 3 2 1
Input: 1
Output: 1
Input: 10
Output: 10 9 8 7 6 5 4 3 2 1
Input: 0
Output:
Input: -3
Output: