AI Coding & CSE Fundamentals
π Explore AI, Coding & Computer Science Fundamentals. π» Programming β’ DSA β’ DBMS β’ OS β’ Networks π€ AI & Emerging Technologies π οΈ Projects β’ Tutorials β’ Learning Resources π Your freedom to gain knowledge for free.
Show moreπ Analytical overview of Telegram channel AI Coding & CSE Fundamentals
Channel AI Coding & CSE Fundamentals (@aicoding_csefundamentals) in the English language segment is an active participant. Currently, the community unites 12 318 subscribers, ranking 10 235 in the Technologies & Applications category and 31 257 in the India region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 12 318 subscribers.
According to the latest data from 13 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -236 over the last 30 days and by -9 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 10.85%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 337 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 11.
- Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.
π Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
βπ Explore AI, Coding & Computer Science Fundamentals.
π» Programming β’ DSA β’ DBMS β’ OS β’ Networks
π€ AI & Emerging Technologies
π οΈ Projects β’ Tutorials β’ Learning Resources
π Your freedom to gain knowledge for free.β
Thanks to the high frequency of updates (latest data received on 14 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
#include <stdio.h>
int stringLength(const char *str) {
const char *p = str;
while (*p != '\0') {
p++;
}
return p - str;
}
int main() {
char str[] = "Hello, World!";
int len = stringLength(str);
printf("Length of the string: %d\n", len);
return 0;
}#include <stdio.h>
void reverseArray(int *arr, int size) {
int *start = arr;
int *end = arr + size - 1;
int temp;
while (start < end) {
temp = *start;
*start = *end;
*end = temp;
start++;
end--;
}
}
int main() {
int arr[] = {1, 2, 3, 4, 5};
int size = sizeof(arr) / sizeof(arr[0]);
reverseArray(arr, size);
printf("Reversed array: ");
for (int i = 0; i < size; i++) {
printf("%d ", arr[i]);
}
printf("\n");
return 0;
}#include <stdio.h>
int add(int x, int y) {
while (y != 0) {
int carry = x & y;
x = x ^ y;
y = carry << 1;
}
return x;
}
int main() {
int num1 = 5;
int num2 = 10;
int sum = add(num1, num2);
printf("Sum of %d and %d is %d\n", num1, num2, sum);
return 0;
}#include <stdio.h>
int main() {
int num = 7;
if (num & 1) {
printf("%d is odd.\n", num);
} else {
printf("%d is even.\n", num);
}
return 0;
}#include <stdio.h>
#include <stdint.h>
unsigned char setBits[256] = {
0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4,
1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5,
1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5,
2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5,
2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7,
1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5,
2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7,
2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7,
3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7,
4, 5, 5, 6, 5, 6, 6, 7, 5, 6, 6, 7, 6, 7, 7, 8
};
int countSetBits(int n) {
int count = 0;
count += setBits[n & 0xFF];
n >>= 8;
count += setBits[n & 0xFF];
n >>= 8;
count += setBits[n & 0xFF];
n >>= 8;
count += setBits[n & 0xFF];
return count;
}
int main() {
int num = 0b10110011101011001101010111100010;
printf("Number of set bits in %d is %d\n", num, countSetBits(num));
return 0;
}#include <stdio.h>
int isolateRightmostSetBit(int n) {
return n & -n;
}
int main() {
int num = 20; // Example number (binary 10100)
int isolatedBit = isolateRightmostSetBit(num);
printf("Original number: %d\n", num);
printf("Rightmost set bit: %d\n", isolatedBit);
return 0;
}#include <stdio.h>
int turnOffRightmostSetBit(int n) {
return n & (n - 1);
}
int main() {
int num = 12;
int result = turnOffRightmostSetBit(num);
printf("Original number: %d\n", num);
printf("Number with rightmost set bit turned off: %d\n", result);
return 0;
}#include <stdio.h>
int findRightmostSetBit(unsigned int n) {
if (n == 0) {
return 0;
}
int pos = 1;
while ((n & 1) == 0) {
n = n >> 1;
pos++;
}
return pos;
}
int main() {
unsigned int num = 12; // Example number (1100 in binary)
int position = findRightmostSetBit(num);
printf("Rightmost set bit is at position: %d\n", position);
return 0;
}#include <stdio.h>
int findRightmostSetBit(unsigned int n) {
if (n == 0)
return 0;
int pos = 1;
while ((n & 1) == 0) {
n = n >> 1;
pos++;
}
return pos;
}
int main() {
unsigned int num = 12; // Example: 1100 in binary
int position = findRightmostSetBit(num);
printf("Rightmost set bit is at position: %d\n", position);
return 0;
}#include <stdio.h>
#include <stdbool.h>
bool isOnlyOneBitSet(int n) {
if (n <= 0) {
return false;
}
return (n & (n - 1)) == 0;
}
int main() {
int num = 8;
if (isOnlyOneBitSet(num)) {
printf("%d has only one bit set.\n", num);
} else {
printf("%d does not have only one bit set.\n", num);
}
return 0;
}