Code With SaiPradeep
A space for curious minds to explore software engineering, computer science, programming and technology. Learn. Explore. Understand.
إظهار المزيد📈 نظرة تحليلية على قناة تيليجرام Code With SaiPradeep
تُعد قناة Code With SaiPradeep (@codewithsaipradeep) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 12 327 مشتركاً، محتلاً المرتبة 10 232 في فئة التكنولوجيات والتطبيقات والمرتبة 31 271 في منطقة الهند.
📊 مؤشرات الجمهور والحراك
منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 12 327 مشتركاً.
بحسب آخر البيانات بتاريخ 12 نوفمبر, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -238، وفي آخر 24 ساعة بمقدار -8، مع بقاء الوصول العام مرتفعاً.
- حالة التحقق: غير موثّقة
- معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 10.45%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً N/A% من ردود الفعل نسبةً إلى إجمالي المشتركين.
- وصول المنشورات: يحصل كل منشور على متوسط 1 288 مشاهدة. وخلال اليوم الأول يجمع عادةً 0 مشاهدة.
- التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 11.
- الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل input, string, scanf("%d, array, element.
📝 الوصف وسياسة المحتوى
يصف المؤلف القناة بأنها مساحة للتعبير عن الآراء الذاتية:
“A space for curious minds to explore software engineering, computer science, programming and technology.
Learn. Explore. Understand.”
بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 13 نوفمبر, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التكنولوجيات والتطبيقات.
#include <stdio.h>
#include <math.h>
int main() {
int number, originalNumber, remainder, n = 0;
float result = 0.0;
printf("Enter an integer: ");
scanf("%d", &number);
originalNumber = number;
// Count number of digits
while (originalNumber != 0) {
originalNumber /= 10;
++n;
}
originalNumber = number;
// Calculate result
while (originalNumber != 0) {
remainder = originalNumber % 10;
result += pow(remainder, n);
originalNumber /= 10;
}
// Check if number is Armstrong
if ((int)result == number)
printf("%d is an Armstrong number.", number);
else
printf("%d is not an Armstrong number.", number);
return 0;
}
📤 Output:
Input: 153 Output: 153 is an Armstrong number. Input: 120 Output: 120 is not an Armstrong number. Input: 1634 Output: 1634 is an Armstrong number. Input: 1234 Output: 1234 is not an Armstrong number.
#include <stdio.h>
int main() {
int num, reversed_num = 0, remainder, original_num;
printf("Enter an integer: ");
scanf("%d", &num);
original_num = num;
for (; num != 0; num /= 10) {
remainder = num % 10;
reversed_num = reversed_num * 10 + remainder;
}
if (original_num == reversed_num)
printf("%d is a palindrome.n", original_num);
else
printf("%d is not a palindrome.n", original_num);
return 0;
}
📤 Output:
Input: 121 Output: 121 is a palindrome. Input: 123 Output: 123 is not a palindrome. Input: 12321 Output: 12321 is a palindrome. Input: 12345 Output: 12345 is not a palindrome. Input: 1 Output: 1 is a palindrome. Input: 0 Output: 0 is a palindrome.
#include <stdio.h>
int main() {
int num, sum = 0, digit;
printf("Enter a positive integer: ");
scanf("%d", &num);
if (num < 0) {
printf("Please enter a positive integer.n");
return 1;
}
for (; num != 0; num /= 10) {
digit = num % 10;
sum += digit;
}
printf("Sum of digits = %dn", sum);
return 0;
}
📤 Output:
Input: 12345 Output: Enter a positive integer: Sum of digits = 15 Input: 9876 Output: Enter a positive integer: Sum of digits = 30 Input: 0 Output: Enter a positive integer: Sum of digits = 0 Input: -123 Output: Enter a positive integer: Please enter a positive integer.
