C Programming Codes

前往频道在 Telegram

C Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii

显示更多

📈 Telegram 频道 C Programming Codes 的分析概览

频道 C Programming Codes (@c_programming_codes) 英语语言赛道中的是活跃参与者。目前社区聚集了 13 430 名订阅者，在 技术与应用 类别中位列第 9 534，并在印度地区排名第 32 075 位。

📊 受众指标与增长动态

自 невідомо 创建以来，项目保持高速增长，吸引了 13 430 名订阅者。

根据 11 六月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -239，过去 24 小时变化为 -9，整体触达仍然可观。

认证状态： 未认证
互动率 (ER)： 平均受众互动率为 9.78%。内容发布后 24 小时内通常能获得 N/A% 的反应，占订阅者总量。
帖子覆盖： 每篇帖子平均可获得 0 次浏览，首日通常累积 0 次浏览。
互动与反馈： 受众积极参与，单帖平均反应数为 0。
主题关注点： 内容集中在 input, string, scanf("%d, array, element 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台：
“C Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii”

凭借高频更新（最新数据采集于 12 六月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 技术与应用 类别中的关键影响点。

13 430

订阅者

-924 小时

-577 天

-23930 天

1 313

帖子浏览量

无数据24 小时

无数据48 小时

9.78%

参与率

无数据

每日帖子数

Ads index

beta

帖子存档

13 430

💻 Find First N Fibonacci Numbers

#include <stdio.h>

int main() {
    int n, i;
    long long first = 0, second = 1, next;

    printf("Enter the number of Fibonacci numbers to generate: ");
    scanf("%d", &n);

    printf("First %d Fibonacci numbers are:
", n);

    i = 0;
    while (i < n) {
        printf("%lld ", first);
        next = first + second;
        first = second;
        second = next;
        i++;
    }

    printf("
");
    return 0;
}

📤 Output:

Input: 10
Output: Enter the number of Fibonacci numbers to generate: First 10 Fibonacci numbers are:
0 1 1 2 3 5 8 13 21 34

13 430

💻 Print Multiplication Table

#include <stdio.h>

int main() {
    int num, i = 1;

    printf("Enter a number: ");
    scanf("%d", &num);

    while (i <= 10) {
        printf("%d * %d = %dn", num, i, num * i);
        i++;
    }

    return 0;
}

📤 Output:

Input: 5
Output: Enter a number: 5 * 1 = 5
5 * 2 = 10
5 * 3 = 15
5 * 4 = 20
5 * 5 = 25
5 * 6 = 30
5 * 7 = 35
5 * 8 = 40
5 * 9 = 45
5 * 10 = 50

13 430

💻 Check if Number is Armstrong

#include <stdio.h>
#include <math.h>

int main() {
    int number, originalNumber, remainder, n = 0;
    float result = 0.0;

    printf("Enter an integer: ");
    scanf("%d", &number);

    originalNumber = number;

    // Count number of digits
    while (originalNumber != 0) {
        originalNumber /= 10;
        ++n;
    }

    originalNumber = number;

    // Calculate result
    while (originalNumber != 0) {
        remainder = originalNumber % 10;
        result += pow(remainder, n);
        originalNumber /= 10;
    }

    // Check if number is Armstrong
    if ((int)result == number)
        printf("%d is an Armstrong number.", number);
    else
        printf("%d is not an Armstrong number.", number);

    return 0;
}

📤 Output:

Input: 153
Output: 153 is an Armstrong number.

Input: 121
Output: 121 is not an Armstrong number.

Input: 370
Output: 370 is an Armstrong number.

Input: 1634
Output: 1634 is an Armstrong number.

Input: 123
Output: 123 is not an Armstrong number.

13 430

💻 Check if Number is Palindrome

#include <stdio.h>

int main() {
    int n, reversed = 0, remainder, original;

    printf("Enter an integer: ");
    scanf("%d", &n);

    original = n;

    while (n != 0) {
        remainder = n % 10;
        reversed = reversed * 10 + remainder;
        n /= 10;
    }

    if (original == reversed)
        printf("%d is a palindrome.n", original);
    else
        printf("%d is not a palindrome.n", original);

    return 0;
}

📤 Output:

Input: 121
Output: 121 is a palindrome.

Input: 123
Output: 123 is not a palindrome.

Input: 12321
Output: 12321 is a palindrome.

Input: 10
Output: 10 is not a palindrome.

