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C Programming Language || Hands On Coding

C Programming Language || Hands On Coding

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Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii

إظهار المزيد

📈 نظرة تحليلية على قناة تيليجرام C Programming Language || Hands On Coding

تُعد قناة C Programming Language || Hands On Coding (@c_programming_language_coding) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 12 809 مشتركاً، محتلاً المرتبة 9 558 في فئة التكنولوجيات والتطبيقات والمرتبة 30 933 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 12 809 مشتركاً.

بحسب آخر البيانات بتاريخ 29 أغسطس, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -215، وفي آخر 24 ساعة بمقدار -7، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 7.22‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 2.42‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 925 مشاهدة. وخلال اليوم الأول يجمع عادةً 310 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 2.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل input, string, scanf("%d, array, element.

📝 الوصف وسياسة المحتوى

يصف المؤلف القناة بأنها مساحة للتعبير عن الآراء الذاتية:
Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 30 أغسطس, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التكنولوجيات والتطبيقات.

12 809
المشتركون
-724 ساعات
-317 أيام
-21530 أيام
أرشيف المشاركات
#CProgramming #HelloWorld #BeginnerCode

The Classic Hello World: Your First Step in C Programming!
#include <stdio.h>

int main() {
    printf("Hello, World!");
    return 0;
}

C Programming: Hello World! 👋 Ready to dive into the world of coding? C is a great place to start! Let's cover the basics. What is C? * A powerful, general-purpose programming language. * Foundation for many other languages (like C++, Java, Python). * Used in system programming, embedded systems, and more! Basic Syntax 📜 * Think of it as grammar for computers. * **`#include <stdio.h>`:** Includes standard input/output library (for printing to the screen and getting input). * **`int main() { ... }`:** The main function where your program starts executing. * **`printf("Hello, World!\n");`:** Prints "Hello, World!" to the console. `\n` creates a new line. * **`return 0;`:** Indicates that the program executed successfully. * Every statement ends with a semicolon (`;`). Your First Program 🚀 ```c #include <stdio.h> int main() { printf("Hello, World!\n"); return 0; } ``` Simple I/O (Input/Output) ⌨️ * **`printf()`:** Prints output to the console. * Example: `printf("The value is: %d\n", 10);` (%d is a placeholder for integers). * **`scanf()`:** Reads input from the console. * Example: `int age; scanf("%d", &age);` (&age means "address of age"). Let's try an example! ```c #include <stdio.h> int main() { int age; printf("Enter your age: "); scanf("%d", &age); printf("You are %d years old.\n", age); return 0; } ``` Next Steps ➡️ * Experiment! Change the text, try different numbers. * Learn about variables, data types, and operators. * Practice makes perfect! #Cprogramming #beginners #coding #tutorial

🚀 **C Programming: Hello, World! 👋** 🚀 Ready to dive into the world of coding? Let's start with C, a powerful and foundational language! **What is C?** * C is a general-purpose programming language. * It's known for its efficiency and control. * It's used for system programming, embedded systems, and more! **Your First C Program: Hello, World!** Here's the classic "Hello, World!" program: ```c #include <stdio.h> int main() { printf("Hello, World!\n"); return 0; } ``` **Let's Break it Down:** * `#include <stdio.h>`: This line *includes* the standard input/output library. Think of it as borrowing tools for printing and reading. * `int main() { ... }`: This is the *main function*. Your program starts executing here. The `int` means the function will return an integer value. * `printf("Hello, World!\n");`: This *prints* "Hello, World!" to the console. `printf` is a function from `stdio.h`. `\n` adds a newline. * `return 0;`: This indicates that the program executed successfully. **Basic Syntax:** * Statements end with a semicolon `;` * Curly braces `{}` define blocks of code. * Comments: `// This is a single-line comment` or `/* This is a multi-line comment */` **Simple Input/Output (I/O):** * `printf()`: Prints output to the console. * Example: `printf("The value is: %d\n", 10);` (%d is a placeholder for an integer) * `scanf()`: Reads input from the console. * Example: `int age; scanf("%d", &age);` (Reads an integer and stores it in the `age` variable. `&` is important! It's the "address of" operator). **Next Steps:** * Install a C compiler (like GCC). * Try compiling and running the "Hello, World!" program. * Experiment with `printf` and `scanf`. * Learn about variables and data types (int, float, char, etc.). Happy coding! 🚀

#CProgramming #MathTrick #Algorithm

Efficiently calculate the sum of numbers from 1 to N in C?
#include <stdio.h>int main() {    int n = 10;    int sum = (n * (n + 1)) / 2;    printf("Sum of numbers from 1 to %d is: %d\n", n, sum);    return 0;}

#CProgramming #Bitwise #PowerOfTwo

How to check if a number is a power of 2 efficiently?
#include <stdio.h>#include <stdbool.h>bool isPowerOfTwo(int n) {    return (n > 0) && ((n & (n - 1)) == 0);}int main() {    int num = 16;    if (isPowerOfTwo(num)) {        printf("%d is a power of 2\n", num);    } else {        printf("%d is not a power of 2\n", num);    }    return 0;}

#CProgramming #Pointers #CallByReference

Pointers in C: Can you modify a variable outside a function?
#include <stdio.h>

void increment(int *n) {
  (*n)++;
}

int main() {
  int num = 10;
  printf("Before: %d\n", num);
  increment(&num);
  printf("After: %d\n", num);
  return 0;
}

#CProgramming #DynamicArrays #Malloc

Function to Return Dynamic Array (malloc)
#include <stdio.h>
#include <stdlib.h>

int* create_dynamic_array(int size) {
    if (size <= 0) {
        return NULL; 
    }
    int* arr = (int*)malloc(size * sizeof(int));
    if (arr == NULL) {
        return NULL; 
    }
    for (int i = 0; i < size; i++) {
        arr[i] = i + 1; 
    }
    return arr;
}

int main() {
    int size = 5;
    int* my_array = create_dynamic_array(size);
    if (my_array != NULL) {
        for (int i = 0; i < size; i++) {
            printf("%d ", my_array[i]);
        }
        printf("\n");
        free(my_array);
        my_array = NULL; 
    }
    return 0;
}

#CProgramming #Pointers #DynamicMemory

Pointer to Pointer (Double Pointer)
#include <stdio.h>
#include <stdlib.h>

int main() {
    int x = 10;
    int *ptr = &x;
    int **ptr_to_ptr = &ptr;

    printf("Value of x: %d\n", x);
    printf("Address of x: %p\n", &x);
    printf("Value of ptr: %p\n", ptr);
    printf("Value pointed to by ptr: %d\n", *ptr);
    printf("Address of ptr: %p\n", &ptr);
    printf("Value of ptr_to_ptr: %p\n", ptr_to_ptr);
    printf("Value pointed to by ptr_to_ptr: %p\n", *ptr_to_ptr);
    printf("Value pointed to by *ptr_to_ptr: %d\n", **ptr_to_ptr);
    printf("Address of ptr_to_ptr: %p\n", &ptr_to_ptr);

    // Example: Dynamically allocate an array of strings
    int num_strings = 3;
    char **string_array = (char **)malloc(num_strings * sizeof(char *));

    if (string_array == NULL) {
        perror("malloc failed");
        return 1;
    }

    string_array[0] = (char *)malloc(10 * sizeof(char));
    string_array[1] = (char *)malloc(15 * sizeof(char));
    string_array[2] = (char *)malloc(20 * sizeof(char));

    if (string_array[0] == NULL || string_array[1] == NULL || string_array[2] == NULL) {
        perror("malloc failed");
        // Free previously allocated memory to avoid memory leaks
        for(int i = 0; i < num_strings; ++i){
            if(string_array[i] != NULL){
                free(string_array[i]);
            }
        }
        free(string_array);
        return 1;
    }

    sprintf(string_array[0], "Hello");
    sprintf(string_array[1], "World!");
    sprintf(string_array[2], "Double Pointers");

    for (int i = 0; i < num_strings; i++) {
        printf("string_array[%d] = %s\n", i, string_array[i]);
    }

    // Free dynamically allocated memory
    for (int i = 0; i < num_strings; i++) {
        free(string_array[i]);
    }
    free(string_array);

    return 0;
}

#CProgramming #Arrays #Pointers

Array Traversal with Pointers
#include <stdio.h>

int main() {
    int arr[] = {10, 20, 30, 40, 50};
    int *ptr = arr;
    int size = sizeof(arr) / sizeof(arr[0]);

    printf("Array elements:\n");
    for (int i = 0; i < size; i++) {
        printf("Element %d: %d\n", i, *ptr);
        ptr++;
    }

    ptr = arr; 
    printf("Array elements (using pointer arithmetic):\n");
    for (int i = 0; i < size; i++) {
        printf("Element %d: %d\n", i, *(arr + i));
    }

    return 0;
}

#CProgramming #Pointers #SwapVariables

Swap Variables Using Pointers
#include <stdio.h>

void swap(int *x, int *y) {
    int temp = *x;
    *x = *y;
    *y = temp;
}

int main() {
    int a = 10;
    int b = 20;

    printf("Before swap: a = %d, b = %d\n", a, b);
    swap(&a, &b);
    printf("After swap: a = %d, b = %d\n", a, b);

    return 0;
}

#CProgramming #StringLength #Pointers

String Length using Pointer Arithmetic
#include <stdio.h>

int stringLength(const char *str) {
    const char *p = str;
    while (*p != '\0') {
        p++;
    }
    return p - str;
}

int main() {
    char str[] = "Hello, World!";
    int len = stringLength(str);
    printf("Length of the string: %d\n", len);
    return 0;
}