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C Programming Language || Hands On Coding

C Programming Language || Hands On Coding

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Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii

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πŸ“ˆ Analytical overview of Telegram channel C Programming Language || Hands On Coding

Channel C Programming Language || Hands On Coding (@c_programming_language_coding) in the English language segment is an active participant. Currently, the community unites 12 809 subscribers, ranking 9 558 in the Technologies & Applications category and 30 933 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 12 809 subscribers.

According to the latest data from 29 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -215 over the last 30 days and by -7 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 7.22%. Within the first 24 hours after publication, content typically collects 2.42% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 925 views. Within the first day, a publication typically gains 310 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
  • Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œHands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii”

Thanks to the high frequency of updates (latest data received on 30 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

12 809
Subscribers
-724 hours
-317 days
-21530 days
Posts Archive
#CProgramming #HelloWorld #BeginnerCode

The Classic Hello World: Your First Step in C Programming!
#include <stdio.h>

int main() {
    printf("Hello, World!");
    return 0;
}

C Programming: Hello World! πŸ‘‹ Ready to dive into the world of coding? C is a great place to start! Let's cover the basics. What is C? * A powerful, general-purpose programming language. * Foundation for many other languages (like C++, Java, Python). * Used in system programming, embedded systems, and more! Basic Syntax πŸ“œ * Think of it as grammar for computers. * **`#include <stdio.h>`:** Includes standard input/output library (for printing to the screen and getting input). * **`int main() { ... }`:** The main function where your program starts executing. * **`printf("Hello, World!\n");`:** Prints "Hello, World!" to the console. `\n` creates a new line. * **`return 0;`:** Indicates that the program executed successfully. * Every statement ends with a semicolon (`;`). Your First Program πŸš€ ```c #include <stdio.h> int main() { printf("Hello, World!\n"); return 0; } ``` Simple I/O (Input/Output) ⌨️ * **`printf()`:** Prints output to the console. * Example: `printf("The value is: %d\n", 10);` (%d is a placeholder for integers). * **`scanf()`:** Reads input from the console. * Example: `int age; scanf("%d", &age);` (&age means "address of age"). Let's try an example! ```c #include <stdio.h> int main() { int age; printf("Enter your age: "); scanf("%d", &age); printf("You are %d years old.\n", age); return 0; } ``` Next Steps ➑️ * Experiment! Change the text, try different numbers. * Learn about variables, data types, and operators. * Practice makes perfect! #Cprogramming #beginners #coding #tutorial

πŸš€ **C Programming: Hello, World! πŸ‘‹** πŸš€ Ready to dive into the world of coding? Let's start with C, a powerful and foundational language! **What is C?** * C is a general-purpose programming language. * It's known for its efficiency and control. * It's used for system programming, embedded systems, and more! **Your First C Program: Hello, World!** Here's the classic "Hello, World!" program: ```c #include <stdio.h> int main() { printf("Hello, World!\n"); return 0; } ``` **Let's Break it Down:** * `#include <stdio.h>`: This line *includes* the standard input/output library. Think of it as borrowing tools for printing and reading. * `int main() { ... }`: This is the *main function*. Your program starts executing here. The `int` means the function will return an integer value. * `printf("Hello, World!\n");`: This *prints* "Hello, World!" to the console. `printf` is a function from `stdio.h`. `\n` adds a newline. * `return 0;`: This indicates that the program executed successfully. **Basic Syntax:** * Statements end with a semicolon `;` * Curly braces `{}` define blocks of code. * Comments: `// This is a single-line comment` or `/* This is a multi-line comment */` **Simple Input/Output (I/O):** * `printf()`: Prints output to the console. * Example: `printf("The value is: %d\n", 10);` (%d is a placeholder for an integer) * `scanf()`: Reads input from the console. * Example: `int age; scanf("%d", &age);` (Reads an integer and stores it in the `age` variable. `&` is important! It's the "address of" operator). **Next Steps:** * Install a C compiler (like GCC). * Try compiling and running the "Hello, World!" program. * Experiment with `printf` and `scanf`. * Learn about variables and data types (int, float, char, etc.). Happy coding! πŸš€

#CProgramming #MathTrick #Algorithm

Efficiently calculate the sum of numbers from 1 to N in C?
#include <stdio.h>int main() {    int n = 10;    int sum = (n * (n + 1)) / 2;    printf("Sum of numbers from 1 to %d is: %d\n", n, sum);    return 0;}

#CProgramming #Bitwise #PowerOfTwo

How to check if a number is a power of 2 efficiently?
#include <stdio.h>#include <stdbool.h>bool isPowerOfTwo(int n) {    return (n > 0) && ((n & (n - 1)) == 0);}int main() {    int num = 16;    if (isPowerOfTwo(num)) {        printf("%d is a power of 2\n", num);    } else {        printf("%d is not a power of 2\n", num);    }    return 0;}