13 430

💻 Sum of Digits of a Number

#include <stdio.h>

int main() {
    int num, sum = 0, digit;

    printf("Enter a number: ");
    scanf("%d", &num);

    while (num > 0) {
        digit = num % 10;
        sum += digit;
        num /= 10;
    }

    printf("Sum of digits: %dn", sum);

    return 0;
}

📤 Output:

Input: 12345
Output: Enter a number: Sum of digits: 15

Input: 9876
Output: Enter a number: Sum of digits: 30

Input: 0
Output: Enter a number: Sum of digits: 0

Input: 1
Output: Enter a number: Sum of digits: 1

13 430

Solve LeetCode problems consistently in structured manner Join here👇 https://t.me/+L6Z9gjVIVEQ4NmRl

13 430

💻 Count Digits in a Number

#include <stdio.h>

int main() {
    int number, count = 0;

    printf("Enter an integer: ");
    scanf("%d", &number);

    if (number == 0) {
        count = 1;
    } else {
        while (number != 0) {
            number /= 10;
            count++;
        }
    }

    printf("Number of digits: %dn", count);

    return 0;
}

📤 Output:

Input: 12345
Output: Number of digits: 5

Input: 0
Output: Number of digits: 1

Input: -987
Output: Number of digits: 3

Input: 10
Output: Number of digits: 2

13 430

💻 Reverse a Number

#include <stdio.h>

int main() {
  int n, reversed = 0, remainder;

  printf("Enter an integer: ");
  scanf("%d", &n);

  while (n != 0) {
    remainder = n % 10;
    reversed = reversed * 10 + remainder;
    n /= 10;
  }

  printf("Reversed number = %d", reversed);

  return 0;
}

📤 Output:

Input: 123
Output: Reversed number = 321

Input: -456
Output: Reversed number = -654

Input: 0
Output: Reversed number = 0

Input: 1200
Output: Reversed number = 21

13 430

💻 Factorial of a Number

#include <stdio.h>

int main() {
  int n;
  unsigned long long factorial = 1;

  printf("Enter an integer: ");
  scanf("%d", &n);

  if (n < 0) {
    printf("Factorial is not defined for negative numbers.n");
  } else {
    int i = 1;
    while (i <= n) {
      factorial *= i;
      i++;
    }
    printf("Factorial of %d = %llun", n, factorial);
  }

  return 0;
}

📤 Output:

Input: 5
Output: Enter an integer: Factorial of 5 = 120

Input: -2
Output: Enter an integer: Factorial is not defined for negative numbers.

Input: 0
Output: Enter an integer: Factorial of 0 = 1

13 430

💻 Sum of Odd Numbers from 1 to N

#include <stdio.h>

int main() {
  int n, i, sum = 0;

  printf("Enter a positive integer: ");
  scanf("%d", &n);

  i = 1;
  while (i <= n) {
    if (i % 2 != 0) {
      sum += i;
    }
    i++;
  }

  printf("Sum of odd numbers from 1 to %d is: %dn", n, sum);

  return 0;
}

📤 Output:

Input: 10
Output: Sum of odd numbers from 1 to 10 is: 25

Input: 5
Output: Sum of odd numbers from 1 to 5 is: 9

Input: 1
Output: Sum of odd numbers from 1 to 1 is: 1

Input: 2
Output: Sum of odd numbers from 1 to 2 is: 1

13 430

💻 Sum of Even Numbers from 1 to N

#include <stdio.h>

int main() {
    int N, i, sum = 0;

    printf("Enter the value of N: ");
    scanf("%d", &N);

    i = 2;
    while (i <= N) {
        sum += i;
        i += 2;
    }

    printf("Sum of even numbers from 1 to %d is: %dn", N, sum);

    return 0;
}

📤 Output:

Input: 10
Output: Enter the value of N: Sum of even numbers from 1 to 10 is: 30
Input: 5
Output: Enter the value of N: Sum of even numbers from 1 to 5 is: 6
Input: 20
Output: Enter the value of N: Sum of even numbers from 1 to 20 is: 110
Input: 1
Output: Enter the value of N: Sum of even numbers from 1 to 1 is: 0

13 430

💻 Sum of First N Natural Numbers

#include <stdio.h>

int main() {
    int n, i = 1, sum = 0;

    printf("Enter a positive integer: ");
    scanf("%d", &n);

    while (i <= n) {
        sum += i;
        i++;
    }

    printf("Sum of first %d natural numbers = %dn", n, sum);

    return 0;
}

📤 Output:

Input: 5
Output: Enter a positive integer: Sum of first 5 natural numbers = 15

Input: 10
Output: Enter a positive integer: Sum of first 10 natural numbers = 55

Input: 1
Output: Enter a positive integer: Sum of first 1 natural numbers = 1

Input: 0
Output: Enter a positive integer: Sum of first 0 natural numbers = 0

13 430

💻 Print Odd Numbers from 1 to N

#include <stdio.h>

int main() {
    int n, i = 1;

    printf("Enter the value of N: ");
    scanf("%d", &n);

    while (i <= n) {
        if (i % 2 != 0) {
            printf("%d ", i);
        }
        i++;
    }

    printf("n");

    return 0;
}

📤 Output:

Input: 10
Output: Enter the value of N: 1 3 5 7 9

Input: 1
Output: Enter the value of N: 1

Input: 2
Output: Enter the value of N: 1

Input: 15
Output: Enter the value of N: 1 3 5 7 9 11 13 15

13 430

💻 Print Even Numbers from 1 to N

#include <stdio.h>

int main() {
  int N, i = 2;

  printf("Enter the value of N: ");
  scanf("%d", &N);

  while (i <= N) {
    printf("%d ", i);
    i += 2;
  }

  printf("n");

  return 0;
}

📤 Output:

Input: 10
Output: 2 4 6 8 10

Input: 15
Output: 2 4 6 8 10 12 14

Input: 1
Output:

Input: 0
Output:

Input: -5
Output:

13 430

https://t.me/+9BYfwzAg1dQzODQ1

13 430

💻 Print Numbers from N to 1

#include <stdio.h>

int main() {
  int n;

  printf("Enter a number: ");
  scanf("%d", &n);

  while (n >= 1) {
    printf("%d ", n);
    n--;
  }
  printf("n");

  return 0;
}

📤 Output:

Input: 5
Output: 5 4 3 2 1
Input: 1
Output: 1
Input: 10
Output: 10 9 8 7 6 5 4 3 2 1
Input: 0
Output:
Input: -3
Output:

13 430

💻 Print Numbers from 1 to N

#include <stdio.h>

int main() {
  int N, i = 1;

  printf("Enter the value of N: ");
  scanf("%d", &N);

  while (i <= N) {
    printf("%d ", i);
    i++;
  }
  printf("n");

  return 0;
}

📤 Output:

Input: 5
Output: 1 2 3 4 5

13 430

🔧 Loops - While

13 430

💻 Unit Converter Using Switch

#include <stdio.h>

int main() {
  int choice;
  float value, result;

  printf("Unit Convertern");
  printf("1. Celsius to Fahrenheitn");
  printf("2. Fahrenheit to Celsiusn");
  printf("Enter your choice (1 or 2): ");
  scanf("%d", &choice);

  switch (choice) {
    case 1:
      printf("Enter temperature in Celsius: ");
      scanf("%f", &value);
      result = (value * 9 / 5) + 32;
      printf("Temperature in Fahrenheit: %.2fn", result);
      break;
    case 2:
      printf("Enter temperature in Fahrenheit: ");
      scanf("%f", &value);
      result = (value - 32) * 5 / 9;
      printf("Temperature in Celsius: %.2fn", result);
      break;
    default:
      printf("Invalid choice!n");
  }

  return 0;
}

📤 Output:

Unit Converter
1. Celsius to Fahrenheit
2. Fahrenheit to Celsius
Enter your choice (1 or 2): Input: 1
Enter temperature in Celsius: Input: 25
Temperature in Fahrenheit: 77.00
Unit Converter
1. Celsius to Fahrenheit
2. Fahrenheit to Celsius
Enter your choice (1 or 2): Input: 2
Enter temperature in Fahrenheit: Input: 98.6
Temperature in Celsius: 37.00
Unit Converter
1. Celsius to Fahrenheit
2. Fahrenheit to Celsius
Enter your choice (1 or 2): Input: 3
Invalid choice!

13 430

💻 Season Identification from Month

#include <stdio.h>

int main() {
  int month;

  printf("Enter month number (1-12): ");
  scanf("%d", &month);

  switch (month) {
    case 12:
    case 1:
    case 2:
      printf("Wintern");
      break;
    case 3:
    case 4:
    case 5:
      printf("Springn");
      break;
    case 6:
    case 7:
    case 8:
      printf("Summern");
      break;
    case 9:
    case 10:
    case 11:
      printf("Autumnn");
      break;
    default:
      printf("Invalid month number.n");
  }

  return 0;
}

📤 Output:

Input: 1
Output: Winter

Input: 4
Output: Spring

Input: 7
Output: Summer

Input: 10
Output: Autumn

Input: 13
Output: Invalid month number.