#include <stdio.h>
int main() {
int num, i;
printf("Enter an integer: ");
scanf("%d", &num);
for (i = 1; i <= 10; i++) {
printf("%d * %d = %dn", num, i, num * i);
}
return 0;
}
📤 Output:
Input: 5 Output: Enter an integer: 5 * 1 = 5 5 * 2 = 10 5 * 3 = 15 5 * 4 = 20 5 * 5 = 25 5 * 6 = 30 5 * 7 = 35 5 * 8 = 40 5 * 9 = 45 5 * 10 = 50
#include <stdio.h>
int main() {
int num1, num2, gcd;
printf("Enter two integers: ");
scanf("%d %d", &num1, &num2);
while (num1 != num2) {
if (num1 > num2) {
num1 -= num2;
} else {
num2 -= num1;
}
}
gcd = num1;
printf("GCD = %d", gcd);
return 0;
}
📤 Output:
Input: 12 18 Output: Enter two integers: GCD = 6 Input: 25 15 Output: Enter two integers: GCD = 5 Input: 10 10 Output: Enter two integers: GCD = 10 Input: 48 18 Output: Enter two integers: GCD = 6
#include <stdio.h>
int main() {
int n, i;
long long first = 0, second = 1, next;
printf("Enter the number of Fibonacci numbers to generate: ");
scanf("%d", &n);
printf("First %d Fibonacci numbers are:
", n);
i = 0;
while (i < n) {
printf("%lld ", first);
next = first + second;
first = second;
second = next;
i++;
}
printf("
");
return 0;
}
📤 Output:
Input: 10 Output: Enter the number of Fibonacci numbers to generate: First 10 Fibonacci numbers are: 0 1 1 2 3 5 8 13 21 34
#include <stdio.h>
int main() {
int num, i = 1;
printf("Enter a number: ");
scanf("%d", &num);
while (i <= 10) {
printf("%d * %d = %dn", num, i, num * i);
i++;
}
return 0;
}
📤 Output:
Input: 5 Output: Enter a number: 5 * 1 = 5 5 * 2 = 10 5 * 3 = 15 5 * 4 = 20 5 * 5 = 25 5 * 6 = 30 5 * 7 = 35 5 * 8 = 40 5 * 9 = 45 5 * 10 = 50
#include <stdio.h>
#include <math.h>
int main() {
int number, originalNumber, remainder, n = 0;
float result = 0.0;
printf("Enter an integer: ");
scanf("%d", &number);
originalNumber = number;
// Count number of digits
while (originalNumber != 0) {
originalNumber /= 10;
++n;
}
originalNumber = number;
// Calculate result
while (originalNumber != 0) {
remainder = originalNumber % 10;
result += pow(remainder, n);
originalNumber /= 10;
}
// Check if number is Armstrong
if ((int)result == number)
printf("%d is an Armstrong number.", number);
else
printf("%d is not an Armstrong number.", number);
return 0;
}
📤 Output:
Input: 153 Output: 153 is an Armstrong number. Input: 121 Output: 121 is not an Armstrong number. Input: 370 Output: 370 is an Armstrong number. Input: 1634 Output: 1634 is an Armstrong number. Input: 123 Output: 123 is not an Armstrong number.
#include <stdio.h>
int main() {
int n, reversed = 0, remainder, original;
printf("Enter an integer: ");
scanf("%d", &n);
original = n;
while (n != 0) {
remainder = n % 10;
reversed = reversed * 10 + remainder;
n /= 10;
}
if (original == reversed)
printf("%d is a palindrome.n", original);
else
printf("%d is not a palindrome.n", original);
return 0;
}
📤 Output:
Input: 121 Output: 121 is a palindrome. Input: 123 Output: 123 is not a palindrome. Input: 12321 Output: 12321 is a palindrome. Input: 10 Output: 10 is not a palindrome.