#CProgramming #Pointers #CallByReference

Pointers in C: Can you modify a variable outside a function?
#include <stdio.h>

void increment(int *n) {
  (*n)++;
}

int main() {
  int num = 10;
  printf("Before: %d\n", num);
  increment(&num);
  printf("After: %d\n", num);
  return 0;
}

#CProgramming #DynamicArrays #Malloc

Function to Return Dynamic Array (malloc)
#include <stdio.h>
#include <stdlib.h>

int* create_dynamic_array(int size) {
    if (size <= 0) {
        return NULL; 
    }
    int* arr = (int*)malloc(size * sizeof(int));
    if (arr == NULL) {
        return NULL; 
    }
    for (int i = 0; i < size; i++) {
        arr[i] = i + 1; 
    }
    return arr;
}

int main() {
    int size = 5;
    int* my_array = create_dynamic_array(size);
    if (my_array != NULL) {
        for (int i = 0; i < size; i++) {
            printf("%d ", my_array[i]);
        }
        printf("\n");
        free(my_array);
        my_array = NULL; 
    }
    return 0;
}

#CProgramming #Pointers #DynamicMemory

Pointer to Pointer (Double Pointer)
#include <stdio.h>
#include <stdlib.h>

int main() {
    int x = 10;
    int *ptr = &x;
    int **ptr_to_ptr = &ptr;

    printf("Value of x: %d\n", x);
    printf("Address of x: %p\n", &x);
    printf("Value of ptr: %p\n", ptr);
    printf("Value pointed to by ptr: %d\n", *ptr);
    printf("Address of ptr: %p\n", &ptr);
    printf("Value of ptr_to_ptr: %p\n", ptr_to_ptr);
    printf("Value pointed to by ptr_to_ptr: %p\n", *ptr_to_ptr);
    printf("Value pointed to by *ptr_to_ptr: %d\n", **ptr_to_ptr);
    printf("Address of ptr_to_ptr: %p\n", &ptr_to_ptr);

    // Example: Dynamically allocate an array of strings
    int num_strings = 3;
    char **string_array = (char **)malloc(num_strings * sizeof(char *));

    if (string_array == NULL) {
        perror("malloc failed");
        return 1;
    }

    string_array[0] = (char *)malloc(10 * sizeof(char));
    string_array[1] = (char *)malloc(15 * sizeof(char));
    string_array[2] = (char *)malloc(20 * sizeof(char));

    if (string_array[0] == NULL || string_array[1] == NULL || string_array[2] == NULL) {
        perror("malloc failed");
        // Free previously allocated memory to avoid memory leaks
        for(int i = 0; i < num_strings; ++i){
            if(string_array[i] != NULL){
                free(string_array[i]);
            }
        }
        free(string_array);
        return 1;
    }

    sprintf(string_array[0], "Hello");
    sprintf(string_array[1], "World!");
    sprintf(string_array[2], "Double Pointers");

    for (int i = 0; i < num_strings; i++) {
        printf("string_array[%d] = %s\n", i, string_array[i]);
    }

    // Free dynamically allocated memory
    for (int i = 0; i < num_strings; i++) {
        free(string_array[i]);
    }
    free(string_array);

    return 0;
}

#CProgramming #Arrays #Pointers

Array Traversal with Pointers
#include <stdio.h>

int main() {
    int arr[] = {10, 20, 30, 40, 50};
    int *ptr = arr;
    int size = sizeof(arr) / sizeof(arr[0]);

    printf("Array elements:\n");
    for (int i = 0; i < size; i++) {
        printf("Element %d: %d\n", i, *ptr);
        ptr++;
    }

    ptr = arr; 
    printf("Array elements (using pointer arithmetic):\n");
    for (int i = 0; i < size; i++) {
        printf("Element %d: %d\n", i, *(arr + i));
    }

    return 0;
}

#CProgramming #Pointers #SwapVariables

Swap Variables Using Pointers
#include <stdio.h>

void swap(int *x, int *y) {
    int temp = *x;
    *x = *y;
    *y = temp;
}

int main() {
    int a = 10;
    int b = 20;

    printf("Before swap: a = %d, b = %d\n", a, b);
    swap(&a, &b);
    printf("After swap: a = %d, b = %d\n", a, b);

    return 0;
}

#CProgramming #StringLength #Pointers

String Length using Pointer Arithmetic
#include <stdio.h>

int stringLength(const char *str) {
    const char *p = str;
    while (*p != '\0') {
        p++;
    }
    return p - str;
}

int main() {
    char str[] = "Hello, World!";
    int len = stringLength(str);
    printf("Length of the string: %d\n", len);
    return 0;
}

C Programming Language || Hands On Coding - Statistics & analytics of Telegram channel @c_programming_language_coding