AI Coding & CSE Fundamentals
🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.
显示更多📈 Telegram 频道 AI Coding & CSE Fundamentals 的分析概览
频道 AI Coding & CSE Fundamentals (@aicoding_csefundamentals) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 12 318 名订阅者,在 技术与应用 类别中位列第 10 235,并在 印度 地区排名第 31 257 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 12 318 名订阅者。
根据 13 十一月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -236,过去 24 小时变化为 -9,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 10.85%。内容发布后 24 小时内通常能获得 N/A% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 337 次浏览,首日通常累积 0 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 11。
- 主题关注点: 内容集中在 input, string, scanf("%d, array, element 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台:
“🚀 Explore AI, Coding & Computer Science Fundamentals.
💻 Programming • DSA • DBMS • OS • Networks
🤖 AI & Emerging Technologies
🛠️ Projects • Tutorials • Learning Resources
📚 Your freedom to gain knowledge for free.”
凭借高频更新(最新数据采集于 14 十一月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
#include <stdio.h>
int main() {
char name[50];
int age;
printf("Enter your name: ");
scanf("%s", name);
printf("Enter your age: ");
scanf("%d", &age);
printf("Hello, %s! You are %d years old.\n", name, age);
return 0;
}#include <stdio.h>
int main() {
printf("Hello, World!");
return 0;
}#include <stdio.h>int main() { int n = 10; int sum = (n * (n + 1)) / 2; printf("Sum of numbers from 1 to %d is: %d\n", n, sum); return 0;}#include <stdio.h>#include <stdbool.h>bool isPowerOfTwo(int n) { return (n > 0) && ((n & (n - 1)) == 0);}int main() { int num = 16; if (isPowerOfTwo(num)) { printf("%d is a power of 2\n", num); } else { printf("%d is not a power of 2\n", num); } return 0;}#include <stdio.h>
void increment(int *n) {
(*n)++;
}
int main() {
int num = 10;
printf("Before: %d\n", num);
increment(&num);
printf("After: %d\n", num);
return 0;
}#include <stdio.h>
#include <stdlib.h>
int* create_dynamic_array(int size) {
if (size <= 0) {
return NULL;
}
int* arr = (int*)malloc(size * sizeof(int));
if (arr == NULL) {
return NULL;
}
for (int i = 0; i < size; i++) {
arr[i] = i + 1;
}
return arr;
}
int main() {
int size = 5;
int* my_array = create_dynamic_array(size);
if (my_array != NULL) {
for (int i = 0; i < size; i++) {
printf("%d ", my_array[i]);
}
printf("\n");
free(my_array);
my_array = NULL;
}
return 0;
}#include <stdio.h>
#include <stdlib.h>
int main() {
int x = 10;
int *ptr = &x;
int **ptr_to_ptr = &ptr;
printf("Value of x: %d\n", x);
printf("Address of x: %p\n", &x);
printf("Value of ptr: %p\n", ptr);
printf("Value pointed to by ptr: %d\n", *ptr);
printf("Address of ptr: %p\n", &ptr);
printf("Value of ptr_to_ptr: %p\n", ptr_to_ptr);
printf("Value pointed to by ptr_to_ptr: %p\n", *ptr_to_ptr);
printf("Value pointed to by *ptr_to_ptr: %d\n", **ptr_to_ptr);
printf("Address of ptr_to_ptr: %p\n", &ptr_to_ptr);
// Example: Dynamically allocate an array of strings
int num_strings = 3;
char **string_array = (char **)malloc(num_strings * sizeof(char *));
if (string_array == NULL) {
perror("malloc failed");
return 1;
}
string_array[0] = (char *)malloc(10 * sizeof(char));
string_array[1] = (char *)malloc(15 * sizeof(char));
string_array[2] = (char *)malloc(20 * sizeof(char));
if (string_array[0] == NULL || string_array[1] == NULL || string_array[2] == NULL) {
perror("malloc failed");
// Free previously allocated memory to avoid memory leaks
for(int i = 0; i < num_strings; ++i){
if(string_array[i] != NULL){
free(string_array[i]);
}
}
free(string_array);
return 1;
}
sprintf(string_array[0], "Hello");
sprintf(string_array[1], "World!");
sprintf(string_array[2], "Double Pointers");
for (int i = 0; i < num_strings; i++) {
printf("string_array[%d] = %s\n", i, string_array[i]);
}
// Free dynamically allocated memory
for (int i = 0; i < num_strings; i++) {
free(string_array[i]);
}
free(string_array);
return 0;
}#include <stdio.h>
int main() {
int arr[] = {10, 20, 30, 40, 50};
int *ptr = arr;
int size = sizeof(arr) / sizeof(arr[0]);
printf("Array elements:\n");
for (int i = 0; i < size; i++) {
printf("Element %d: %d\n", i, *ptr);
ptr++;
}
ptr = arr;
printf("Array elements (using pointer arithmetic):\n");
for (int i = 0; i < size; i++) {
printf("Element %d: %d\n", i, *(arr + i));
}
return 0;
}#include <stdio.h>
void swap(int *x, int *y) {
int temp = *x;
*x = *y;
*y = temp;
}
int main() {
int a = 10;
int b = 20;
printf("Before swap: a = %d, b = %d\n", a, b);
swap(&a, &b);
printf("After swap: a = %d, b = %d\n", a, b);
return 0;
}