#include <stdio.h>
int main() {
int num, sum = 0, digit;
printf("Enter a number: ");
scanf("%d", &num);
while (num > 0) {
digit = num % 10;
sum += digit;
num /= 10;
}
printf("Sum of digits: %dn", sum);
return 0;
}
📤 Output:
Input: 12345 Output: Enter a number: Sum of digits: 15 Input: 9876 Output: Enter a number: Sum of digits: 30 Input: 0 Output: Enter a number: Sum of digits: 0 Input: 1 Output: Enter a number: Sum of digits: 1
#include <stdio.h>
int main() {
int number, count = 0;
printf("Enter an integer: ");
scanf("%d", &number);
if (number == 0) {
count = 1;
} else {
while (number != 0) {
number /= 10;
count++;
}
}
printf("Number of digits: %dn", count);
return 0;
}
📤 Output:
Input: 12345 Output: Number of digits: 5 Input: 0 Output: Number of digits: 1 Input: -987 Output: Number of digits: 3 Input: 10 Output: Number of digits: 2
#include <stdio.h>
int main() {
int n, reversed = 0, remainder;
printf("Enter an integer: ");
scanf("%d", &n);
while (n != 0) {
remainder = n % 10;
reversed = reversed * 10 + remainder;
n /= 10;
}
printf("Reversed number = %d", reversed);
return 0;
}
📤 Output:
Input: 123 Output: Reversed number = 321 Input: -456 Output: Reversed number = -654 Input: 0 Output: Reversed number = 0 Input: 1200 Output: Reversed number = 21
#include <stdio.h>
int main() {
int n;
unsigned long long factorial = 1;
printf("Enter an integer: ");
scanf("%d", &n);
if (n < 0) {
printf("Factorial is not defined for negative numbers.n");
} else {
int i = 1;
while (i <= n) {
factorial *= i;
i++;
}
printf("Factorial of %d = %llun", n, factorial);
}
return 0;
}
📤 Output:
Input: 5 Output: Enter an integer: Factorial of 5 = 120 Input: -2 Output: Enter an integer: Factorial is not defined for negative numbers. Input: 0 Output: Enter an integer: Factorial of 0 = 1
#include <stdio.h>
int main() {
int n, i, sum = 0;
printf("Enter a positive integer: ");
scanf("%d", &n);
i = 1;
while (i <= n) {
if (i % 2 != 0) {
sum += i;
}
i++;
}
printf("Sum of odd numbers from 1 to %d is: %dn", n, sum);
return 0;
}
📤 Output:
Input: 10 Output: Sum of odd numbers from 1 to 10 is: 25 Input: 5 Output: Sum of odd numbers from 1 to 5 is: 9 Input: 1 Output: Sum of odd numbers from 1 to 1 is: 1 Input: 2 Output: Sum of odd numbers from 1 to 2 is: 1
#include <stdio.h>
int main() {
int N, i, sum = 0;
printf("Enter the value of N: ");
scanf("%d", &N);
i = 2;
while (i <= N) {
sum += i;
i += 2;
}
printf("Sum of even numbers from 1 to %d is: %dn", N, sum);
return 0;
}
📤 Output:
Input: 10 Output: Enter the value of N: Sum of even numbers from 1 to 10 is: 30 Input: 5 Output: Enter the value of N: Sum of even numbers from 1 to 5 is: 6 Input: 20 Output: Enter the value of N: Sum of even numbers from 1 to 20 is: 110 Input: 1 Output: Enter the value of N: Sum of even numbers from 1 to 1 is: 0
#include <stdio.h>
int main() {
int n, i = 1, sum = 0;
printf("Enter a positive integer: ");
scanf("%d", &n);
while (i <= n) {
sum += i;
i++;
}
printf("Sum of first %d natural numbers = %dn", n, sum);
return 0;
}
📤 Output:
Input: 5 Output: Enter a positive integer: Sum of first 5 natural numbers = 15 Input: 10 Output: Enter a positive integer: Sum of first 10 natural numbers = 55 Input: 1 Output: Enter a positive integer: Sum of first 1 natural numbers = 1 Input: 0 Output: Enter a positive integer: Sum of first 0 natural numbers = 0
#include <stdio.h>
int main() {
int n, i = 1;
printf("Enter the value of N: ");
scanf("%d", &n);
while (i <= n) {
if (i % 2 != 0) {
printf("%d ", i);
}
i++;
}
printf("n");
return 0;
}
📤 Output:
Input: 10 Output: Enter the value of N: 1 3 5 7 9 Input: 1 Output: Enter the value of N: 1 Input: 2 Output: Enter the value of N: 1 Input: 15 Output: Enter the value of N: 1 3 5 7 9 11 13 15
#include <stdio.h>
int main() {
int N, i = 2;
printf("Enter the value of N: ");
scanf("%d", &N);
while (i <= N) {
printf("%d ", i);
i += 2;
}
printf("n");
return 0;
}
📤 Output:
Input: 10 Output: 2 4 6 8 10 Input: 15 Output: 2 4 6 8 10 12 14 Input: 1 Output: Input: 0 Output: Input: -5 Output:
